7.2.1Oscillations
Features of SHM — AP PHYSICS 1 Revision Notes & Topical Questions
5 min read 9 parts Lesson 5 of 10 1 quiz
Lesson summary
7.2.1 Features of SHM — AP PHYSICS 1 notes: Describe how displacement, velocity, acceleration and force vary in SHM and calculate maximum values and values at given positions.Setup — equilibrium at x = 0, amplitude A, oscillation between +A and −A, repeating every period T.At the…
- At the extremes
- At equilibrium
- Complementary
- amax = ω2A = kA/m
- x = A cosωt
- x = A sinωt
Part 1 of 7Positions in an oscillation
Setup
- Setup equilibrium at x = 0, amplitude A, oscillation between +A and −A, repeating every period T.
At the extremes
- At the extremes the object is momentarily at rest (v = 0) while the restoring force and acceleration have maximum magnitude toward equilibrium.
At equilibrium
- At equilibrium net force and acceleration are zero and speed is maximum.
Between
- Between speed rises approaching equilibrium and falls moving away.
Complementary
- Complementary where velocity is zero acceleration is maximum, and vice versa.
Part 2 of 7Maximum speed and acceleration
ω
√(k/m) = 2π/T for a spring.
vmax = ωA
- vmax = ωA at equilibrium.
amax
ω2A = kA/m
- at the amplitude.
Relation
- Relation amax = ωvmax.
Amplitude
- Amplitude doubling A doubles both maxima while the period stays the same.
Part 3 of 7Displacement as a function of time
Displacement as a function of time
x
A cosωt
- starting at x = +A when t = 0.
x
A sinωt
- starting at equilibrium moving in the positive direction.
Velocity
- Velocity v(t) = −ωA sinωt.
Acceleration
- Acceleration a(t) = −ω2A cosωt = −ω2x.
Starting condition
- Starting condition sets the choice of function; they repeat after T = 2π/ω.
Part 4 of 7Speed at any position
v
ω√(A2 − x2)
- from energy conservation; ωA at x = 0 and zero at x = ±A.
Time spent
- Time spent longer near the extremes where the object is slow.
Part 5 of 7Directions
Directions
Velocity
- Velocity changes sign at each turning point.
Acceleration
- Acceleration changes sign as the object crosses equilibrium.
Moving away from equilibrium
- Moving away from equilibrium v and a opposite, so it slows.
Moving toward equilibrium
- Moving toward equilibrium v and a same direction, so it speeds up.
Timing
- Timing extreme to equilibrium takes T/4; extreme to extreme takes T/2.
Part 6 of 7Using equations and ratios
1Two known quantities
- Two known quantities any two of A, T (or f or ω), vmax, amax give the others.
2From vmax and A
- ω = vmax/A, then T, f, amax and k = mω2.
3Frequency doubled, A same
- Frequency doubled, A same vmax doubles and amax quadruples.
4Amplitude doubled, f same
- Amplitude doubled, f same both double.
5Loudspeaker example
- 200 Hz and 0.50 mm give vmax = 0.63 m/s and amax about 790 m/s2, roughly 80g.
6Vibrating platform
- Vibrating platform an object leaves it if ω2A exceeds g.
Part 7 of 7More from the specification
1Periodic cycle in oscillating systems
- Periodic cycle in oscillating systems mechanical oscillators in a conservative oscillating system repeat position and velocity profiles throughout each complete sinusoidal cycle.
2Tangent
- Line touching a curve; its slope gives the instantaneous rate.
3Gradient
- Slope of a graph line.
Velocity
- Velocity the gradient of a displacement–time graph gives the velocity.
Acceleration
- Acceleration the gradient of a velocity–time graph gives the acceleration.
Turning points
- Turning points at maximum displacement the speed is zero and the acceleration is greatest.
Equilibrium
- Equilibrium at the centre the speed is greatest and the acceleration is zero.
Key terms
| Term | Meaning |
|---|---|
| Amplitude | Maximum displacement from equilibrium, A. |
| Angular frequency | ω = 2π/T = √(k/m) for a spring. |
| Maximum speed | vmax = ωA, reached at equilibrium. |
| Maximum acceleration | amax = ω2A, at the extremes. |
| Turning point | Position where the object momentarily stops and reverses. |
Avoid these mistakes
1
Saying acceleration is zero at the extremes — it is zero at equilibrium.
2
Saying velocity and acceleration are always in the same direction.
3
Using v = ωA at all positions rather than only at x = 0.
4
Forgetting that maximum speed depends on A.
5
Confusing amplitude with the peak-to-peak distance.
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