3.3.2Exchange and Transport
Enzymes in Digestion — AQA A Level Biology 7402 Revision Notes & Topical Questions
5 min read 9 parts Lesson 22 of 48 1 quiz
3.3.2 Enzymes in Digestion — AQA A Level Biology 7402 notes: Explain how the structure, specificity and optimum conditions of digestive enzymes link to where they act in the gut.Enzymes are globular proteins that lower the activation energy of a reaction.The substrate binds to th…
- active site
- induced-fit model
- Temperature
- Substrate concentration
- Enzyme concentration
- competitive inhibitor
Part 1 of 6Enzymes as biological catalysts
Enzymes are globular proteins that lower the activation energy of a reaction.
Part 2 of 6Digestive enzymes and their sites of action
| Enzyme | Source | Substrate | Products | Optimum pH |
|---|---|---|---|---|
| Salivary amylase | Salivary glands | Starch | Maltose | About 7 |
| Pepsin | Stomach | Proteins | Shorter polypeptides | 1–2 |
| Pancreatic amylase | Pancreas | Starch | Maltose | About 7–8 |
| Trypsin | Pancreas | Proteins | Polypeptides | About 8 |
| Lipase | Pancreas | Triglycerides | Monoglycerides, fatty acids | About 7–8 |
| Maltase, sucrase, lactase | Epithelium of ileum | Disaccharides | Monosaccharides | About 7–8 |
Notice that each enzyme works best in the pH of the region of the gut in which it is released. Pepsin's low optimum matches the acid in the stomach, whereas pancreatic enzymes work in the slightly alkaline conditions made by hydrogencarbonate in pancreatic juice and bile.
Part 3 of 6Inhibitors
A competitive inhibitor has a shape similar to the substrate and binds to the active site, blocking it.
Part 4 of 6Calculating rates and linking to practical work
The rate of an enzyme-controlled reaction is calculated as change in product (or substrate) ÷ time, or from the gradient of a tangent to the curve at a given time.
Enzymes are also used in industry
- lactase is used to make lactose-free milk, and proteases are used in biological washing powders.
- Immobilising enzymes on beads or in alginate allows reuse and easier separation of the product.
Part 5 of 6Worked interpretation of a rate graph
Imagine a graph of rate of product formation (mg min−1) against pH for pepsin and trypsin. The pepsin curve peaks at pH 2 and falls to almost zero by pH 5; the trypsin curve peaks near pH 8 and is almost zero at pH 4. To explain such a curve, state the optimum, say that on either side of it the rate is lower because changes in H+ concentration alter the ionisation of R groups in the active site and break ionic and hydrogen bonds, and conclude that each enzyme is adapted to its site of action.
For a substrate-concentration graph, state that the initial part is a straight line, because substrate is the limiting factor and every substrate molecule finds an active site. The plateau shows that the enzyme concentration, not the substrate, is limiting. If the question asks how to raise the plateau, answer: add more enzyme.
The Michaelis constant, Km, is the substrate concentration at half the maximum rate and shows the affinity of an enzyme for its substrate; a low value means high affinity. This extra detail is not required, but it shows how enzyme kinetics is analysed.
Part 6 of 6Exam-style questions
Explain why pepsin works well in the stomach but not in the small intestine. [3]3 marks
The stomach contains hydrochloric acid giving a pH of about 2, which is the optimum for pepsin (1).
Exam-style questionsIn the small intestine, the pH is about 7–8 as a result of hydrogencarbonate from bile and pancreatic juice (1).This changes the ionic and hydrogen bonds in pepsin, altering the shape of the active site, so it is denatured and cannot bind to the substrate (1).A competitive inhibitor is added to a digestion reaction. Explain how increasing substrate concentration affects its action. [2]2 marks
The inhibitor competes with the substrate for the active site (1). More substrate means substrate molecules are more likely to bind, so the effect of the inhibitor is reduced and the rate rises (1).
In an investigation, 6.0 g of product forms in the first 3 minutes. Calculate the mean rate. [2]2 marks
Rate = change ÷ time (1) = 6.0 ÷ 3 = 2.0 g min−1 (1).
Key terms
| Term | Meaning |
|---|---|
| Active site | Region of an enzyme where the substrate binds. |
| Induced-fit model | Model in which the active site changes shape to fit the substrate. |
| Denaturation | Permanent change in tertiary structure of a protein. |
| Competitive inhibitor | Molecule that binds to the active site and blocks the substrate. |
| Non-competitive inhibitor | Molecule that binds elsewhere and changes the active site shape. |
| Zymogen | Inactive precursor of an enzyme, such as pepsinogen. |
| Activation energy | Energy needed to start a reaction. |
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