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1.1.4Atomic Structure and the Periodic Table

Half Equations and Ionic Equations

5 min read 8 parts Lesson 5 of 19 1 quiz

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Section 1 of 8Half equations

What they show
  • What they show A half equation shows what happens to one species, with electrons written as e−.
  • Two half equations can be added together, with the electrons cancelling, to give the full ionic equation for a redox reaction.
Losing electrons
  • Losing electrons Metal atoms form positive ions: Na → Na+ + e−. Electrons appear on the product side.
Gaining electrons
  • Gaining electrons Non-metal atoms form negative ions: Cl2 + 2e− → 2Cl−.
    • Electrons appear on the reactant side.
Balanced twice
  • Balanced twice The number of atoms and the total charge must be equal on both sides.

Section 2 of 8Writing a half equation

1
Write the species before and after the change, such as Mg and Mg2+.
2
Balance the atoms, adding a coefficient where needed, as in Cl2 → 2Cl−.
3
Work out the total charge on each side.
4
Add electrons to the side with the more positive charge so that the charges match.
5
Check that atoms and charge balance: Mg → Mg2+ + 2e− is neutral on the left and 2+ plus 2− on the right.

Section 3 of 8Writing an ionic equation

1
Write the balanced symbol equation with state symbols.
2
Split every aqueous ionic compound into its ions. Leave solids, liquids and gases whole.
3
Cross out the ions that appear unchanged on both sides, the spectator ions.
4
Write what is left as the ionic equation.
5
Check that atoms and charges balance.

Section 4 of 8Worked example: silver nitrate and sodium chloride

StageEquation
Full equationAgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)
Split into ionsAg+ + NO3− + Na+ + Cl− → AgCl(s) + Na+ + NO3−
Remove spectatorsNa+ and NO3−
Ionic equationAg+(aq) + Cl−(aq) → AgCl(s)

Section 5 of 8More ionic equations

ReactionIonic equationObservation
NeutralisationH+(aq) + OH−(aq) → H2O(l)Solution becomes neutral
Barium sulfate precipitateBa2+(aq) + SO42−(aq) → BaSO4(s)White precipitate forms
Copper hydroxide precipitateCu2+(aq) + 2OH−(aq) → Cu(OH)2(s)Blue precipitate forms

Section 6 of 8Electrolysis half equations

Electrodes
Cathode
  • Cathode Reduction: Cu2+ + 2e− → Cu, or 2H+ + 2e− → H2.
  • Positive ions are attracted to the negative cathode, where they gain electrons.
Anode
  • Anode Oxidation: 2Cl− → Cl2 + 2e−, or 4OH− → O2 + 2H2O + 4e−.
  • Negative ions are attracted to the positive anode, where they lose electrons.
Electron balance
  • Electron balance The electrons gained at the cathode equal those lost at the anode, which is why the overall equation has no electrons in it.

Section 7 of 8Key terms

TermMeaning
Half equationAn equation showing the loss or gain of electrons by one species.
Ionic equationAn equation showing only the ions or particles that take part in a reaction.
Spectator ionAn ion that is present but unchanged during the reaction.
PrecipitateAn insoluble solid formed in a reaction between solutions.
ElectronA negatively charged particle, written e−.
AqueousDissolved in water, shown by the state symbol (aq).

Section 8 of 8Exam technique

1
Splitting a solid or gas into ions.
2
Not balancing the charge, only the atoms.
3
Putting electrons on the wrong sideelectrons are lost on the product side for positive ions.
4
Leaving spectator ions in the final ionic equation.
5
Forgetting that diatomic elements like Cl2 take 2 electrons.
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