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7.2.3Organic Chemistry

Addition Reactions of Alkenes

5 min read 5 parts Lesson 8 of 15 Unit quiz

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Section 1 of 5Features of Addition

In an addition reaction, a small molecule joins across the carbon double bond, so the product has no double bond left.

Alkene
  • Alkene An unsaturated hydrocarbon with a carbon-carbon double bond and the general formula CₙH₂ₙ.
Addition
  • Addition A reaction in which two substances join together to form one product, with no other products formed.
Saturated product
  • Saturated product The product contains only single bonds, because the double bond has been converted to single bonds.
Decolourising
  • Decolourising Alkenes turn orange bromine water colourless, which is a test for the presence of a C=C double bond.

Section 2 of 5Reagents and Products

Each reagent needs different conditions, and the product type changes with the reagent used.

Reagents and Products
Bromine
  • Bromine Adds across the double bond at room temperature, giving a dibromoalkane with two bromine atoms.
Hydrogen
  • Hydrogen Adds with a nickel catalyst at about 150 °C, producing an alkane from the alkene.
Steam
  • Steam Adds with a phosphoric acid catalyst at high temperature and pressure, producing an alcohol.
ReagentConditionsProductEquation
Bromine water (Br₂)Room temperature1,2-dibromoethaneC₂H₄(g) + Br₂(aq) → C₂H₄Br₂(l)
Hydrogen (H₂)Nickel catalyst, about 150 °CEthaneC₂H₄(g) + H₂(g) → C₂H₆(g)
Steam (H₂O)Phosphoric acid catalyst, about 300 °C, 60 to 70 atmEthanolC₂H₄(g) + H₂O(g) → C₂H₅OH(g)

Section 3 of 5Testing for a Double Bond

The bromine water test is a quick way to tell an alkene from an alkane in a laboratory.

1
Place a few drops of the hydrocarbon in a test tube and add orange bromine water.
2
Shake the tube gently and observe whether the orange colour disappears.
3
An alkene decolourises the bromine water, turning it colourless, because addition takes place.
4
An alkane does not react with bromine water at room temperature, so the orange colour remains.

Section 4 of 5Worked Example

Question

  • Calculate the mass of 1,2-dibromoethane formed when 14 g of ethene reacts completely with bromine.
  • (Relative atomic masses: H = 1, C = 12, Br = 80.)

  1. Relative formula mass of C₂H₄ = (2 × 12) + (4 × 1) = 28.
  2. Moles of ethene = 14 ÷ 28 = 0.5 mol.
  3. Mole ratio C₂H₄C₂H₄Br₂ is 1 : 1, so 0.5 mol of product forms.
  4. Relative formula mass of C₂H₄Br₂ = 24 + 4 + 160 = 188, so mass = 0.5 × 188 = 94 g.

Answer 94 g of 1,2-dibromoethane.

Section 5 of 5Exam Checklist & Tips

7.2.3 – Key Points for the Exam

  • Addition reaction A reaction in which atoms or molecules join across a double bond, with no other product.
  • Alkene An unsaturated hydrocarbon containing at least one carbon-carbon double bond.
  • Saturated A compound containing only single bonds between carbon atoms.
  • Hydration Addition of water across a double bond, here forming an alcohol with a phosphoric acid catalyst.
  • Decolourise To remove colour, as alkenes do to orange bromine water.

Common Mistakes

  • Describing addition as atoms being replaced;
    • in addition, atoms join onto the double bond without any being removed.
  • Stating that alkanes decolourise bromine water; only unsaturated alkenes do this.
  • Forgetting the catalyst and conditions when a question asks for them for hydrogenation or hydration.
  • Miscounting the hydrogen atoms in the product, so the formula of the product is written incorrectly.
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