2.1.3Electricity
Current, Resistance and Potential Difference
5 min read 9 parts Lesson 4 of 27 1 quiz
Section 1 of 9Three key quantities
| Quantity | Meaning | Unit |
|---|---|---|
| Current, I | Rate of flow of electric charge: how many electrons pass a point each second | ampere (A) |
| Potential difference, V | Energy transferred per unit of charge between two points; the push that drives the current | volt (V) |
| Resistance, R | Opposition to current, caused by electrons colliding with the lattice of metal ions | ohm (Ω); 1 Ω = 1 V/A |
Section 2 of 9Why wires resist
1Electrons flow
- Electrons flow A potential difference makes free electrons drift through the metal.
2Collisions
- Collisions They collide with the vibrating positive ions in the lattice.
3Energy transferred
- Energy transferred The ions vibrate more, so the wire's thermal store increases and the wire warms.
4Current limited
- Current limited The more resistance, the lower the current for a given potential difference.
Section 3 of 9Using V = I × R
1
List what is known, e.g. current 0.50 A and resistance 12 Ω.
2
Write the equation: potential difference (V) = current (A) × resistance (Ω).
3
Substitute: V = 0.50 × 12 = 6.0 V.
4
To find current use I = V ÷ R, and to find resistance use R = V ÷ I; check the unit matches the quantity.
Section 4 of 9Worked examples
| Question | Working | Answer |
|---|---|---|
| A 4.0 Ω resistor carries 3.0 A. Find the potential difference. | V = I × R = 3.0 × 4.0 | 12 V |
| A lamp has 6.0 V across it and a resistance of 20 Ω. Find the current. | I = V ÷ R = 6.0 ÷ 20 | 0.30 A |
| A component has 9.0 V across it and carries 0.15 A. Find the resistance. | R = V ÷ I = 9.0 ÷ 0.15 | 60 Ω |
| A current of 250 mA flows through a 48 Ω resistor. Find the potential difference. | Convert 250 mA = 0.25 A; V = 0.25 × 48 | 12 V |
Section 5 of 9Relationships
V = I × R
Higher resistance
- Higher resistance With the same potential difference the current is smaller.
Lower resistance
- Lower resistance The current is larger for the same potential difference.
Conductors and insulators
- Conductors and insulators Good conductors have low resistance; insulators have very high resistance.
Exam assumption
- Exam assumption Unless told otherwise, the resistance of connecting wires and cells is treated as negligible.
Section 6 of 9Measuring the quantities in a circuit
Ammeter
- Ammeter Measures current and is connected in series with the component, so that all of the current flows through it.
- It has very low resistance.
Voltmeter
- Voltmeter Measures potential difference and is connected in parallel across the component.
- It has very high resistance so that hardly any current flows through it.
Finding resistance
- Finding resistance Record the voltmeter and ammeter readings together and then calculate R = V ÷ I.
- Repeating at several settings and averaging improves reliability.
Section 7 of 9Charge, current and time
1Charge flows
- Charge flows Charge is measured in coulombs (C); a current of 1 A means 1 C passes a point each second.
2Equation
- Equation Q = I × t, where charge Q is in coulombs, current I in amperes and time t in seconds.
3Example
- Example A current of 2.0 A flowing for 30 s transfers Q = 2.0 × 30 = 60 C of charge.
Section 8 of 9Key terms
| Term | Meaning |
|---|---|
| Current | The rate of flow of electrical charge, measured in amperes. |
| Potential difference | The energy transferred per unit charge between two points, measured in volts; also called voltage. |
| Resistance | A measure of how much a component opposes the flow of current, in ohms. |
| Ohm | The unit of resistance; one volt per ampere. |
| Lattice | The regular arrangement of positive ions in a metal. |
| Ammeter | A meter placed in series that measures the current in a circuit. |
Section 9 of 9Exam technique
1
Saying that current is 'used up' in a component. Charge keeps flowing; energy is transferred.
2
Mixing up potential difference (across a component) with current (through it).
3
Forgetting units, or giving resistance in volts or amps.
4
Thinking higher resistance means higher current. It means lower current.
5
Forgetting to convert milliamps to amps before using V = I × R.