Section 1 of 10Momentum
Momentum
- Momentum the product of an object's mass and its velocity, p = mv.
- The unit is kg m/s, or equivalently N s.
Vector quantity
- Vector quantity momentum has the same direction as the velocity.
- Choose one direction as positive, such as right, and write leftward momentum as negative.
Dependence
- Dependence a heavy slow object can have the same momentum as a light fast object.
- A 1000 kg car at 2 m/s has the same momentum (2000 kg m/s) as a 2 kg object at 1000 m/s.
- Momentum depends on both mass and velocity, so a slow lorry can be harder to stop than a fast cyclist.
Change in momentum
- Δp = mv − mu, the final minus the initial momentum.
Section 2 of 10Force and impulse
Force and impulse
Force as rate of change of momentum
- Force as rate of change of momentum the resultant force equals the change in momentum per unit time, F = Δp ÷ Δt.
- This is Newton's second law in its original form and gives F = ma when the mass is constant.
Impulse
- Impulse the change of momentum, which equals force multiplied by the time for which it acts, impulse = FΔt.
- The unit is N s, the same as kg m/s.
Making the time longer
- Making the time longer the same change in momentum with a longer time means a smaller force.
- A cricketer pulls the hands back when catching a ball, and crumple zones and airbags in cars do the same.
Making the time shorter
- Making the time shorter a shorter contact time gives a larger force, as when a hammer hits a nail.
Calculation route
- Calculation route find Δp from masses and velocities, then divide by the time to get the force.
Section 3 of 10Conservation of momentum
Conservation of momentum
Principle
- Principle in a closed system with no external resultant force, the total momentum before an interaction equals the total momentum after it.
Collision and explosion
- Collision and explosion the principle works for both, although kinetic energy is treated differently.
Method for collision problems
- Method for collision problems follow the steps in order.
1
Choose a positive direction and draw a before and after diagram.
2
Write the masses and velocities, with signs for direction.
3
Calculate the total momentum before.
4
Set the total momentum after equal to this and solve for the unknown.
5
Check the direction of your answer from its sign.
- Equation form
- m1u1 + m2u2 = m1v1 + m2v2.
- For objects that stick together the final velocity is common, so (m1 + m2)v on the right-hand side.
Section 4 of 10Types of collision
Types of collision
Elastic collision
- Elastic collision both momentum and kinetic energy are conserved, and the objects bounce apart.
Inelastic collision
- Inelastic collision momentum is conserved but some kinetic energy changes into heat, sound and deformation.
| Property | Elastic | Inelastic |
|---|---|---|
| Momentum | Conserved | Conserved |
| Kinetic energy | Conserved | Not conserved |
| Typical example | Two hard steel balls | Car crash, clay lumps sticking |
| After collision | Separate | Often join together |
Types of collision
Explosions
- Explosions objects start at rest with zero total momentum and fly apart with momenta that cancel.
- A gun recoils backward as the bullet moves forward, and the recoil speed is smaller because the gun has more mass.
Newton's third law link
- Newton's third law link in a collision the forces on the two objects are equal and opposite for the same time,
- so the changes in momentum are equal and opposite.
Section 5 of 10Linking momentum with kinetic energy and safety
Linking momentum with kinetic energy and safety
Kinetic energy comparison
- KE = ½mv2 depends on velocity squared, so doubling speed quadruples energy.
Check for elastic collisions
- Check for elastic collisions calculate the total KE before and after; if equal, the collision is elastic.
Safety applications
- Safety applications car safety features lengthen the time of a collision and so reduce the force on passengers.
- Seat belts stretch slightly, crumple zones deform and airbags cushion the head.
Rockets and jets
- Rockets and jets they work by throwing mass backward at high speed so that the vehicle gains forward momentum.
- The rocket and gas have equal and opposite momentum changes.
Sports
- Sports following through with a bat or racket increases the contact time and imparts more momentum.
Section 6 of 10Worked strategy for collisions in a line
Worked strategy for collisions in a line
Two objects moving towards each other
- Two objects moving towards each other give one a positive velocity and the other a negative velocity.
- A 3 kg trolley at +4 m/s and a 1 kg trolley at −2 m/s have a total momentum of 12 − 2 = +10 kg m/s.
Two objects that bounce apart
- Two objects that bounce apart use momentum conservation for one equation, and the elastic condition, if stated, for the second.
- If kinetic energy is conserved, the relative speed of approach equals the relative speed of separation.
Objects that join
- Objects that join they move together afterwards, so only one unknown velocity remains.
Direction of the answer
- Direction of the answer a positive result means the same direction as the chosen positive direction, a negative result means the opposite direction.
Checking results
- Checking results total momentum after should equal total momentum before, and no object should gain energy from nowhere.
- In an inelastic collision the total kinetic energy after must be less than before.
Energy lost
- Energy lost find KE before minus KE after to see how much changed into thermal and sound energy.
- For the 2.0 kg and 1.0 kg trolleys in the worked example the energy lost is 9.0 − 6.0 = 3.0 J.
Section 7 of 10Momentum in everyday and exam contexts
Momentum in everyday and exam contexts
Stopping distance link
- Stopping distance link a vehicle with large momentum needs a larger impulse to stop, so it needs a longer time or a greater braking force.
- Heavier lorries have longer braking distances than cars moving at the same speed.
Jet and rocket propulsion
- Jet and rocket propulsion hot gas is expelled backward, which gives the rocket forward momentum so that the total remains zero.
Water hose
- Water hose a firefighter feels a backward force because the water leaves with a large momentum each second.
Typical exam wording
- "stationary" means zero initial velocity, "joined together" means a common final velocity,
- and "rebounds" means the velocity reverses direction.
Units check
- Units check a momentum answer should be in kg m/s and an impulse answer in N s, which are the same thing.
- Writing both helps recognise that impulse equals the change in momentum.
Section 8 of 10Worked examples
Calculate the momentum of a 1200 kg car travelling at 15 m/s, and of a 60 kg cyclist moving at 8 m/s. [2]2 marks
Worked examplesCar: p = 1200 × 15 = 18 000 kg m/s.Cyclist: p = 60 × 8 = 480 kg m/s.A 0.50 kg ball moving at 6.0 m/s is hit by a bat and returns at 10 m/s in the opposite direction. The contact lasts 0.020 s. Find the average force. [4]4 marks
1Take the initial direction as positive, so u = +6.0 and v = −10 m/s.2Δp = 0.50 × (−10) − 0.50 × 6.0 = −5.0 − 3.0 = −8.0 kg m/s.3F = Δp ÷ Δt = −8.0 ÷ 0.020 = −400 N.4The force is 400 N in the direction the ball returns.A 2.0 kg trolley moving at 3.0 m/s collides with a stationary 1.0 kg trolley and they stick together. Find their common velocity. [3]3 marks
Worked examplesMomentum before = 2.0 × 3.0 + 1.0 × 0 = 6.0 kg m/s.After: (2.0 + 1.0) × v = 6.0.v = 2.0 m/s in the original direction.A 0.020 kg bullet is fired at 300 m/s from a 4.0 kg rifle initially at rest. Find the recoil speed. [3]3 marks
Worked examplesTotal momentum before = 0.Bullet momentum = 0.020 × 300 = 6.0 kg m/s forward, so the rifle has 6.0 kg m/s backward.v = 6.0 ÷ 4.0 = 1.5 m/s backward.Explain why an airbag reduces injury in a crash. [3]3 marks
Worked examplesThe passenger's momentum must change to zero in either case.The airbag increases the time taken to stop.Since F = Δp ÷ Δt, a longer time gives a smaller force on the passenger.
Section 9 of 10Key terms
| Term | Meaning |
|---|---|
| Momentum | The product of mass and velocity, p = mv, in kg m/s. |
| Impulse | The change in momentum, equal to force multiplied by time, in N s. |
| Conservation of momentum | The total momentum of a closed system is constant. |
| Elastic collision | A collision in which kinetic energy is conserved. |
| Inelastic collision | A collision in which kinetic energy is not conserved. |
| Recoil | The backward motion of a gun or launcher when a projectile is fired. |
Section 10 of 10Exam technique
1
Ignoring direction — momentum is a vector, so give opposite directions opposite signs.
2
Saying kinetic energy is always conserved in a collision — only elastic collisions conserve it.
3
Using grams in p = mv — convert mass to kg so the unit is kg m/s.
4
Mixing up impulse and momentum — impulse equals the change in momentum, not the momentum itself.
5
Applying conservation when an external force acts — it holds only for a closed system.