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22.4.3Quantum and nuclear physics (A Level)

Calculating Discrete Energies

5 min read 8 parts Lesson 13 of 23 1 quiz

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Lesson summary

22.4.3 Calculating Discrete Energies — AS PHYSICS 9702 notes: Calculate photon energies, frequencies and wavelengths for transitions between atomic energy levels.Photon energy — ΔE = E2 − E1 = hf = hc/λ.E1 is the lower level and E2 is the higher level.Wavelength — λ = hc/(E2 − E1…

  • Dependence
  • Useful values
  • Reverse conversion
  • Sense check
  • Three levels
  • Shortest wavelength

Section 1 of 8The key equation

Photon energy
  • ΔE = E2 − E1 = hf = hc/λ.
  • E1 is the lower level and E2 is the higher level.
Wavelength
  • λ = hc/(E2 − E1).
Dependence
  • A larger energy difference gives a shorter wavelength, and a smaller difference gives a longer wavelength.
Useful values
  • Useful values hc = 1.99 × 10−25 J m, or 1240 eV nm, so λ (nm) = 1240 / E (eV).

Section 2 of 8Working with units

1
Take the difference between the two levels in eV.
2
Multiply by 1.60 × 10−19 to get joules.
3
Use f = E/h or λ = hc/E.
4
Convert the wavelength to nm if sensible by dividing by 10−9.
Reverse conversion
  • Use E = hc/λ in joules and divide by 1.60 × 10−19 to get eV.
Sense check
  • Visible photons have energies between about 1.7 eV (red) and 3.3 eV (violet).

Section 3 of 8Multiple transitions

Three levels
  • Levels 1 (ground), 2 and 3 allow downward transitions 3 → 2, 3 → 1 and 2 → 1, giving three lines.
Shortest wavelength
  • The largest gap, 3 → 1, gives the shortest wavelength.
Energies add
  • E31 = E32 + E21, and the frequencies add in the same way.
Wavelengths do not add
  • Do not add wavelengths of two transitions to get the combined transition.
Number of lines
  • For N levels the maximum number of emission lines is N(N − 1)/2.
  • Not all may be seen in a given experiment, so this is an upper limit.

Section 4 of 8Excitation by electron collision

Excitation by electron collision
Electron energy
  • An electron accelerated through a p.d.
  • V has kinetic energy eV.
Condition
  • It can excite an atom only if eV is at least as large as the energy gap.
Partial transfer
  • The electron need not give all its energy and keeps the remainder.
Photon difference
  • A photon must be fully absorbed with an exact match, but a colliding electron can keep the excess.
Minimum voltage
  • The minimum accelerating voltage for the first excitation is the gap in eV divided by e, numerically the gap in volts.

Section 5 of 8Finding an unknown level

1
Find the photon energy from the measured wavelength using E = hc/λ.
2
Decide from the context whether the transition is emission (down) or absorption (up).
3
For emission from an unknown upper level, add the photon energy to the lower level.
4
For emission to an unknown lower level, subtract the photon energy from the upper level.
5
Check that the new level lies below zero for a bound state.
Diagram aid
  • A quick energy level sketch shows the direction and prevents sign mistakes.
Ratios
  • If photon A has twice the frequency of photon B, it has twice the energy and half the wavelength.

Section 6 of 8More from the specification

Discrete atomic energy levels
  • In isolated atoms, electrons can only occupy certain quantised energy levels,
    • (such as hydrogen)
  • meaning electron transitions between these levels result in the emission or absorption of photons with discrete energies.
Photon emission equation
  • When an excited electron transitions from a higher energy level E2 to a lower energy level E1, the energy change corresponds to the energy of the emitted photon: delta_E = E2 - E1 = h f = h c / lambda.
Line emission spectra
  • An emission spectrum consists of sharp, coloured lines of light on a dark background,
  • where each spectral line corresponds to a specific electronic transition and wavelength characteristic of the element.
Hydrogen line spectrum series
  • For hydrogen atoms, transitions ending at n=1 produce the ultraviolet Lyman series,
  • while transitions to n=2 produce visible light lines in the Balmer series of the hydrogen spectrum.
Spectrum
  • Range of colours in white light.
Series
  • Components in one loop, sharing the e.m.f. between them.

Section 7 of 8Key terms

TermMeaning
Energy difference (ΔE)The difference between two energy levels, equal to the energy of the photon emitted or absorbed.
Photon energy relationΔE = E2 − E1 = hf = hc/λ.
Excitation energyThe energy needed to raise an electron from one level to a higher level.
Planck constant6.63 × 10−34 J s, relating photon energy to frequency.
ElectronvoltA unit of energy equal to 1.60 × 10−19 J.

Section 8 of 8Exam technique

1
Not converting eV to joules before using h in J s — multiply by 1.60 × 10−19 first.
2
Adding wavelengths of two transitions — add the energies or frequencies, not the wavelengths.
3
Using the energies themselves rather than their difference in E = hf — use E2 − E1.
4
Giving a wavelength with the wrong power of ten — visible light is about 4 × 10−7 to 7 × 10−7 m.
5
Assuming an electron must lose all its energy to excite an atom — a photon must be absorbed fully but a colliding electron keeps the remainder.
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