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3.2Work, energy, power and deformation

Deformation OF Solids

5 min read 10 parts Lesson 3 of 17 1 quiz Virtual lab

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Lesson summary

3.2 Deformation of Solids — AS PHYSICS 9702 notes: Describe tensile and compressive deformation, state Hooke’s law, define stress, strain and the Young modulus, and distinguish elastic from plastic behaviour.Deformation — forces change the size or shape of a body.Tensile forces —…

  • Compressive forces
  • What the symbols mean
  • Spring constant
  • Springs in series
  • Springs in parallel
  • Limit of proportionality

Section 1 of 10Tensile and compressive forces

Deformation
  • Deformation forces change the size or shape of a body.
Tensile forces
  • Tensile forces a pair of equal and opposite forces that stretch a body and cause extension.
Compressive forces
  • Compressive forces a pair of equal and opposite forces that squash a body and cause compression.
Extension
  • Extension x = L − L0, the extended length minus the natural length, in metres.

Section 2 of 10Hooke’s law and the spring constant

Hooke’s law
  • Hooke’s law the extension of a body is directly proportional to the applied force, provided the limit of proportionality is not exceeded.
  • F = kx, with F in N, k in N m−1 and x in m.
    What the symbols mean: F = force (N) · k = spring constant (N m−1) · x or e = extension (m)
Spring constant
  • Spring constant k = F/x, the force per unit extension and a measure of stiffness.
  • It equals the gradient of the linear part of a force–extension graph.
Springs in series
  • 1/k = 1/k1 + 1/k2.
Springs in parallel
  • Springs in parallel k = k1 + k2.

Section 3 of 10Stress, strain and the Young modulus

Stress
  • σ = F/A, force per unit cross-sectional area, in Pa.
    What the symbols mean: σ = stress (Pa) · F = tensile force (N) · A = cross-sectional area (m2)
Strain
  • ε = x/L, extension per unit original length, with no unit.
Young modulus
  • E = σ/ε = FL/(Ax), in Pa.
    What the symbols mean: E = Young modulus (Pa) · σ = stress (Pa) · ε = strain · F = force (N) · L = original length (m) · A = cross-sectional area (m2) · ΔL = extension (m)
  • It is a property of the material, not of the sample.
  • A stiffer material has a larger Young modulus; steel is about 2 × 1011 Pa.
Wire area
  • A = πd2/4 = πr2.
Graph
  • Graph the gradient of the linear part of a stress–strain graph is the Young modulus.

Section 4 of 10Elastic and plastic behaviour

FeatureElasticPlastic
Return to original length on unloadingYesNo — permanent extension remains
Region of graphUp to the elastic limitBeyond the elastic limit
Energy on unloadingStored energy is recoveredSome work done is dissipated as thermal energy
Atomic viewBonds stretch and atoms returnLayers of atoms slide past each other
Limit of proportionality
  • Limit of proportionality the point beyond which force is no longer proportional to extension.
Elastic limit
  • Elastic limit the maximum force beyond which the material will not return to its original length;
    • it is slightly beyond the limit of proportionality.

Section 5 of 10Brittle, ductile and rubber

Brittle
  • Brittle glass and ceramics break with little or no plastic deformation, at the end of the elastic region.
Ductile
  • Ductile copper has a large plastic region and stretches before breaking.
Ultimate tensile stress
  • Ultimate tensile stress the maximum stress a material can withstand before it breaks.
Rubber
  • Rubber a non-linear material with hysteresis, where loading and unloading curves differ.
  • The area between the curves is energy dissipated as heat per cycle.

Section 6 of 10Elastic potential energy

Work done
  • Work done the area under a force–extension graph is the work done in stretching.
Hooke’s law region
  • Ep = ½Fx = ½kx2, the area of a triangle.
Non-linear graph
  • Non-linear graph count squares, with energy per square = force per square × extension per square.
Energy density
  • Energy density the area under a stress–strain graph is the strain energy per unit volume, in J m−3.
Beyond the elastic limit
  • Beyond the elastic limit the unloading line is roughly parallel to the loading line, so only the area under the unloading line is recovered.

Section 7 of 10Experiment to find the Young modulus of a wire

1
Clamp a long, thin wire at one end and pass it over a pulley to a mass hanger, with a marker on the wire against a scale.
2
Measure the original length L with a metre rule.
3
Measure the diameter with a micrometer at several points and orientations, then take the mean and calculate A = πd2/4.
4
Add masses in equal steps and record the extension for each load F = mg.
5
Record readings while unloading to check the elastic limit was not exceeded.
6
Plot force against extension and find the gradient of the linear region.
7
Calculate E = gradient × L/A.
  • Precautions
    • a long wire gives a larger extension, and the diameter has the largest percentage uncertainty because it is squared.

Section 8 of 10More from the specification

1Hooke's law
  • Hooke's law extension is proportional to force up to the limit of proportionality, and a force-extension graph is straight in that region
2Young modulus
  • Young modulus stress divided by strain, a property of the material independent of the object's shape
3Stress and strain
  • Stress and strain stress is force per unit cross-sectional area and strain is extension divided by original length
4Stress-strain graph
  • Stress-strain graph the gradient gives the Young modulus and the area under it gives energy stored per unit volume;
    • for a metal wire measure diameter and length and the extension for several loads to determine it
5Hooke's law
  • Hooke's law extension is proportional to force up to the limit of proportionality, and a force-extension graph is straight in that region
6Young modulus
  • Young modulus stress divided by strain, a property of the material independent of the object's shape
7Stress and strain
  • Stress and strain stress is force per unit cross-sectional area and strain is extension divided by original length
8Stress-strain graph
  • Stress-strain graph the gradient gives the Young modulus and the area under it gives energy stored per unit volume;
    • for a metal wire measure diameter and length and the extension for several loads to determine it

Section 9 of 10Key terms

TermMeaning
Hooke’s lawExtension is directly proportional to force up to the limit of proportionality.
Spring constantForce per unit extension, k = F/x, in N m⁻¹.
StressForce per unit cross-sectional area, σ = F/A.
StrainExtension per unit original length, ε = x/L.
Young modulusRatio of stress to strain for a material, E = σ/ε.
Elastic limitMaximum force beyond which a material does not return to its original length.
Plastic deformationPermanent deformation after the load is removed.
Elastic potential energyEnergy stored in a deformed body, equal to the area under the force–extension graph.

Section 10 of 10Exam technique

1
Using the total length instead of the extension in F = kx — use x = L − L₀.
2
Confusing the elastic limit with the limit of proportionality — they are different points on the graph.
3
Thinking the Young modulus depends on the wire’s dimensions — it is a property of the material.
4
Using Ep = ½kx² for a non-linear graph — then the area must be found directly.
Try it in the virtual labHooke’s law \n