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Thermal physics (A Level)

16. Thermodynamics

5 min read 7 parts Lesson 20 of 20 Unit quiz

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16. Thermodynamics — Cambridge AS & A Level Physics 9702 — CAMBRIDGE AS & A LEVEL PHYSICS 9702 — COMPLETE NOTES notes: Define internal energy, calculate the work done by or on a gas, and apply the first law of thermodynamics with the correct sign convention.Internal energy U = th…

  • State dependence
  • Definition wording
  • Solids and liquids
  • Real gases
  • Proportionality
  • Kelvin only

Section 1 of 7What internal energy is

  • Internal energy U = the sum of the random distribution of kinetic and potential energies of the molecules in a system.
    • Kinetic energy comes from the random motion (speed) of the molecules.
    • Potential energy comes from the intermolecular forces and changes with their separation.
  • State dependence
    • for a fixed mass at its melting or boiling point, the liquid has more internal energy than the solid and the gas more than the liquid.
  • Definition wording
    • the energies and motion must be described as random.

Section 2 of 7Changing internal energy

Internal energy increases when…Internal energy decreases when…
Thermal energy is added (the system is heated)Thermal energy is lost to the surroundings
Work is done on the system, for example by compressing a gasThe system does work on its surroundings, for example a gas pushing a piston

Section 3 of 7Internal energy and temperature

  • Solids and liquids
    • molecules are close with intermolecular forces, so they have kinetic and potential energy, and vibrate more when heated.
  • Real gases
    • molecules also have potential energy from intermolecular forces, and heating makes them move faster.
  • Ideal gas
    • there are no intermolecular forces, so potential energy is zero and the internal energy is the total kinetic energy of the molecules, (3/2)NkT.
  • Proportionality
    • the internal energy is directly proportional to the temperature in kelvin, U ∝ T, and ΔU ∝ ΔT.
  • Kelvin only
    • tripling the Celsius temperature does not triple U.

Section 4 of 7Work done by an expanding gas

  • Constant pressure
    • a gas pushes back its surroundings and does work on them, W = pΔV.
    • p is the external pressure of the surroundings, not the pressure of the gas.
    • ΔV is the final volume minus the initial volume, in m3.
  • Piston
    • a gas in a cylinder pushes the piston out a distance s with force F = pA, so work = Fs = pAs = pΔV.
  • Examples
    • steam pushing a piston in an engine and a balloon inflating against atmospheric pressure.

Section 5 of 7Work done on a gas

  • Compression
    • a force must push the piston in, which needs work and reduces the volume.
  • Effect on the gas
    • the molecules speed up, so their kinetic energy and the temperature increase.
  • Sign convention
    • in the first law, W is the work done on the system.
ProcessWork term WReason
Gas expandsNegative (−)The gas does work on the surroundings
Gas is compressedPositive (+)The surroundings do work on the gas

Section 6 of 7The first law of thermodynamics

  • First law of thermodynamics = the increase in internal energy of a system equals the thermal energy added to it plus the work done on it.
    • It is energy conservation, and applies to every thermodynamic system, not only gases.
  • Equation
    • ΔU = q + W.
SymbolPositive meansNegative means
ΔUInternal energy risesInternal energy falls
qThermal energy added to the systemThermal energy removed from the system
WWork done on the systemWork done by the system

Section 7 of 7Using the first law

  1. Decide the direction of each energy transfer and give it the correct sign.
  2. Find the work from W −pΔV for an expansion (positive for a compression), using the external pressure.
  3. Find q from the information given, for example a latent heat when a substance changes state.
  4. Substitute into ΔU q + W and check the sign is physically sensible.
  • Boiling a liquid
    • heat is added (q positive) and the vapour expands against the atmosphere (W negative),
    • but internal energy rises because q is greater than the work done.

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