Section 1 of 7The mole and the Avogadro constant (HT only)
The mole
- The mole The mole (symbol mol) is the SI unit for amount of substance.
- It is a counting unit, like a dozen, but for extremely small particles.
- One mole of any substance contains the same number of the stated particles, whether they are atoms, molecules, ions or formula units.
Avogadro constant
- Avogadro constant One mole contains 6.02 × 1023 particles. This number is the Avogadro constant.
- You must say which particle you mean: 1 mol of Na is 6.02 × 1023 atoms, 1 mol of H2 is 6.02 × 1023 molecules and 1 mol of NaCl is 6.02 × 1023 formula units.
Section 2 of 7Molar mass (HT only)
Elements
- Elements One mole of an element has a mass in grams equal to its Ar.
- So 1 mol of carbon is 12 g, 1 mol of helium is 4 g and 1 mol of lithium is 7 g.
Compounds
- Compounds One mole of a compound has a mass in grams equal to its Mr.
- For carbon dioxide Mr = 12 + (2 × 16) = 44, so 1 mol has a mass of 44 g.
- The mass of one mole is called the molar mass and has units g/mol.
Section 3 of 7The key equation (HT only)
| To find | Equation | Units |
|---|---|---|
| Moles | n = m ÷ Mr | mol |
| Mass | m = n × Mr | g |
| Mr (molar mass) | Mr = m ÷ n | g/mol |
| Number of particles | N = n × 6.02 × 1023 | particles |
Section 4 of 7Worked example: mass from moles (HT only)
1
Question: what is the mass of 0.250 mol of zinc?
2
Look up the Ar of zinc: 65, so the molar mass is 65 g/mol.
3
Rearrange the equation: mass = moles × molar mass.
4
Mass = 0.250 mol × 65 g/mol = 16.25 g, which is 16.3 g to three significant figures.
Section 5 of 7Worked example: moles and particles (HT only)
1Moles from mass
- Moles from mass How many moles are in 2.64 g of sucrose (Mr = 342)? Moles = 2.64 ÷ 342 = 7.72 × 10-3 mol.
2Moles to molecules
- Moles to molecules For 15.7 g of water (Mr = 18): moles = 15.7 ÷ 18 = 0.872 mol.
3Number of molecules
- Number of molecules 0.872 × 6.02 × 1023 = 5.25 × 1023 molecules.
4Number of atoms
- Number of atoms Each water molecule has 3 atoms, so there are 3 × 5.25 × 1023 = 1.57 × 1024 atoms.
Section 6 of 7Key terms
| Term | Meaning |
|---|---|
| Mole | The unit for amount of substance; one mole contains 6.02 × 1023 particles. |
| Avogadro constant | The number of particles in one mole of a substance, 6.02 × 1023 per mole. |
| Molar mass | The mass of one mole of a substance, in g/mol, numerically equal to its Ar or Mr. |
| Formula unit | The simplest ratio of ions in an ionic compound, such as one NaCl. |
| Amount of substance | A measure of how many particles are present, measured in moles. |
Section 7 of 7Exam technique
1
Multiplying by 6.02 × 1023 without first saying whether you are counting atoms, molecules or ions; count atoms by multiplying by the atoms in the formula.
2
Using mass in kilograms in the equation; the molar mass is in g/mol so the mass must be in grams.
3
Rearranging the equation the wrong way round; check that your answer is sensible, since a heavy sample should give a number of moles that is smaller than the mass.
4
Writing only the final answer with no working, which loses method marks if a slip occurs.