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1.6.9Atomic Structure

Deducing Stoichiometry

5 min read 7 parts Lesson 30 of 30 1 quiz

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Section 1 of 7Types of equation

Word equation
  • Word equation Uses full names with reactants on the left and products on the right, joined by an arrow meaning produces.
  • Examplesodium hydroxide + hydrochloric acid → sodium chloride + water.
Symbol equation
  • Symbol equation Uses formulae and coefficients so that the numbers of each type of atom are equal on both sides.
  • Balancing follows from the fact that atoms cannot be created or destroyed.
State symbols
  • State symbols (s) solid, (l) liquid, (g) gas and (aq) aqueous, meaning dissolved in water.

Section 2 of 7Balancing

1
Write the correct formulae for all reactants and products.
2
Count the atoms of each element on each side.
3
Add coefficients in front of formulae, one element at a time, never altering subscripts.
4
For combustion of organic compounds balance carbon first, then hydrogen, then oxygen.
5
Add state symbols and check each element once more.

Section 3 of 7Ionic equations (HT only)

1Full equation
  • Full equation Zn(s) + CuSO4(aq) → ZnSO4(aq) + Cu(s).
2Split aqueous ionic compounds
  • Split aqueous ionic compounds Write each as its separate ions: Zn(s) + Cu2+ + SO42− → Zn2+ + SO42− + Cu(s).
3Cancel spectators
  • Cancel spectators Ions that appear unchanged on both sides, here SO42−, take no part in the reaction.
4Net ionic equation
  • Net ionic equation Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s). Solids, liquids and gases are never split into ions.

Section 4 of 7Deducing the equation from masses (HT only)

1
Calculate the Mr of each substance in the reaction.
2
Divide each reacting mass by its Mr to get moles.
3
Divide all the mole values by the smallest to find a ratio.
4
If the ratio is not whole numbers, multiply every value by the same factor, for example 1 : 2 : 2.5 becomes 2 : 4 : 5.
5
Use the whole numbers as the coefficients to write the balanced equation.

Section 5 of 7Worked example (HT only)

SubstanceMassMrMolesRatio
CH3OH64 g3222
O296 g3233
CO288 g4422
H2O72 g1844
Equation2CH3OH + 3O2 → 2CO2 + 4H2O

Section 6 of 7Key terms

TermMeaning
StoichiometryThe numbers of moles of each substance shown by the coefficients in a balanced equation.
Spectator ionAn ion present in a solution that does not take part in the reaction.
Ionic equationAn equation showing only the ions and particles that actually react.
AqueousDissolved in water.
CoefficientA number in front of a formula showing how many units of it react or form.

Section 7 of 7Exam technique

1
Altering the formula of a compound to make atoms balance instead of changing the coefficient.
2
Splitting solids, liquids and gases into ions in an ionic equation.
3
Leaving ratios such as 1 : 1.5 unconverted to whole numbers.
4
Cancelling ions that are not identical on both sides, including their charge and state.
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