Section 1 of 7Types of equation
Word equation
- Word equation Uses full names with reactants on the left and products on the right, joined by an arrow meaning produces.
- Examplesodium hydroxide + hydrochloric acid → sodium chloride + water.
Symbol equation
- Symbol equation Uses formulae and coefficients so that the numbers of each type of atom are equal on both sides.
- Balancing follows from the fact that atoms cannot be created or destroyed.
State symbols
- State symbols (s) solid, (l) liquid, (g) gas and (aq) aqueous, meaning dissolved in water.
Section 2 of 7Balancing
1
Write the correct formulae for all reactants and products.
2
Count the atoms of each element on each side.
3
Add coefficients in front of formulae, one element at a time, never altering subscripts.
4
For combustion of organic compounds balance carbon first, then hydrogen, then oxygen.
5
Add state symbols and check each element once more.
Section 3 of 7Ionic equations (HT only)
1Full equation
- Full equation Zn(s) + CuSO4(aq) → ZnSO4(aq) + Cu(s).
2Split aqueous ionic compounds
- Split aqueous ionic compounds Write each as its separate ions: Zn(s) + Cu2+ + SO42− → Zn2+ + SO42− + Cu(s).
3Cancel spectators
- Cancel spectators Ions that appear unchanged on both sides, here SO42−, take no part in the reaction.
4Net ionic equation
- Net ionic equation Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s). Solids, liquids and gases are never split into ions.
Section 4 of 7Deducing the equation from masses (HT only)
1
Calculate the Mr of each substance in the reaction.
2
Divide each reacting mass by its Mr to get moles.
3
Divide all the mole values by the smallest to find a ratio.
4
If the ratio is not whole numbers, multiply every value by the same factor, for example 1 : 2 : 2.5 becomes 2 : 4 : 5.
5
Use the whole numbers as the coefficients to write the balanced equation.
Section 5 of 7Worked example (HT only)
| Substance | Mass | Mr | Moles | Ratio |
|---|---|---|---|---|
| CH3OH | 64 g | 32 | 2 | 2 |
| O2 | 96 g | 32 | 3 | 3 |
| CO2 | 88 g | 44 | 2 | 2 |
| H2O | 72 g | 18 | 4 | 4 |
| Equation | 2CH3OH + 3O2 → 2CO2 + 4H2O |
Section 6 of 7Key terms
| Term | Meaning |
|---|---|
| Stoichiometry | The numbers of moles of each substance shown by the coefficients in a balanced equation. |
| Spectator ion | An ion present in a solution that does not take part in the reaction. |
| Ionic equation | An equation showing only the ions and particles that actually react. |
| Aqueous | Dissolved in water. |
| Coefficient | A number in front of a formula showing how many units of it react or form. |
Section 7 of 7Exam technique
1
Altering the formula of a compound to make atoms balance instead of changing the coefficient.
2
Splitting solids, liquids and gases into ions in an ionic equation.
3
Leaving ratios such as 1 : 1.5 unconverted to whole numbers.
4
Cancelling ions that are not identical on both sides, including their charge and state.