Section 1 of 9What power is
Power is the rate at which energy is transferred, or equivalently the rate at which work is done. A powerful machine transfers a lot of energy each second. Two people can lift the same box to the same shelf, doing the same work, but the one who does it in half the time has twice the power.
Power is a scalar measured in watts (W). One watt is one joule per second: 1 W = 1 J s−1. Larger units are the kilowatt (1 kW = 1000 W) and megawatt (1 MW = 106 W).
Section 2 of 9The equations
- RearrangedE = P t and t = E ÷ P.
- Always convert minutes and hours into seconds before substituting, unless working in kilowatt-hours.
- but at this level you are mostly expected to use the energy and time form.
Section 3 of 9Typical powers
A human climbing stairs outputs about 200 W.
The household bill uses a unit of energy called the kilowatt-hour (kWh): the energy transferred by a 1 kW device in 1 hour. 1 kWh = 1000 W × 3600 s = 3.6 × 106 J.
Section 4 of 9Power, work and efficiency
Power links closely with other ideas.
On an energy-time graph, the gradient is the power. A steeper line means a faster rate of transfer, and a straight line means constant power.
Section 5 of 9Common problem types
You may be asked to compare two machines doing the same job in different times, to calculate how long a heater takes to transfer a given amount of energy, or to work out the cost of running an appliance (energy in kWh × price per kWh).
Section 6 of 9Power in everyday devices and cost
The kilowatt-hour is how electricity is sold.
- such as heaters, matter far more than small chargers.
Power also matters for choosing equipment.
Section 7 of 9Worked examples
A student of mass 55 kg climbs a flight of stairs 3.5 m high in 5.0 s. Calculate the useful power. (g = 9.8 N kg−1)
Work done = mgh = 55 × 9.8 × 3.5 = 1886.5 J.
P = W ÷ t = 1886.5 ÷ 5.0 = 377 W.
What the symbols mean: P = power (W = J s−1) · W or E = work done / energy transferred (J) · t = time (s) · F = force (N) · v = velocity (m s−1)A 2.4 kW kettle runs for 3 minutes. How much energy does it transfer?
P = 2400 W; t = 3 × 60 = 180 s.
E = Pt = 2400 × 180 = 432 000 J = 432 kJ, which is 0.12 kWh.
A pump needs to raise 600 kg of water through 8.0 m. If the pump has a useful power of 400 W, how long does it take?
E = mgh = 600 × 9.8 × 8.0 = 47 040 J.
t = E ÷ P = 47 040 ÷ 400 = 117.6 s ≈ 118 s, about 2 minutes.
Section 8 of 9Key terms
| Term | Meaning |
|---|---|
| Power | Rate of energy transfer or rate of doing work. |
| Watt | Unit of power, one joule per second. |
| Kilowatt-hour | Energy transferred by a 1 kW device in one hour (3.6 MJ). |
| Useful power | Power transferred to the desired store. |
| Rating | The power an appliance is designed to use. |