Section 1 of 9Series circuits
In a series circuit the components are connected one after another in a single loop, so there is only one path for the charge. The current is the same at every point in the loop:
Itotal = I1 = I2 = I3
Charge is not used up as it passes through a component, and it cannot pile up anywhere, so the same amount of charge passes each point every second. An ammeter placed before or after a lamp reads the same value. If one component in a series circuit breaks, the whole circuit stops, as in old-style strings of lights.
Imagine the circuit as a loop of water pipes with a pump.
Section 2 of 9Parallel circuits
In a parallel circuit the components are connected on separate branches between the same two points. The current from the cell splits at a junction, flows through the branches, and then recombines. The total current equals the sum of the branch currents:
Itotal = I1 + I2 + I3
This is because charge is conserved at a junction: the charge arriving each second equals the charge leaving each second. The branch with the lower resistance carries the larger current.
At a junction the rule is called Kirchhoff's first law at advanced level: the sum of currents entering equals the sum of currents leaving. In a diagram, label every wire with its current and check each junction. If a current arrow is unknown, assume a direction; a negative answer then simply means the current actually flows the other way.
Section 3 of 9Identical and different branches
If two branches have identical components, the current splits equally.
- because the p.d. across each branch is the same and I = V/R.
- which is why houses use parallel circuits for lights and sockets: each appliance gets the full mains voltage and works independently.
The relative sizes of branch currents follow from V = IR, because each branch has the same p.d.
Section 4 of 9Comparing series and parallel
| Series | Parallel | |
|---|---|---|
| Paths for current | One | More than one |
| Current | Same everywhere | Splits at junctions |
| If one component fails | All stop | Others keep working |
| Total current from the cell | Small | Larger as branches are added |
Section 5 of 9Adding components
When more lamps are added in series, the total resistance increases and the current falls, so the lamps become dimmer.
This is also why plugging too many appliances into one extension lead is dangerous: the total current is the sum of the currents of each appliance, and it may exceed the rating of the cable and the fuse, so the cable overheats.
Section 6 of 9Using ammeters
To measure the current in a branch, place the ammeter in series with that branch.
- or add the branch currents to find the total.
Section 7 of 9Worked examples
Three lamps in series carry a current of 0.40 A at the first lamp. What is the current through the third lamp?
Series: the current is the same everywhere, so 0.40 A.
A parallel circuit has branches with currents 0.30 A, 0.50 A and 0.20 A. Find the total current from the cell.
I = 0.30 + 0.50 + 0.20 = 1.0 A.
The total current in a parallel circuit is 2.4 A. One branch carries 0.90 A. The two other branches are identical. Find the current in each.
Remaining current = 2.4 − 0.90 = 1.5 A.
Each identical branch = 1.5/2 = 0.75 A.
Section 8 of 9Key terms
| Term | Meaning |
|---|---|
| Series | Components connected in one loop. |
| Parallel | Components on separate branches between the same two points. |
| Junction | Point where wires meet and current splits or joins. |
| Branch | One path in a parallel circuit. |
| Conservation of charge | Charge entering a point equals charge leaving. |