2.7.7Inorganic Chemistry
Prepare an Insoluble Salt — Edexcel Linear - OL (Chemistry) Revision Notes & Topical Questions
5 min read 6 parts Lesson 21 of 23 Unit quiz
Part 1 of 6Precipitation Reactions
This method works only when the salt to be made is insoluble in water.
Idea
- Idea Two soluble salt solutions are mixed, and the ions that form an insoluble compound join and appear as a solid precipitate.
General pattern
- General pattern Soluble salt 1 + soluble salt 2 → insoluble salt + soluble salt 3, which is also called double decomposition.
Example
- Example The balanced equation is Pb(NO₃)₂(aq) + K₂SO₄(aq) → PbSO₄(s) + 2KNO₃(aq).
Ionic equation
- Ionic equation Pb²⁺(aq) + SO₄²⁻(aq) → PbSO₄(s) shows only the ions that react.
Part 2 of 6Choosing the Reactants
Choosing the Reactants
Nitrates
- Nitrates All nitrates are soluble, so lead(II) nitrate or silver nitrate is a common source of the metal ion.
Sulfates
- Sulfates Most sulfates are soluble, but lead(II), barium and calcium sulfates are insoluble.
Chlorides
- Chlorides Most chlorides are soluble, except silver and lead(II) chloride.
Carbonates and hydroxides
- Carbonates and hydroxides Most are insoluble, except those of sodium, potassium and ammonium.
| To make | Solution 1 | Solution 2 |
|---|---|---|
| Lead(II) sulfate | Lead(II) nitrate | Potassium sulfate |
| Silver chloride | Silver nitrate | Sodium chloride |
| Barium sulfate | Barium chloride | Sodium sulfate |
Part 3 of 6Method
Filtering, washing and drying purify the product.
1
Measure a fixed volume of one salt solution into a beaker.
2
Add the second solution until it is in slight excess so the maximum precipitate forms.
3
Filter the mixture so the solid stays in the filter paper.
4
Wash the residue with distilled water to remove soluble impurities.
5
Dry the precipitate in a warm oven or between filter papers.
Part 4 of 6Why Each Step Matters
Why Each Step Matters
Slight excess
- Slight excess Making sure one reactant is in excess ensures all of the other has reacted, maximising yield.
Washing
- Washing Washing removes the soluble salt solution left on the precipitate, which would contaminate it.
Distilled water
- Distilled water Distilled water is used because tap water contains dissolved ions that could add impurities.
Part 5 of 6Worked Example
Question
- 25.0 cm³ of 0.50 mol/dm³ lead(II) nitrate is mixed with excess potassium sulfate.
- Calculate the maximum mass of lead(II) sulfate formed.
- (Ar: Pb = 207, S = 32, O = 16)
- Moles of Pb(NO₃)₂ = 0.50 × 25.0 ÷ 1000 = 0.0125 mol.
- From the equation, 1 mol Pb(NO₃)₂ gives 1 mol PbSO₄, so moles of PbSO₄ = 0.0125 mol.
- Mr of PbSO₄ = 207 + 32 + (4 × 16) = 303.
- Mass = 0.0125 × 303 = 3.79 g.
Answer Maximum mass of PbSO₄ = 3.79 g
Part 6 of 6Exam Checklist & Tips
2.7.7 – Key Points for the Exam
- Precipitate An insoluble solid formed when two solutions react.
- Filtrate The liquid that passes through the filter paper.
- Residue The solid left on the filter paper.
- Insoluble Does not dissolve in water.
Common Mistakes
- Choosing an insoluble reactant, since both starting salts must be soluble.
- Skipping the washing step and leaving soluble impurities on the product.
- Trying to crystallise the filtrate to obtain the insoluble salt.
- Writing the precipitate as (aq) instead of (s) in equations.
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