5.3Equilibrium and Reaction Rates
Ionic equilibria — EST 2 Chemistry Revision Notes & Topical Questions
5 min read 8 parts Lesson 3 of 3 1 quiz
Ionic equilibria EST Chemistry notes: Calculate pH of weak acids.Larger Ka (smaller pKa) means a stronger acid.Buffers work best when pH ≈ pKa.Blood is buffered by H2CO3/HCO3− near pH 7.4.For AgCl, Ksp = [Ag+][Cl−] = s².Percent ionisation of a weak acid increases on dilution.Calc…
- Adding acid to a buffer
- Adding base
- 0.10 M acetic acid, Ka = 1.8 × 10−5. Find pH
- Ksp of AgCl is 1.8 × 10−10. Find molar solubility
- Ionic equilibria EST Chemistry: what to do next
- Common-ion effect
Part 1 of 8Key ideas
Part 2 of 8Learning objectives
Part 3 of 8Essential knowledge
Part 4 of 8Process & sequence
Weak acid pHwrite these steps in this order; each step is a marking point.
- Ionisation equation
- ICE table
- Ka = x²/C
- Solve for x
- pH = −log x
Part 5 of 8Worked examples
- x = √(1.8 × 10−6) = 1.34 × 10−3; pH = 2.87.
- s = √(1.8 × 10−10) = 1.3 × 10−5 M.
Part 6 of 8Summary
Part 7 of 8Keep going
Ionic equilibria EST Chemistry: what to do next
These Ionic equilibria EST Chemistry notes covered the key ideas, worked examples and exam technique for this topic. Check your Ionic equilibria EST Chemistry understanding with the practice questions below, then reread any Ionic equilibria EST Chemistry point you were unsure about before moving on.

Part 8 of 8Compare: Compare
| Salt from | Example | pH |
|---|---|---|
| Strong acid + strong base | NaCl | 7 |
| Strong acid + weak base | NH4Cl | < 7 |
| Weak acid + strong base | CH3COONa | > 7 |
| Relationship | Use |
|---|---|
| Ka × Kb = Kw | Conjugate pair constants |
| [H+] ≈ √(KaC) | Weak acid pH |
| pH = pKa + log([A−]/[HA]) | Buffer pH |
| Qsp > Ksp | Precipitate forms |
Key terms
Command terms
Exam technique
Keywords the mark scheme looks for in this lesson
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