1.4.5Additional lessons
Avogadro’s Law — IB Chemistry SL Revision Notes & Topical Questions
5 min read 5 parts Lesson 15 of 98
Curriculum Equation Key قوانين المول والحسابات الكيميائية - Moles & Stoichiometry FormulasFast Exam Solution
n = m / M_r | N = n × N_A (6.022 × 10²³) | M = n / V | V_gas = n × 22.4 L (STP)
Word Equation & Conditions: عدد المولات = الكتلة بالجرام ÷ الكتلة المولية | عدد الجسيمات = عدد المولات × عدد أفوجادرو
Location & Specifications: كيمياء التحصيلي وثانوي وبكالوريا و Cambridge IGCSE Chemistry.
Part 1 of 5The Law
Equal volumes of different gases contain the same number of molecules under the same conditions.
Statement
- Statement At the same temperature and pressure, equal volumes of all gases contain equal numbers of particles.
Proportionality
- Proportionality At constant temperature and pressure the volume of a gas is directly proportional to its amount in moles.
Mole ratio
- Mole ratio Therefore the ratio of volumes of gases in a reaction is the same as the ratio of their coefficients.
Conditions
- Conditions The law holds only when all volumes are measured at the same temperature and pressure.
Part 2 of 5Using It in Reactions
Gas volume ratios can replace mole ratios when everything is a gas.
1
Write the balanced equation with state symbols so that you can see which species are gases.
2
Read the coefficients of the gases to get the volume ratio, ignoring solids and liquids.
3
Multiply the given volume by the ratio to obtain the volume of the other gas.
4
State that the volumes were measured under the same conditions of temperature and pressure.
Part 3 of 5Limits
Limits
Liquid water
- Liquid water Water produced below its boiling point is a liquid and takes up almost no volume compared with gases.
Real gases
- Real gases At high pressure or low temperature, gases deviate and the proportionality is only approximate.
Different volumes
- Different volumes Volumes at different pressures or temperatures cannot be compared by the simple ratio.
Identity of gas
- Identity of gas The law does not depend on the type of gas, so a mole of any ideal gas occupies the same volume.
Part 4 of 5Worked Example
Question
- 20.0 cm³ of methane burns completely in excess oxygen: CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l).
- All volumes are measured at the same conditions.
- Find the volume of oxygen used and of carbon dioxide formed.
- The gas ratio CH₄O₂ : CO₂ = 1 : 2 : 1.
- Oxygen used = 2 × 20.0 = 40.0 cm³.
- Carbon dioxide formed = 1 × 20.0 = 20.0 cm³; water is liquid and does not count.
Answer
- 40.0 cm³ of O₂ used;
- 20.0 cm³ of CO₂ formed
Part 5 of 5Exam Checklist & Tips
1.4.5 – Key Points for the Exam
- Avogadro's law Equal volumes of gases at the same temperature and pressure contain equal numbers of molecules.
- Gas volume ratio The ratio of volumes of reacting gases, equal to the ratio of coefficients in the equation.
- Standard conditions Specified temperature and pressure at which gas volumes are compared.
- Direct proportion A relationship in which one quantity doubles when the other doubles.
Common Mistakes
- Applying the volume ratio to solids or liquids in the equation.
- Comparing gas volumes measured at different temperatures or pressures.
- Thinking that equal volumes of gases have equal masses.
- Counting liquid water as a gas when the products are cooled.
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