6.2.4Additional lessons
Acids with Reactive Metals — IB Chemistry SL Revision Notes & Topical Questions
5 min read 6 parts Lesson 87 of 98
Curriculum Equation Key pH & Acid-Base Equilibrium FormulasFast Exam Solution
pH = -log[H⁺] | pOH = -log[OH⁻] | pH + pOH = 14 | [H⁺][OH⁻] = 10⁻¹⁴
Word Equation & Conditions: pH + pOH = 14
Section 1 of 6The General Reaction

Metals above hydrogen in the reactivity series can displace it from dilute acids.
Word equation
- Reactive metal + dilute acid → salt + hydrogen.
Magnesium
- Magnesium gives magnesium chloride and hydrogen: Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g).
Zinc
- Zinc with sulfuric acid givesZn(s) + H₂SO₄(aq) → ZnSO₄(aq) + H₂(g).
Iron
- Fe(s) + 2HCl(aq) → FeCl₂(aq) + H₂(g), forming iron(II) rather than iron(III).
Section 2 of 6Redox Analysis
Redox Analysis
Oxidation
- The metal loses electrons and its oxidation number increases, for example Mg: 0 → +2.
Reduction
- H⁺ gains electrons to form H₂, so hydrogen goes from +1 to 0.
Ionic equation
- Mg(s) + 2H⁺(aq) → Mg²⁺(aq) + H₂(g); the anion is a spectator.
Reducing agent
- The metal is the reducing agent and the acid supplies the oxidising agent H⁺.
Section 3 of 6Observations and Tests
1
Effervescence shows that hydrogen gas is being made.
2
The metal slowly dissolves, and the test tube becomes warm because the reaction is exothermic.
3
A lit splint held at the mouth of the tube burns with a squeaky pop.
4
More reactive metals react faster, so rate order is Mg > Zn > Fe.
5
Copper, silver and gold lie below hydrogen and do not react with dilute acids.
Section 4 of 6Linking to Reactivity
Linking to Reactivity
Order of reactivity
- Rate of hydrogen production increases from iron to zinc to magnesium, reflecting the ease of oxidation.
Safety
- Hydrogen is flammable, so the gas should be collected away from flames and tested in small quantities.
Evidence of redox
- The disappearance of the metal and the formation of H₂ show electrons being transferred from metal to H⁺.
Sulfuric acid note
- Dilute sulfuric acid with lead stops quickly because insoluble lead(II) sulfate coats the metal.
Section 5 of 6Worked Example
Question
- Calculate the volume of hydrogen released at STP when 0.250 g of magnesium reacts with excess dilute hydrochloric acid.
- Molar volume of a gas at STP is 22.7 dm³ mol⁻¹.
- Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g), so 1 mol Mg gives 1 mol H₂.
- n(Mg) = 0.250 / 24.31 = 0.01028 mol, so n(H₂) = 0.01028 mol.
- V = 0.01028 × 22.7 = 0.233 dm³.
Answer 0.233 dm³ (233 cm³) of hydrogen.
Section 6 of 6Exam Checklist & Tips
6.2.4 – Key Points for the Exam
- Salt The ionic compound formed when metal replaces hydrogen in an acid.
- Spectator ion An ion present but not changing in the reaction, such as Cl⁻.
- Reactivity series The order of metals by ease of oxidation.
- Effervescence The formation of gas bubbles in a liquid.
Common Mistakes
- Writing iron(III) chloride as the product with dilute HCl; the product is iron(II) chloride.
- Saying that all metals react with dilute acids, forgetting that copper does not.
- Using dilute nitric acid as a typical example: nitrate is reduced, so H₂ is not the usual product.
- Leaving the equation unbalanced, for example Mg + HCl → MgCl₂ + H₂.
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