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6.2.5Additional lessons

Primary Cells — IB Chemistry SL Revision Notes & Topical Questions

5 min read 6 parts Lesson 88 of 98

📚 IB Chemistry SL Hub / Topical Revision
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Part 1 of 6How a Voltaic Cell Works

6.2.5 Primary Cells

A primary cell is a voltaic cell that cannot be recharged, because its reaction is not easily reversed.

Spontaneous redox
  • A voltaic (galvanic) cell produces electricity from a spontaneous redox reaction.
Separate half-cells
  • The oxidation and reduction occur in different half-cells, so electrons travel through an external circuit.
Anode and cathode
  • Oxidation occurs at the anode (negative) and reduction at the cathode (positive).
Salt bridge
  • A salt bridge with an inert electrolyte, such as KNO₃, completes the circuit by letting ions move.

Part 2 of 6The Zinc–Copper (Daniell) Cell

The Zinc–Copper (Daniell) Cell
Anode (−)
  • Zn(s) → Zn²⁺(aq) + 2e⁻; the zinc electrode loses mass.
Cathode (+)
  • Cu²⁺(aq) + 2e⁻ → Cu(s); copper is deposited.
Electron flow
  • Electrons move from the zinc to the copper electrode through the wire.
Overall
  • Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s), giving a voltage of about 1.10 V.
FeatureZinc half-cellCopper half-cell
ProcessOxidationReduction
PolarityNegativePositive
Electrode changeMass decreasesMass increases

Part 3 of 6The Hydrogen–Oxygen Fuel Cell

1
A fuel cell supplies the fuel and oxygen continuously, so it keeps working as long as they are supplied.
2
At the negative electrode hydrogen is oxidised: in acid, H₂ → 2H⁺ + 2e⁻.
3
At the positive electrode oxygen is reduced: O₂ + 4H⁺ + 4e⁻ → 2H₂O.
4
The overall reaction 2H₂ + O₂ → 2H₂O gives water as the only product.
5
Hydrogen storage and its production from fossil fuels are the main limitations.

Part 4 of 6Components of the Cell

Components of the Cell
Electrodes
  • Metal strips act as conductors that provide the surface where electrons are lost or gained.
Electrolytes
  • Each half-cell contains a solution of the metal's own ions, such as ZnSO₄(aq) for the zinc half-cell.
Voltmeter
  • A high-resistance voltmeter measures the potential difference without allowing a large current.
Cell notation
  • The cell is written Zn(s) | Zn²⁺(aq) || Cu²⁺(aq) | Cu(s), with the anode on the left and the salt bridge as ||.

Part 5 of 6Worked Example

Question

  • A voltaic cell is made from magnesium in Mg²⁺(aq) and copper in Cu²⁺(aq).
  • Write the half-equations, the direction of electron flow and the overall equation.

  1. Magnesium is more reactive, so it is oxidised at the anode: Mg(s) → Mg²⁺(aq) + 2e⁻.
  2. Copper(II) ions are reduced at the cathode: Cu²⁺(aq) + 2e⁻ → Cu(s).
  3. Electrons flow from Mg to Cu in the external circuit; add the equations to obtain the overall reaction.

Answer

  • Mg(s) + Cu²⁺(aq) → Mg²⁺(aq) + Cu(s);
    • electrons flow from the magnesium electrode to the copper electrode.

Part 6 of 6Exam Checklist & Tips

6.2.5 – Key Points for the Exam

  • Voltaic cell A cell that generates electricity from a spontaneous redox reaction.
  • Anode The electrode where oxidation occurs.
  • Salt bridge A link containing mobile ions that completes the circuit.
  • Primary cell A non-rechargeable voltaic cell.
  • Fuel cell A cell where fuel and oxidant are fed in continuously.

Common Mistakes

  • Placing the anode as positive in a voltaic cell; it is negative in a voltaic cell.
  • Showing electrons flowing through the salt bridge; only ions move there.
  • Thinking that a salt bridge is optional; without it the circuit is incomplete.
  • Treating a fuel cell as storing energy like a battery rather than converting a continuous supply.

Last updated:

Cambridge 9700 AS Biology Core Formula

Magnification Triangle & Unit Conversion

Formula: M = I / A  ⇔  A = I / M  ⇔  I = M × A

Units: 1 mm = 1,000 μm = 1,000,000 nm.
Rule: Convert Image size (ruler mm) to μm by ×1,000 before dividing by Actual size.