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6.3.2Additional lessons

Homolytic Fission — IB Chemistry SL Revision Notes & Topical Questions

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📚 IB Chemistry SL Hub / Topical Revision
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Curriculum Equation Key قوانين الرقم الهيدروجيني والاتزان الأيوني - pH & Acid-Base Equilibrium FormulasFast Exam Solution
pH = -log[H⁺] | pOH = -log[OH⁻] | pH + pOH = 14 | [H⁺][OH⁻] = 10⁻¹⁴
Word Equation & Conditions: الرقم الهيدروجيني = -لوغاريتم تركيز أيون الهيدروجين | pH + pOH = 14
Location & Specifications: الاتزان الأيوني، كيمياء 3 ثانوي، التحصيلي، و AP Chemistry.
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Section 1 of 6Homolytic Fission

Homolytic fission usually happens with non-polar bonds in the presence of heat or UV radiation.

Definition
  • Definition In homolytic fission a covalent bond breaks so that each atom keeps one electron of the shared pair.
Products
  • Products Two radicals form, for example Cl–Cl → Cl• + Cl•.
Fishhook arrows
  • Fishhook arrows A curly arrow with a half head shows the movement of a single electron.
Energy needed
  • Energy needed Energy at least equal to the bond enthalpy must be supplied, for example 242 kJ mol⁻¹ for Cl–Cl and 193 kJ mol⁻¹ for Br–Br.

Section 2 of 6Conditions for Fission

1
UV light supplies photons with enough energy to break the bond.
2
The photon energy is absorbed by one molecule and a bond breaks homolytically.
3
High temperature can also provide enough energy for bonds to break homolytically.
4
The radicals produced start a chain reaction, as in the chlorination of methane.

Section 3 of 6Comparing Bond Fission Types

Comparing Bond Fission Types
Homolytic
  • Homolytic Each atom takes one of the shared electrons, so two radicals are produced.
Heterolytic
  • Heterolytic One atom takes both electrons, producing a cation and an anion.
Bond type
  • Bond type Non-polar bonds tend to break homolytically, while polar bonds tend to break heterolytically.
Arrow
  • Arrow Homolytic uses half-arrows and heterolytic uses full-headed arrows.
FeatureHomolyticHeterolytic
ElectronsOne to each atomBoth to one atom
ProductsTwo radicalsTwo ions
ArrowHalf-headedFull-headed

Section 4 of 6Photochemical Reactions

Photochemical Reactions
UV and bond breaking
  • UV and bond breaking UV photons have enough energy to break the Cl–Cl bond, whereas infrared light does not.
Single photon
  • Single photon One photon breaks one bond, so the intensity of light affects how many radicals form.
Chain reactions
  • Chain reactions Each initiation step creates two radicals, and each can start a long chain.
Bond enthalpy trends
  • Bond enthalpy trends Weaker bonds such as Br–Br need less energy to break than Cl–Cl.

Section 5 of 6Worked Example

Question

  • Calculate the longest wavelength of light able to break one Cl–Cl bond if the bond enthalpy is 242 kJ mol⁻¹.
  • Use L = 6.02 × 10²³ mol⁻¹, h = 6.63 × 10⁻³⁴ J s and c = 3.00 × 10⁸ m s⁻¹.

  1. Energy per bond = 242 000 / 6.02 × 10²³ = 4.02 × 10⁻¹⁹ J.
  2. λ = hc / E = (6.63 × 10⁻³⁴ × 3.00 × 10⁸) / 4.02 × 10⁻¹⁹.
  3. λ = 4.95 × 10⁻⁷ m = 495 nm.

Answer

  • About 495 nm;
    • any shorter wavelength, including UV, can cause homolytic fission.

Section 6 of 6Exam Checklist & Tips

6.3.2 – Key Points for the Exam

  • Homolytic fission Breaking of a covalent bond so each atom gets one electron.
  • Photon A packet of electromagnetic radiation energy.
  • Bond enthalpy The energy needed to break one mole of a bond in gaseous molecules.
  • Fishhook arrow A curved arrow with half a head, showing the movement of one electron.

Common Mistakes

  • Drawing a full-headed arrow for homolytic fission.
  • Producing ions from homolytic fission instead of radicals.
  • Forgetting that energy must be absorbed to break bonds.
  • Using visible light as the typical condition in school work instead of UV.

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