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Theme D — Fields

D.1.10 Escape Speed — IB Physics HL Revision Notes & Topical Questions

5 min read 9 parts Lesson 12 of 39 1 quiz

📚 IB Physics HL Hub / Topical Revision
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Curriculum Equation Key قوانين الرقم الهيدروجيني والاتزان الأيوني - pH & Acid-Base Equilibrium FormulasFast Exam Solution
pH = -log[H⁺] | pOH = -log[OH⁻] | pH + pOH = 14 | [H⁺][OH⁻] = 10⁻¹⁴
Word Equation & Conditions: الرقم الهيدروجيني = -لوغاريتم تركيز أيون الهيدروجين | pH + pOH = 14
Location & Specifications: الاتزان الأيوني، كيمياء 3 ثانوي، التحصيلي، و AP Chemistry.
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Lesson summary

D.1.10 Escape Speed — IB PHYSICS HL notes: Define escape speed and derive and use vesc = √(2GM/r).Escape speed — the minimum speed that allows an object to escape a gravitational field with no further energy inputReaching infinity — the object arrives there with zero speedIndepen…

  • Independent of mass
  • Independent of direction
  • Depends on
  • Escape of the field
  • Surface form
  • Potential form

Part 1 of 7Definition

Escape speed
  • Escape speed the minimum speed that allows an object to escape a gravitational field with no further energy input
Reaching infinity
  • Reaching infinity the object arrives there with zero speed
Independent of mass
  • Independent of mass it is the same for a rocket and a tennis ball at the same point
Independent of direction
  • Independent of direction provided the path does not hit the planet
Depends on
  • Depends on the mass and radius of the body creating the field, such as a planet, moon or black hole
Escape of the field
  • Escape of the field not just of the planet's surface, which may be a large distance away

Part 2 of 7Derivation

1
All kinetic energy is transferred to gravitational potential energy, so total energy at infinity is zero.
2
Set ½mvesc2 = GMm/r.
3
Cancel the mass m on both sides.
4
Multiply by 2 and take the square root.
5
Result: vesc = √(2GM/r).
Symbols
  • M is the mass of the body in kg, r the distance from its centre in m, vesc in m s−1
Surface form
  • Surface form using g = GM/r2, vesc = √(2gr)
Potential form
  • ½v2 equals the magnitude of the potential at the launch point

Part 3 of 7Dependence and typical values

Mass
  • Mass a larger planet mass gives a larger escape speed
Radius
  • Radius a larger distance from the centre gives a smaller escape speed
Earth
  • 11.2 km s−1
Moon
  • Moon about 2.4 km s−1

Part 4 of 7Escape speed and orbit

Orbital speed
  • Orbital speed vorb = √(GM/r)
Relation
  • Relation vesc = √2 × vorb at the same radius
Bound orbit
  • Bound orbit negative total energy
  • Escape needs total energy zero
Rockets
  • Rockets they need not reach escape speed to enter orbit because thrust adds energy continually and orbit needs less energy than escape

Part 5 of 7Energy and atmospheres

Total energy
  • E = ½mv2 − GMm/r at launch
Atmosphere
  • Atmosphere light gases such as hydrogen can leak from low-mass planets because some molecules exceed the escape speed
Moon
  • Moon it has virtually no atmosphere because its escape speed is small
Black hole
  • Black hole a body whose escape speed would exceed c

Part 6 of 7Definition wording

Say field
  • Say field describe escape from the gravitational field and avoid the words gravity or pull
Data booklet
  • Data booklet the equation is given, but its derivation must be known

Part 7 of 7More from the specification

More from the specification
Escape velocity calculation
  • Escape velocity calculation equating launch kinetic energy to gravitational binding potential provides an analytical means to derive escape velocity.
Escape Speed from a Gravitational Field
  • Escape speed vesc is the minimum initial speed required for an unpowered object to escape the gravitational attraction of a massive body to infinity, derived by equating kinetic energy to the change in gravitational potential energy: ½·m·vesc² = G·M·m / r,
  • giving vesc = √(2·G·M / r).
Gravitational Potential Energy and Field Strength Curves
  • On a graph of gravitational force or field strength against radial distance r, gravitational field strength g follows an inverse-square curve (g ∝ 1/r²),
  • while near a planet's surface the field can be approximated as uniform with parallel field lines.
Orbital Mechanics and Satellite Motion
  • A satellite in stable circular motion around Earth experiences an inward resultant centripetal force equal to gravitational pull;
    • its orbital speed vorbit = √(G·M / r) is related to escape speed by vesc = √2·vorbit, with orbital period T = 2π·r / v.
Field lines
  • Lines showing the direction and strength of a magnetic field.
Equipotential line
  • A line joining points of equal gravitational potential.
Potential gradient
  • The rate of change of potential with distance, equal to −E
Centripetal force
  • Net force toward the centre, mv2/r.
Escape velocity
  • Minimum speed to escape a planet's gravity without further propulsion; about 11.2 km/s for Earth.
Satellite
  • A body that orbits a larger one; the Moon is the Earth's natural satellite.
Uniform
  • Same density throughout, so the weight acts at the centre.
Period
  • Time for one revolution.
Newton
  • Unit of force, kg m s-2.
Constant
  • Not changing.
Density
  • Mass per unit volume.
Equipotential
  • A surface of constant potential
Field strength
  • G = Fg/m.

Key terms

TermMeaning
Escape speedThe minimum launch speed to reach infinity without further propulsion.
Total energy zeroThe condition at the escape threshold where kinetic energy balances potential energy.
Bound orbitAn orbit with negative total energy.
√2 relationvesc = √2 × vorb at the same radius.
Black holeA body whose escape speed exceeds c at some radius.

Avoid these mistakes

1
Thinking the mass of the escaping object changes the escape speed — it cancels.
2
Using altitude instead of distance from the centre.
3
Believing the projectile must keep moving at escape speed all the way — its speed falls to zero at infinity.
4
Mixing up escape speed with orbital speed — they differ by a factor √2.
5
Saying escape needs a vertical launch — any direction works.

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