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Theme A — Space, Time and Motion

A.1.6 Projectile Motion — IB Physics HL Revision Notes & Topical Questions

5 min read 9 parts Lesson 8 of 63 1 quiz

📚 IB Physics HL Hub / Topical Revision
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Lesson summary

A.1.6 Projectile Motion — IB PHYSICS SL notes: Analyse projectile motion by treating horizontal and vertical components independently, with and without air resistance.Projectile = a particle moving freely under gravity alone in a two-dimensional plane, after being launched.Exampl…

  • Assumptions
  • Independence
  • Components of the launch velocity
  • Vertical (up positive)
  • Horizontal launch from height h
  • Landing speed

Section 1 of 9What a projectile is

Projectile
Projectile a particle moving freely under gravity alone in a two-dimensional plane, after being launched.
  • Examples are a thrown ball, a diver leaving a board and a struck baseball.
Assumptions
  • Assumptions fluid resistance is negligible and g is constant near Earth's surface.
Launch
  • Launch speed u at an angle θ to the horizontal.

Section 2 of 9Horizontal and vertical components

Horizontal and vertical components
Independence
  • Independence the horizontal and vertical motions are independent of each other and are analysed separately with the suvat equations.
Time
  • Time it is the same for both directions and is the link between them.
Components of the launch velocity
  • Components of the launch velocity horizontal u cos θ and vertical u sin θ.
QuantityHorizontalVertical
AccelerationZerog = 9.8 m s−2 downwards
VelocityConstantChanges uniformly; zero at maximum height
DisplacementRange at the end of the flightMaximum height at half the flight time

Section 3 of 9Equations of motion

1Horizontal
  • Horizontal ax = 0, so x = uxt with ux constant.
2Vertical (up positive)
  • Vertical (up positive) vy = uy − gt, y = uyt − ½gt2 and vy2 = uy2 − 2gy.
3Horizontal launch from height h
  • Horizontal launch from height h uy = 0 so the fall time is t = √(2h/g), independent of the horizontal speed.
  • A ball dropped and a ball fired horizontally from the same height reach level ground together.
4Landing speed
  • Landing speed v = √(vx2 + vy2) at angle tan−1(vy / vx) below the horizontal.

Section 4 of 9Level-ground results

Path
  • Path a symmetric parabola when launch and landing heights are equal.
Highest point
  • Highest point vy = 0 but the speed equals vx, which is not zero.
Time of flight
  • Time of flight the time to the top is uy/g, so the total time is 2uy/g.
Maximum height
  • H = uy2 / (2g).
Range
  • R = u2 sin 2θ / g, greatest at θ = 45°.
  • Complementary angles such as 30° and 60° give the same range.
  • The steeper angle has the longer flight time and greater height.
Acceleration
  • Acceleration it is 9.8 m s−2 downwards at every point and the velocity is tangent to the path.

Section 5 of 9Effect of air resistance

Without drag
  • Without drag mechanical energy is conserved, so the speed at a given height does not depend on the launch angle.
With drag
  • With drag the resistive force opposes the velocity and the path is no longer a parabola.
QuantityEffect of air resistance
Time of flightDecreases
Horizontal velocityDecreases
RangeDecreases
Maximum heightDecreases
TrajectorySteeper on the way down than on the way up
Landing speedLower
  • Light objects
    • a badminton shuttle is affected far more than a dense shot put, because the force depends on speed and cross-section.

Section 6 of 9Method and applications

1
Resolve the launch velocity into horizontal and vertical components.
2
Choose signs and list the known values for each direction.
3
Use the vertical equations to find the time.
4
Use x = uxt with that time to find the range.
5
Combine components if the final speed or direction is wanted.
Method and applications
Quadratic in t
  • Quadratic in t it appears when there is a height difference between launch and landing.
Sport
  • Sport a shot putter releases above ground level, so the best angle is a little below 45°.
Gymnastics and ski jumping
  • Gymnastics and ski jumping a large initial vertical velocity gives greater height and flight time.

Section 7 of 9More from the specification

More from the specification
Projectile motion
  • Projectile motion horizontal velocity is constant while vertical motion has constant acceleration g downward.
Independence of components
  • Independence of components the two motions are analysed separately and share only the time of flight.
Motion graphs
  • Motion graphs the gradient of a displacement-time graph gives velocity and of a velocity-time graph gives acceleration.
Terminal velocity
  • Terminal velocity a skydiver or cyclist stops accelerating when drag equals the driving or weight force.
Average speed
  • Average speed total distance divided by total time; area under a velocity-time graph gives displacement.
Distance
  • Total length of path travelled, a scalar.
Terminal
  • Connection point of a cell, labelled + or −.
Gradient
  • Slope of a graph line.
Vector
  • Quantity with magnitude and direction.
Terminal velocity
  • Constant speed when air resistance equals weight.
Kinematic equations
  • Equations relating displacement, velocity, acceleration and time for constant acceleration.
Velocity-time graph
  • A graph of velocity against time whose gradient is acceleration and area is displacement.
Average speed
  • Total distance divided by total time.

Section 8 of 9Key terms

TermMeaning
ProjectileObject moving under gravity alone after launch
TrajectoryThe curved path followed by a projectile
ComponentPart of a vector along a chosen axis
Time of flightTotal time from launch to landing
RangeHorizontal distance travelled before landing
ParabolaShape of the path when air resistance is negligible

Section 9 of 9Exam technique

1
Thinking the horizontal velocity changes because gravity acts — without drag it is constant.
2
Believing the speed is zero at the top — only the vertical component is zero.
3
Using the launch speed in the suvat equations instead of its components — resolve first.
4
Assuming a heavier object falls faster — without air resistance all fall together.
5
Drawing the real path with drag as symmetric — it is steeper on the way down.

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Physics 0625 & 9702 SUVAT Mastery Graph Interpretation

Constant Acceleration Equations (SUVAT) & Slopes

v = u + at  |  s = ut + ½at2  |  v2 = u2 + 2as  |  s = ½(u + v)t

  • Displacement-Time Graph: Gradient = Velocity (curve = accelerating).
  • Velocity-Time Graph: Gradient = Acceleration; Area under curve = Distance travelled / Displacement.
  • Free Fall in vacuum: a = g ≈ 9.81 m/s2 downwards (air resistance negligible).
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