3.6.1 Work Done — OCR A Level Physics A notes: Define work done by a force, including when the force is at an angle, and interpret force–displacement graphs.Work done by a force is the energy transferred when the force moves its point of application.
- area under the graph
- Worked example 1
- Worked example 2
- Worked example 3
- Component of force
- Negative work
Section 1 of 8Definition
Work done by a force is the energy transferred when the force moves its point of application.
Section 2 of 8Force at an angle
Only the component of force along the displacement does work.
- or the tension supplying circular motion) no work is done.
Lifting a mass m at constant speed through height h needs a force equal to the weight mg, so the work done against gravity is mgh. Pulling a sledge with a rope at 30° above the horizontal through 50 m with a 60 N tension does 60 × 50 × cos 30° joules, not 60 × 50.
Section 3 of 8Variable forces and graphs
When the force varies, we plot force against displacement.
- which is the elastic potential energy stored (link to 3.7).What the symbols mean: F = force (N) · k = spring constant (N m−1) · x or e = extension (m)
If the force is positive over one section and negative over another, areas above the axis count as positive work and areas below as negative.
Section 4 of 8Work and energy links
When work is done on a body, its energy changes: the work done equals the energy transferred.
Remember that a person holding a heavy bag stationary does no work in the physics sense, because there is no displacement, even though muscles tire from chemical energy conversions inside the body.
Section 5 of 8Practical applications of work
Work calculations are common in experimentsa trolley pulled up a slope by a falling mass, a student lifting books to a shelf, or a spring compressed by a force sensor.
In a typical practical, a force is measured with a newton-meter while a trolley is pulled a known distance along a bench; the work done is the force times the distance moved in the direction of the force.
Section 6 of 8Worked examples
A 50 N force pulls a trolley 8.0 m along a floor via a rope at 35° above the horizontal. Find the work done by the force.
W = Fs cos θ = 50 × 8.0 × cos 35° = 400 × 0.819 = 328 J.
A crane lifts a 250 kg load at constant speed through 12 m. Find the work done by the crane's cable.
F = mg = 250 × 9.81 = 2450 N. W = Fs = 2450 × 12 = 2.9 × 104 J (29 kJ).
A force rises uniformly from 0 to 30 N as an object is moved 0.20 m. Find the work done.
Area of triangle = ½ × 30 × 0.20 = 3.0 J.
Section 7 of 8Key terms
| Term | Meaning |
|---|---|
| Work done | Energy transferred by a force moving through a distance in its direction. |
| Joule | Work done by 1 N moving 1 m in the direction of the force. |
| Component of force | Part of the force acting along a chosen direction. |
| Force–displacement graph | Plot whose area gives the work done. |
| Negative work | Work done by a force opposing the displacement. |
| Power | Rate of doing work, in watts. |