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8.1.5Global Challenges

Estimating Decelerating Forces

5 min read 6 parts Lesson 6 of 21 Unit quiz

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Section 1 of 6Force from Deceleration

8.1.5 Estimating Decelerating Forces

A resultant force is needed to slow any moving object down.

Newton's second law
  • The resultant force equals mass multiplied by acceleration, F = m × a, and a deceleration is a negative acceleration.
Estimating mass
  • A small family car has a mass of roughly 1000 to 1500 kg, and a person about 70 kg.
Estimating deceleration
  • Normal braking is about 2 to 3 m/s², while an emergency stop on a dry road is roughly 7 to 8 m/s².
Direction
  • The decelerating force acts opposite to the direction of motion, so it is shown as negative in a calculation.
SituationTypical decelerationForce on 1200 kg car
Gentle braking2 m/s²2400 N
Hard braking5 m/s²6000 N
Emergency stop, dry road8 m/s²9600 N

Section 2 of 6Work Done by the Brakes

Braking transfers kinetic energy, and this gives a second way to estimate the force.

1
A moving car has kinetic energy equal to ½mv², which depends on the square of its speed.
2
The brakes apply a force over the braking distance, and work done equals force multiplied by distance.
3
To stop the car, the work done by the braking force must equal the kinetic energy it had.
4
Therefore F × d = ½mv², so a longer braking distance means a smaller average braking force.
5
The kinetic energy becomes thermal energy in the brakes, tyres and road, which is why brakes get hot.

Section 3 of 6Reducing Forces in Collisions

Reducing Forces in Collisions
Force and time
  • For the same change in momentum, taking longer to stop reduces the average force on a person.
Crumple zones
  • The front and rear of a car are designed to collapse, which lengthens the stopping time and absorbs energy.
Seat belts and air bags
  • These spread the force over a larger area and stretch the stopping time, so injuries are reduced.
Cycle helmets
  • The foam lining crushes during an impact, increasing the stopping time and lowering the force on the skull.

Section 4 of 6Making Sensible Estimates

Round numbers
  • Use one significant figure and typical values, because the answer is only meant to give the right order of magnitude.
Check units
  • Convert mass to kilograms and speed to metres per second before using any equation.
Cross-check
  • Compare the answer with a familiar force, such as the weight of a car at about 12 000 N.
State assumptions
  • Say that braking force is treated as constant, even though real forces vary during a stop.

Section 5 of 6Worked Example

Question

  • A car of mass 1200 kg travelling at 20 m/s brakes to a stop in 40 m.
  • Estimate the average braking force.

  1. Kinetic energy = ½ × 1200 × 20² = ½ × 1200 × 400 = 240 000 J.
  2. Work done by the brakes equals this energy, so F × 40 = 240 000.
  3. F = 240 000 ÷ 40 = 6000 N.
  4. Check with F = maa = 20² ÷ (2 × 40) = 5 m/s², and 1200 × 5 = 6000 N.

Answer The average braking force is about 6000 N.

Section 6 of 6Exam Checklist & Tips

8.1.5 – Key Points for the Exam

  • Deceleration Acceleration that reduces the speed of an object, with the force acting opposite to the motion.
  • Resultant force The single force that has the same effect as all the forces acting on an object.
  • Kinetic energy The energy of a moving object, given by ½mv².
  • Crumple zone A part of a vehicle that deforms in a crash to increase the time taken to stop.
  • Order of magnitude An estimate that is correct to the nearest power of ten.

Common Mistakes

  • Using speed in km/h or mph in equations instead of converting to m/s.
  • Forgetting to square the speed when finding kinetic energy.
  • Using the car mass in tonnes instead of kilograms.
  • Thinking a longer stopping distance needs a bigger braking force; it needs a smaller one.
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