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8.1.6Global Challenges

Estimating Braking Distances, Speeds and Accelerations

5 min read 6 parts Lesson 7 of 21 Unit quiz

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Section 1 of 6Stopping Distance

8.1.6 Estimating Braking Distances, Speeds and Accelerations

The total distance needed to stop has two separate parts.

Thinking distance
  • The distance travelled during the driver's reaction time, found from speed × reaction time at constant speed.
Braking distance
  • The distance travelled after the brakes are applied until the vehicle is at rest.
Total
  • Stopping distance equals thinking distance plus braking distance.
Typical reaction time
  • A normal reaction time is about 0.2 to 0.9 seconds, and tiredness, alcohol or distraction makes it longer.

Section 2 of 6Calculating with v² = u² + 2as

For a car braking at constant deceleration, follow these steps.

1
Convert the speed to metres per second, because the equation only works in SI units.
2
Set the final velocity v to zero, since the vehicle ends at rest.
3
Rearrange the equation to give the braking distance s = u² ÷ (2a), using the size of the deceleration.
4
Work out the thinking distance separately as speed multiplied by reaction time.
5
Add the two distances and give the answer with a sensible number of significant figures.

Section 3 of 6Effect of Speed

Effect of Speed
Thinking distance
  • This is directly proportional to speed, so doubling the speed doubles the thinking distance.
Braking distance
  • This is proportional to the speed squared, so doubling the speed makes it four times longer.
Road conditions
  • Wet or icy roads and worn tyres reduce the possible deceleration, which increases braking distance.
Why it matters
  • Small increases in speed raise stopping distance greatly, which is why speed limits are lower near schools.
Speed (m/s)Thinking distance (m)Braking distance (m)Stopping distance (m)
1071017
20144054
302190111

Section 4 of 6Typical Values to Remember

The table above uses a reaction time of 0.7 s and a deceleration of 5 m/s².

Walking and cycling
  • A person walks at about 1.5 m/s and cycles at about 6 m/s, which helps judge whether an estimate is reasonable.
Car speeds
  • A car on a motorway travels at roughly 30 m/s, which is about 70 mph.
Car acceleration
  • A family car accelerating from rest reaches 27 m/s in about 10 seconds, an acceleration near 2.7 m/s².
Checking answers
  • A braking distance of several kilometres, or a deceleration far above 10 m/s², should alert you to an error.

Section 5 of 6Worked Example

Question

  • A car travels at 25 m/s.
  • The driver's reaction time is 0.80 s and the car then decelerates uniformly at 6.0 m/s².
  • Calculate the stopping distance.

  1. Thinking distance = 25 × 0.80 = 20 m.
  2. Braking distance0 = 25² − 2 × 6.0 × s, so s = 625 ÷ 12 = 52.1 m.
  3. Stopping distance = 20 + 52.1 = 72.1 m.

Answer The stopping distance is about 72 m.

Section 6 of 6Exam Checklist & Tips

8.1.6 – Key Points for the Exam

  • Thinking distance The distance a vehicle travels while the driver reacts to a hazard.
  • Braking distance The distance a vehicle travels while the brakes are slowing it to a stop.
  • Stopping distance The sum of thinking distance and braking distance.
  • Reaction time The time between seeing a hazard and starting to brake.
  • Uniform acceleration Acceleration that stays constant, so the equations of motion can be used.

Common Mistakes

  • Using the equation v² = u² + 2as with speed in km/h rather than m/s.
  • Treating braking distance as proportional to speed instead of speed squared.
  • Forgetting to add the thinking distance to the braking distance.
  • Using a negative acceleration and a negative distance together and losing track of the sign.
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