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1.8.4Physical Chemistry

Enthalpy of Hydration

5 min read 6 parts Lesson 43 of 63

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Section 1 of 6Definitions

1.8.4 Enthalpy of Hydration
Enthalpy of solution
  • The enthalpy change when one mole of an ionic solid dissolves in enough water to form an effectively infinitely dilute solution.
Enthalpy of hydration
  • The enthalpy change when one mole of a gaseous ion dissolves in enough water to form an infinitely dilute solution.
Example
  • Mg²⁺(g) + aq → Mg²⁺(aq) is the hydration of magnesium ions, and this process is always exothermic.
Meaning of aq
  • The symbol aq represents excess water, so the ions are surrounded by water and no longer interact with each other.

Section 2 of 6Why Hydration Is Exothermic

Why Hydration Is Exothermic
Polar water
  • Water has a partial negative oxygen and partial positive hydrogens, so it can attract both cations and anions.
Cations
  • The oxygen lone pairs of water point towards positive ions and form ion–dipole attractions with them.
Anions
  • The hydrogen atoms of water point towards negative ions, forming ion–dipole attractions that release energy.
Energy
  • Forming these attractions releases energy, which is why all hydration enthalpies are negative.

Section 3 of 6Factors and the Energy Cycle

Charge density
  • Ions with a higher charge and smaller radius attract water more strongly, giving a more exothermic hydration enthalpy.
Group 1 and 2
  • Mg²⁺ is more strongly hydrated than Na⁺ because it is smaller and carries twice the charge.
Cycle
  • Solid → gaseous ions (lattice dissociation, endothermic) → aqueous ions (hydration, exothermic) gives the enthalpy of solution.
Equation
  • ΔHsol = ΔHlatt(dissociation) + ΣΔHhyd, or equivalently −ΔHlatt(formation) + ΣΔHhyd.
QuantitySignProcess
Lattice dissociationPositiveSolid to gaseous ions
Hydration of an ionNegativeGaseous ion to aqueous ion
SolutionEitherSolid to aqueous ions

Section 4 of 6Interpreting Results

Interpreting Results
Exothermic solution
  • The hydration energy released outweighs the lattice energy needed, so the solution warms.
Endothermic solution
  • The lattice energy is greater than the hydration energy released, so the solution cools.
Solubility
  • Solubility also depends on entropy change, so an endothermic solution can still occur if disorder increases enough.

Section 5 of 6Worked Example

Question

  • Calculate the enthalpy of solution of NaCl using: lattice dissociation = +787;
    • hydration of Na⁺ = −406;
    • hydration of Cl⁻ = −364 (all kJ mol⁻¹).

  1. EquationΔHsol = ΔHlatt(dissociation) + ΔHhyd(Na⁺) + ΔHhyd(Cl⁻).
  2. Substitute+787 + (−406) + (−364).
  3. Add the hydration terms−770.
  4. 787 − 770 = +17.

Answer ΔHsol = +17 kJ mol⁻¹ (slightly endothermic)

Section 6 of 6Exam Checklist & Tips

1.8.4 – Key Points for the Exam

  • Enthalpy of solution Enthalpy change when one mole of solute dissolves in water to give an infinitely dilute solution.
  • Enthalpy of hydration Enthalpy change when one mole of gaseous ions dissolves in water to give an infinitely dilute solution.
  • Ion–dipole attraction Electrostatic attraction between an ion and the partial charge on a polar molecule.
  • Charge density Ionic charge divided by ionic radius, a measure of how concentrated the charge is.

Common Mistakes

  • Writing hydration for the solid instead of for gaseous ions.
  • Using the lattice formation value without changing its sign in the solution equation.
  • Saying hydration enthalpies can be positive; they are always negative.
  • Assuming a solid dissolves only if ΔHsol is negative; entropy matters too.
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