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1.5.4Dynamics

Kinetic Energy

5 min read 6 parts Lesson 19 of 22

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Section 1 of 6Energy of Motion

1.5.4 Kinetic Energy

A fast moving lorry has far more energy than a slow cyclist, and the equation shows exactly how much.

Definition
  • Kinetic energy is the energy a moving object has because of its motion.
Equation
  • Use Ek = ½ m v², with Ek in joules, m in kilograms and v in metres per second.
Mass
  • Doubling the mass doubles the kinetic energy at the same speed.
Speed
  • Doubling the speed quadruples the kinetic energy, because the speed is squared.

Section 2 of 6Why Speed Matters So Much

Why Speed Matters So Much
Squared
  • Because v is squared, small increases in speed give large increases in kinetic energy.
Stopping
  • The work done by brakes must equal the kinetic energy, so a faster car needs a longer stopping distance.
Safety
  • Speed limits reduce the kinetic energy which would be released in a crash.
Transfer
  • Kinetic energy is transferred to heat in brakes, and to sound and deformation in a collision.
Speed (m/s)Ek for 1000 kg car (J)
1050 000
20200 000
30450 000

Section 3 of 6Calculation Steps

1
Write the mass in kilograms and the speed in metres per second.
2
Square the speed first, before multiplying by the mass.
3
Multiply by one half and by the mass to find kinetic energy.
4
Quote the final answer in joules, with a sensible number of significant figures.
5
Rearrange for speed using v = √(2 Ek ÷ m) when the energy is known.

Section 4 of 6Everyday Contexts

Everyday Contexts
Cyclists
  • A cyclist and bike of total mass 80 kg at 10 m/s have 4000 J of kinetic energy.
Braking
  • Brakes must convert all this kinetic energy to heat, so doubling speed means four times as much energy to remove.
Cricket ball
  • A fast bowler gives a 0.16 kg ball a speed of 40 m/s, giving it 128 J of kinetic energy.
Wind turbines
  • Moving air has kinetic energy, and turbines transfer part of it into electrical energy.

Section 5 of 6Worked Example

Question

  • Calculate the kinetic energy of a 1200 kg car at 20 m/s.
  • A 0.20 kg ball has 90 J of kinetic energy;
    • find its speed.

  1. Ek = ½ m v² = 0.5 × 1200 × 20² = 0.5 × 1200 × 400 = 240 000 J.
  2. Rearrangev² = 2 Ek ÷ m = (2 × 90) ÷ 0.20 = 900.
  3. v = √900 = 30 m/s.

Answer 240 000 J (2.4 × 10⁵ J); 30 m/s.

Section 6 of 6Exam Checklist & Tips

1.5.4 – Key Points for the Exam

  • Kinetic energy Energy due to motion.
  • Joule The unit of energy.
  • Speed squared The speed multiplied by itself, v².
  • Stopping distance The distance a vehicle travels after the brakes are applied until it stops.

Common Mistakes

  • Forgetting to square the speed.
  • Squaring the whole expression including the one half.
  • Using the speed in km/h without converting to m/s.
  • Thinking doubling the speed doubles the kinetic energy.
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