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Lesson 1: Qualitative Analysis of Acidic Radicals (Anions)

Chemistry

Lesson 1: Qualitative Analysis of Acidic Radicals (Anions)

Overview

Overview

🌳 Concept tree

  1. Qualitative Analysis of Acidic Radicals (Anions)
  2. ├── Revision of concepts and laws needed in this chapter

├── Importance

├── Kinds of analysis

├── Qualitative analysis

├── A. Identification of acid radicals (anions)

│ ├── (1) Dilute hydrochloric acid group

│ ├── (2) Concentrated sulphuric acid group

│ └── (3) Barium chloride group

  • ├── Practical differentiation between pairs of salts (typical exam type)

└── Reasoning questions

Lesson 1: Qualitative Analysis of Acidic Radicals (Anions) · 1 / 13
Revision of concepts and laws needed in this chapter

Revision of concepts and laws needed in this chapter

Comparison aspectMain ideaKeywords
Mole
  • the amount of substance containing Avogadro’s number (6.02 × 1023) of particles (molecules
  • atoms
  • ions
  • formula units or electrons). Example: Al3+ + 3e− → Al — 3 moles of electrons are needed to reduce 1 mole of Al3+ to 1 mole of Al atoms
amountsubstancecontainingAvogadro
Molar mass (g/mol)= sum of the atomic masses of all atoms in the formulaatomicmassesatomsformula
Number of molesn = mass (g) / molar mass (g/mol)massmolar
Number of particles= n × 6.02 × 10231023
Volume of a gas at STP(L) = n × 22.4 L/mol
Gas density at STP(g/L) = molar mass / 22.4molarmass
MolarityM = n (mol) / V (L). Also n = M × V(mL) / 10001000
Mass percentage of an element in a compound= (mass of the element in one mole of compound / molar mass of the compound) × 100molemolar
Percentage of a compound in an impure sample= (mass of the compound / mass of the sample) × 100mass
Dilution
  • when water is added
  • the number of moles of solute does not change: M₁V₁ = M₂V₂
wateraddednumbermoles
Worked example 1.1.Percentage of sulphur in sodium sulphate Na₂SO₄ (Na = 23, S = 32, O = 16): M = 142 g/mol; %S = 32/142 × 100 = 22.5 %.
Worked example 1.2.Mass of NaOH needed for 250 mL of 0.1 M solution: n = 0.1 × 250/1000 = 0.025 mol; mass = 0.025 × 40 = 1.0 g.
Worked example 1.3.50 mL of 1 M HCl are diluted with water to 250 mL: M₂ = 1 × 50/250 = 0.2 M.
Lesson 1: Qualitative Analysis of Acidic Radicals (Anions) · 2 / 13
Importance

Importance

  • Chemical analysis is an important branch of chemistry that plays an important role in the progress of science and in many fields:
Comparison aspectMain ideaKeywords
Medicine
  • diagnosis depends on measuring sugar
  • albumin
  • urea and cholesterol
  • it makes the doctor’s diagnosis and treatment easier
  • and it gives the amount of active ingredient in medicines
diagnosisdependsmeasuringsugar
Agriculture
  • analysing soil (acidity or basicity
  • kinds and percentages of elements) tells
  • fertilizers to add and how to improve soil and crops
analysingsoilaciditybasicity
Industryores and products are analysed to check identity and compliance with standard specificationsoresproductsanalysedcheck
Environmente.g. measuring nitrogen oxides in air and pollutants in water. There are countless other examples based on studying the chemical composition of substancesmeasuringnitrogenoxidespollutants
Lesson 1: Qualitative Analysis of Acidic Radicals (Anions) · 3 / 13
Kinds of analysis

Kinds of analysis

  • When a substance is analysed we need to know which elements it contains, the percentage of each, and how they are combined (to write the molecular formula, or the compounds if it is a mixture).
  • Two kinds:
Comparison aspectMain ideaExampleKeywords
Qualitative analysisidentifies the constituents of a pure substance (a simple salt) or of a mixture of several substancesidentifiesconstituentspuresubstance
Quantitative analysis
  • estimates the percentage (amount) of each main component. It is carried out after the qualitative analysis
  • which tells us
  • method to choose
—estimatespercentageamountmain
  • Think of qualitative analysis as asking "what is present?" and quantitative analysis as asking "how much of it is present?".
Lesson 1: Qualitative Analysis of Acidic Radicals (Anions) · 4 / 13
Qualitative analysis

Qualitative analysis

  • A pure substance can be recognized from its physical constants (melting point, boiling point, molar mass).
  • For a mixture the components must first be separated and then identified.
  • Qualitative analysis is thus a series of well-chosen chemical reactions, each judged by an observable change (evolution of a gas, change of colour, formation of a precipitate).
Organic compoundsidentify the elements and the functional groups.
Inorganic compoundsidentify the ions — the acid radicals (anions) and basic radicals (cations) of the salt. We study only these ions.
Lesson 1: Qualitative Analysis of Acidic Radicals (Anions) · 5 / 13
A. Identification of acid radicals (anions)

A. Identification of acid radicals (anions)

  1. Anions are classified into three groups
  2. each with a reagent:
  1. Dilute hydrochloric acid group
  2. Concentrated sulphuric acid group
  3. Barium chloride group
Lesson 1: Qualitative Analysis of Acidic Radicals (Anions) · 6 / 13
(1) Dilute hydrochloric acid group

(1) Dilute hydrochloric acid group

Comparison aspectMain ideaKeywords
Anions
  • carbonate CO₃2−
  • bicarbonate HCO₃−
  • sulphite SO₃2−
  • sulphide S2−
  • thiosulphate S₂O₃2−
  • nitrite NO₂−
carbonateCO₃2bicarbonateHCO₃
PrincipleHCl is a more stable acid than the acids these anions come fromstableacidacidsthese
•
  • Those acids (H₂CO₃
  • H₂SO₃
  • H₂S
  • H₂S₂O₃
  • HNO₂) are unstable
  • they volatilize or decompose to gases that can be recognized with a suitable reagent
ThoseacidsH₂CO₃H₂SO₃
•Gentle heating helps to drive off the gasGentleheatinghelpsdrive
Main experimentsolid salt + dilute HClsolidsaltdilute
Anion Observation and gas Detection of the gas Confirmatory test
Carbonate
  • Effervescence
  • CO₂: Na₂CO₃ + 2HCl → 2NaCl + H₂O + CO₂
Turns lime water milky: CO₂ + Ca(OH)₂ → CaCO₃↓ + H₂O. (Excess CO₂ clears it: CaCO₃ + H₂O + CO₂ → Ca(HCO₃)₂ — so pass the gas only briefly.) Salt solution + MgSO₄ solution → white ppt. in the cold: Na₂CO₃ + MgSO₄ → Na₂SO₄ + MgCO₃↓; the ppt. dissolves in HCl: MgCO₃ + 2HCl → MgCl₂ + H₂O + CO₂
Bicarbonate
  • Effervescence
  • CO₂: NaHCO₃ + HCl → NaCl + H₂O + CO₂
Lime water turns milky Salt solution + MgSO₄ solution → no ppt. in the cold; a white ppt. appears on heating: 2NaHCO₃ + MgSO₄ → Na₂SO₄ + Mg(HCO₃)₂; Mg(HCO₃)₂ → MgCO₃↓ + CO₂ + H₂O
Sulphite Colourless gas SO₂ with a suffocating smell: Na₂SO₃ + 2HCl → 2NaCl + H₂O + SO₂ Paper wet with acidified potassium dichromate turns from orange to green: K₂Cr₂O₇ + 3SO₂ + H₂SO₄ → K₂SO₄ + Cr₂(SO₄)₃ + H₂O Salt solution + AgNO₃ → white ppt. Ag₂SO₃ that turns black on heating: Na₂SO₃ + 2AgNO₃ → Ag₂SO₃↓ + 2NaNO₃
Sulphide H₂S gas with a rotten-egg smell: Na₂S + 2HCl → 2NaCl + H₂S Paper wet with lead(II) acetate turns black: (CH₃COO)₂Pb + H₂S → PbS↓ + 2CH₃COOH Salt solution + AgNO₃ → black Ag₂S: Na₂S + 2AgNO₃ → Ag₂S↓ + 2NaNO₃
Thiosulphate SO₂ gas and a pale-yellow turbidity of sulphur: Na₂S₂O₃ + 2HCl → 2NaCl + H₂O + SO₂ + S↓ SO₂ detected as above Decolourizes brown iodine solution: 2Na₂S₂O₃ + I₂ → Na₂S₄O₆ (sodium tetrathionate) + 2NaI
Nitrite Brown fumes in the tube: NaNO₂ + HCl → NaCl + HNO₂; 3HNO₂ → HNO₃ + H₂O + 2NO; colourless NO turns reddish brown at the mouth of the tube: 2NO + O₂ → 2NO₂ — Salt solution + KMnO₄ acidified with H₂SO₄ → the violet colour is removed: 5NaNO₂ + 2KMnO₄ + 3H₂SO₄ → 5NaNO₃ + K₂SO₄ + 2MnSO₄ + 3H₂O
  • Notes:
  • All metal carbonates are insoluble in water except those of sodium, potassium and ammonium; all bicarbonates are soluble.
  • Dilute HCl cannot distinguish carbonate from bicarbonate (both give CO₂ that clouds lime water), so the MgSO₄ test is used: carbonate gives MgCO₃ at once, because MgCO₃ is insoluble; bicarbonate gives soluble Mg(HCO₃)₂, which decomposes on heating to precipitate MgCO₃.
  • The acidified dichromate test works because Cr₂O₇2− (orange) is reduced by SO₂ to Cr3+ (green). Acidified permanganate (violet) is likewise reduced to colourless Mn2+ by sulphite, sulphide or nitrite, so it is not specific for nitrite and is used as a confirmatory test after the HCl test.
  • Lead(II) acetate paper is used for H₂S because black PbS forms on it. Silver nitrate gives a black Ag₂S precipitate with sulphide.
Lesson 1: Qualitative Analysis of Acidic Radicals (Anions) · 7 / 13
(2) Concentrated sulphuric acid group

(2) Concentrated sulphuric acid group

Comparison aspectMain ideaKeywords
Anions
  • chloride Cl−
  • bromide Br−
  • iodide I−
  • nitrate NO₃−
chloridebromideiodidenitrate
Principle
  • concentrated (hot) H₂SO₄ is more stable (less volatile) than the acids of these anions
  • so it displaces them as volatile acids
  • which appear as gases and are detected with a suitable reagent
concentratedH₂SO₄stableless
Main experimentsolid salt + concsolidsaltconc
•
  • H₂SO₄
  • heat if needed
H₂SO₄heatneeded
Anion Gas and its detection Confirmatory test
Chloride Colourless HCl gas: 2NaCl + H₂SO₄ → Na₂SO₄ + 2HCl. Forms white fumes of NH₄Cl with a glass rod wet with NH₃: HCl + NH₃ → NH₄Cl Salt solution + AgNO₃ → white ppt. AgCl: NaCl + AgNO₃ → AgCl↓ + NaNO₃; turns violet in sunlight; dissolves in conc. ammonia solution: AgCl + 2NH₃ → [Ag(NH₃)₂]Cl
Bromide Colourless HBr, partly oxidized by conc. H₂SO₄ to orange-red bromine vapour (turns starch paper yellow): 2NaBr + H₂SO₄ → Na₂SO₄ + 2HBr; 2HBr + H₂SO₄ → 2H₂O + SO₂ + Br₂ AgNO₃ → pale-yellow (white-yellow) ppt. AgBr: NaBr + AgNO₃ → AgBr↓ + NaNO₃; darkens in sunlight; dissolves slowly/with difficulty in conc. ammonia
Iodide Colourless HI, which is oxidized more easily by conc. H₂SO₄ to violet iodine vapour (turns starch paper blue): 2NaI + H₂SO₄ → Na₂SO₄ + 2HI; 2HI + H₂SO₄ → 2H₂O + SO₂ + I₂ AgNO₃ → yellow ppt. AgI, insoluble in ammonia solution: NaI + AgNO₃ → AgI↓ + NaNO₃
Nitrate Reddish-brown NO₂ vapour from decomposition of the nitric acid formed: 2NaNO₃ + H₂SO₄ → Na₂SO₄ + 2HNO₃; 4HNO₃ → 4NO₂ + 2H₂O + O₂. Adding copper turnings increases the brown fumes: Cu + 4HNO₃ → Cu(NO₃)₂ + 2NO₂ + 2H₂O Brown-ring test: nitrate solution + freshly prepared iron(II) sulphate; conc. H₂SO₄ is poured carefully down the tube wall. A brown ring forms at the boundary between the acid and the solution: 6FeSO₄ + 2NaNO₃ + 4H₂SO₄ → 3Fe₂(SO₄)₃ + Na₂SO₄ + 2NO + 4H₂O; FeSO₄ + NO → [Fe(NO)]SO₄ (brown ring compound). The ring disappears on heating or shaking.
  1. The silver halides differ in colour and in solubility in ammonia
  2. which helps distinguish them: AgCl (white
  3. dissolves readily in dilute ammonia)
  4. AgBr (pale yellow
  5. dissolves with difficulty in concentrated ammonia)
  6. AgI (yellow
  7. does not dissolve).
Lesson 1: Qualitative Analysis of Acidic Radicals (Anions) · 8 / 13
(3) Barium chloride group

(3) Barium chloride group

  • Anions phosphate PO₄3− and sulphate SO₄2−.
  • These do not react with dilute HCl or conc.
  • H₂SO₄ to give gases; they are identified by precipitation reactions.
Anion BaCl₂ test Confirmatory test
Phosphate White ppt. of Ba₃(PO₄)₂, soluble in dil. HCl: 2Na₃PO₄ + 3BaCl₂ → Ba₃(PO₄)₂↓ + 6NaCl AgNO₃ → yellow ppt. Ag₃PO₄ soluble in both ammonia and nitric acid: Na₃PO₄ + 3AgNO₃ → Ag₃PO₄↓ + 3NaNO₃
Sulphate White ppt. of BaSO₄, insoluble in dil. HCl: Na₂SO₄ + BaCl₂ → BaSO₄↓ + 2NaCl Lead(II) acetate → white ppt. PbSO₄: Na₂SO₄ + (CH₃COO)₂Pb → PbSO₄↓ + 2CH₃COONa
Lesson 1: Qualitative Analysis of Acidic Radicals (Anions) · 9 / 13
Practical differentiation between pairs of salts (typical exam type)

Practical differentiation between pairs of salts (typical exam type)

Comparison aspectMain ideaKeywords
Sodium sulphite and sodium sulphate
  • add dilute HCl to each solid. Sulphite gives SO₂ (suffocating odour
  • turns acidified dichromate paper green)
  • sulphate gives no gas. Alternatively with BaCl₂ both give a white precipitate
  • but BaSO₃ dissolves in dilute HCl while BaSO₄ does not
dilutesolidgivessuffocating
Iron(II) chloride and iron(III) chloride
  • add NaOH to each solution. Fe2+ gives a white-green precipitate Fe(OH)₂ (which darkens in air)
  • Fe3+ gives a reddish-brown precipitate Fe(OH)₃: FeCl₂ + 2NaOH → Fe(OH)₂↓ + 2NaCl
  • FeCl₃ + 3NaOH → Fe(OH)₃↓ + 3NaCl
NaOHsolutiongiveswhite
Sodium chloride and aluminium chloride
  • add NaOH. NaCl gives no precipitate
  • AlCl₃ gives a white gelatinous precipitate that dissolves in excess NaOH: AlCl₃ + 3NaOH → Al(OH)₃↓ + 3NaCl
  • Al(OH)₃ + NaOH → NaAlO₂ + 2H₂O. (Silver nitrate cannot distinguish them
  • because both contain chloride and both give white AgCl.)
NaOHNaClgivesprecipitate
Sodium carbonate and sodium bicarbonate
  • add MgSO₄ solution in the cold: carbonate gives an immediate white precipitate
  • bicarbonate gives none until heated
MgSO₄solutioncoldgives
Sodium chloride and sodium bromide / iodide
  • add AgNO₃ and observe white / pale yellow / yellow precipitates
  • or add conc. H₂SO₄ and observe HCl fumes / orange-red bromine vapour / violet iodine vapour
AgNO₃observewhitepale
Lesson 1: Qualitative Analysis of Acidic Radicals (Anions) · 10 / 13
Reasoning questions

Reasoning questions

  • Why does adding NaOH gradually to aluminium chloride solution give a white precipitate which then disappears? Al(OH)₃ is amphoteric: it dissolves in excess alkali forming soluble sodium meta-aluminate NaAlO₂.
  • Why is dilute HCl not used to distinguish carbonate from bicarbonate? Both evolve CO₂ that turns lime water milky.
  • Why does acidified KMnO₄ lose its violet colour when nitrite is added? NO₂− is oxidized to NO₃− and MnO₄− is reduced to colourless Mn2+.
  • Why does lead acetate paper turn black in H₂S? Black lead(II) sulphide forms.
  • Why do violet vapours appear when conc. H₂SO₄ is added to an iodide? HI is oxidized by the acid to iodine, which vaporizes as violet vapour.
Lesson 1: Qualitative Analysis of Acidic Radicals (Anions) · 11 / 13
Part 12

Part 12

  • 📖

🔍 In-Depth Explanations, Deductions & Multi-Book Insights:

Chemistry Thanaweya Amma (2026/2027)

  • Lesson 1 – Qualitative Analysis of Acidic Radicals (Anions)
  • Detailed Academic Lesson Overview:
  • Qualitative analysis determines the chemical components of a substance.
  • Anions are classified into three analytical groups based on the volatility and strength of their corresponding parent acids: Dilute HCl Group, Concentrated H2SO4 Group, and Barium Chloride Group.

🌳 Hierarchy Classification & Conceptual Roadmap

Qualitative Analysis of Anions

├── 1. Dilute HCl Group (Less stable acids)

Comparison aspectMain ideaKeywords
│ ├── Carbonate (CO32−) & Bicarbonate (HCO3−)Evolve CO2 turning lime water turbidEvolveturninglimewater
│ ├── Sulfite (SO32−)Evolves SO2 turning K2Cr2O7 paper from orange to greenEvolvesturningK2Cr2O7paper
│ ├── Thiosulfate (S2O32−)Evolves SO2 with yellow colloidal sulfur suspensionEvolvesyellowcolloidalsulfur
│ ├── Sulfide (S2−)Evolves H2S turning lead acetate paper black (PbS)Evolvesturningleadacetate
│ └── Nitrite (NO2−)
  • Evolves NO in solution
  • turns reddish-brown NO2 at test tube mouth
Evolvessolutionturnsreddish
•├── 2. Conc. H2SO4 Group (Moderately stable acids)ConcH2SO4GroupModerately
│ ├── Chloride (Cl−)Evolves colorless HCl gas forming white fumes with ammonia (NH4Cl)Evolvescolorlessformingwhite
│ ├── Bromide (Br−)Evolves orange-red Br2 vapors turning starch paper yellowEvolvesorangevaporsturning
│ ├── Iodide (I−)Evolves violet I2 vapors turning starch paper blueEvolvesvioletvaporsturning
│ └── Nitrate (NO3−)
  • Evolves dense reddish-brown NO2 vapors
  • confirmed by Brown Ring test
Evolvesdensereddishbrown
•└── 3. Barium Chloride (BaCl2) Group (Most stable acids)BariumChlorideBaCl2Group
├── Sulfate (SO42−)White ppt of BaSO4 insoluble in dilute HClWhiteBaSO4insolubledilute
└── Phosphate (PO43−)White ppt of Ba3(PO4)2 soluble in dilute HClWhitesolubledilute
•📋 Master Teacher's Blackboard Rules & Exam SecretsMasterTeacherBlackboardRules
RULE 1The principle of anion detection: A more stable acid displaces a less stable acid from its salts in the form of a gas that can be identifiedprincipleaniondetectionstable
RULE 2
  • Confirmatory test for Sulfate vs. Phosphate: Both form a white precipitate with BaCl2
  • but Barium Sulfate is insoluble in dilute HCl
  • whereas Barium Phosphate is completely soluble
ConfirmatorytestSulfatePhosphate
RULE 3
  • Brown Ring Test for Nitrate: FeSO4 must be freshly prepared because it easily oxidizes to Fe2(SO4)3 in air
  • destroying the complex
BrownRingTestNitrate
📊 Detailed Comparison MatrixDiagnostic Silver Nitrate (AgNO3) Confirmatory MatrixDiagnosticSilverNitrateAgNO3
Anion Precipitate with AgNO3 Solubility in Aqueous Ammonia (NH4OH)
Chloride (Cl−) White ppt of AgCl (turns violet in light) Rapidly soluble in concentrated NH4OH
Bromide (Br−) Yellowish-white ppt of AgBr Slowly soluble in concentrated NH4OH
Iodide (I−) Bright yellow ppt of AgI Completely insoluble in NH4OH
Phosphate (PO43−) Bright yellow ppt of Ag3PO4 Rapidly soluble in NH4OH & dilute HNO3
Sulfide (S2−) Black ppt of Ag2S Insoluble in ammonia
Sulfite (SO32−) White ppt of Ag2SO3 (turns black on heating) Soluble in dilute acids
Lesson 1: Qualitative Analysis of Acidic Radicals (Anions) · 12 / 13
Detailed Comparison Matrix: Diagnostic Silver Nitrate (AgNO3) Confirmatory Matrix

Detailed Comparison Matrix: Diagnostic Silver Nitrate (AgNO3) Confirmatory Matrix

Anion Precipitate with AgNO3 Solubility in Aqueous Ammonia (NH4OH)
Chloride (Cl−) White ppt of AgCl (turns violet in light) Rapidly soluble in concentrated NH4OH
Bromide (Br−) Yellowish-white ppt of AgBr Slowly soluble in concentrated NH4OH
Iodide (I−) Bright yellow ppt of AgI Completely insoluble in NH4OH
Phosphate (PO43−) Bright yellow ppt of Ag3PO4 Rapidly soluble in NH4OH & dilute HNO3
Sulfide (S2−) Black ppt of Ag2S Insoluble in ammonia
Sulfite (SO32−) White ppt of Ag2SO3 (turns black on heating) Soluble in dilute acids
Lesson 1: Qualitative Analysis of Acidic Radicals (Anions) · 13 / 13