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Chapter 1 - Transition Elements and Iron Metallurgy

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Chapter 2 - Chemical Analysis

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Chapter 3 - Chemical Equilibrium

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Chapter 5 - Organic Chemistry

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Lesson 3 Quiz: Alkynes (Acetylene) and Cyclic Hydrocarbons

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1.
STEM Transition Elements Problem 38: Why are most compounds of transition metals in the first series colored and paramagnetic?
Because they possess completely filled 3d10 orbitals
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
Due to nuclear fission within the metal atom
Because of the total absence of electrons in the d-subshell
2.
STEM Chemical Equilibrium Problem 22: For the equilibrium reaction: N2(g) + 3 H2(g) 2 NH3(g) (ΔH = -92 kJ/mol), which change will shift the equilibrium to the right and increase ammonia yield?
Removing nitrogen gas continuously from the chamber
Decreasing temperature and increasing total pressure
Increasing temperature and decreasing pressure
Adding a positive catalyst at constant volume
3.
STEM Transition Elements Problem 34: Why are most compounds of transition metals in the first series colored and paramagnetic?
Due to nuclear fission within the metal atom
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
Because they possess completely filled 3d10 orbitals
Because of the total absence of electrons in the d-subshell
4.
STEM Transition Elements Problem 25: Why are most compounds of transition metals in the first series colored and paramagnetic?
Because of the total absence of electrons in the d-subshell
Due to nuclear fission within the metal atom
Because they possess completely filled 3d10 orbitals
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
5.
STEM Chemical Equilibrium Problem 3: For the equilibrium reaction: N2(g) + 3 H2(g) 2 NH3(g) (ΔH = -92 kJ/mol), which change will shift the equilibrium to the right and increase ammonia yield?
Adding a positive catalyst at constant volume
Removing nitrogen gas continuously from the chamber
Increasing temperature and decreasing pressure
Decreasing temperature and increasing total pressure
6.
STEM Transition Elements Problem 23: Why are most compounds of transition metals in the first series colored and paramagnetic?
Because they possess completely filled 3d10 orbitals
Because of the total absence of electrons in the d-subshell
Due to nuclear fission within the metal atom
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
7.
STEM Chemical Equilibrium Problem 31: For the equilibrium reaction: N2(g) + 3 H2(g) 2 NH3(g) (ΔH = -92 kJ/mol), which change will shift the equilibrium to the right and increase ammonia yield?
Decreasing temperature and increasing total pressure
Adding a positive catalyst at constant volume
Removing nitrogen gas continuously from the chamber
Increasing temperature and decreasing pressure
8.
STEM Chemical Equilibrium Problem 36: For the equilibrium reaction: N2(g) + 3 H2(g) 2 NH3(g) (ΔH = -92 kJ/mol), which change will shift the equilibrium to the right and increase ammonia yield?
Decreasing temperature and increasing total pressure
Removing nitrogen gas continuously from the chamber
Adding a positive catalyst at constant volume
Increasing temperature and decreasing pressure
9.
STEM Transition Elements Problem 11: Why are most compounds of transition metals in the first series colored and paramagnetic?
Because they possess completely filled 3d10 orbitals
Due to nuclear fission within the metal atom
Because of the total absence of electrons in the d-subshell
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
10.
STEM Transition Elements Problem 39: Why are most compounds of transition metals in the first series colored and paramagnetic?
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
Due to nuclear fission within the metal atom
Because of the total absence of electrons in the d-subshell
Because they possess completely filled 3d10 orbitals
11.
STEM Chemical Equilibrium Problem 1: For the equilibrium reaction: N2(g) + 3 H2(g) 2 NH3(g) (ΔH = -92 kJ/mol), which change will shift the equilibrium to the right and increase ammonia yield?
Increasing temperature and decreasing pressure
Decreasing temperature and increasing total pressure
Removing nitrogen gas continuously from the chamber
Adding a positive catalyst at constant volume
12.
STEM Chemical Equilibrium Problem 5: For the equilibrium reaction: N2(g) + 3 H2(g) 2 NH3(g) (ΔH = -92 kJ/mol), which change will shift the equilibrium to the right and increase ammonia yield?
Adding a positive catalyst at constant volume
Removing nitrogen gas continuously from the chamber
Decreasing temperature and increasing total pressure
Increasing temperature and decreasing pressure
13.
STEM Chemical Equilibrium Problem 20: For the equilibrium reaction: N2(g) + 3 H2(g) 2 NH3(g) (ΔH = -92 kJ/mol), which change will shift the equilibrium to the right and increase ammonia yield?
Decreasing temperature and increasing total pressure
Adding a positive catalyst at constant volume
Increasing temperature and decreasing pressure
Removing nitrogen gas continuously from the chamber
14.
STEM Chemical Equilibrium Problem 29: For the equilibrium reaction: N2(g) + 3 H2(g) 2 NH3(g) (ΔH = -92 kJ/mol), which change will shift the equilibrium to the right and increase ammonia yield?
Adding a positive catalyst at constant volume
Removing nitrogen gas continuously from the chamber
Increasing temperature and decreasing pressure
Decreasing temperature and increasing total pressure
15.
STEM Transition Elements Problem 40: Why are most compounds of transition metals in the first series colored and paramagnetic?
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
Because of the total absence of electrons in the d-subshell
Because they possess completely filled 3d10 orbitals
Due to nuclear fission within the metal atom
16.
STEM Transition Elements Problem 41: Why are most compounds of transition metals in the first series colored and paramagnetic?
Because they possess completely filled 3d10 orbitals
Because of the total absence of electrons in the d-subshell
Due to nuclear fission within the metal atom
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
17.
STEM Chemical Equilibrium Problem 11: For the equilibrium reaction: N2(g) + 3 H2(g) 2 NH3(g) (ΔH = -92 kJ/mol), which change will shift the equilibrium to the right and increase ammonia yield?
Increasing temperature and decreasing pressure
Removing nitrogen gas continuously from the chamber
Decreasing temperature and increasing total pressure
Adding a positive catalyst at constant volume
18.
STEM Transition Elements Problem 30: Why are most compounds of transition metals in the first series colored and paramagnetic?
Because they possess completely filled 3d10 orbitals
Because of the total absence of electrons in the d-subshell
Due to nuclear fission within the metal atom
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
19.
STEM Transition Elements Problem 18: Why are most compounds of transition metals in the first series colored and paramagnetic?
Because of the total absence of electrons in the d-subshell
Due to nuclear fission within the metal atom
Because they possess completely filled 3d10 orbitals
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
20.
STEM Chemical Equilibrium Problem 37: For the equilibrium reaction: N2(g) + 3 H2(g) 2 NH3(g) (ΔH = -92 kJ/mol), which change will shift the equilibrium to the right and increase ammonia yield?
Adding a positive catalyst at constant volume
Increasing temperature and decreasing pressure
Decreasing temperature and increasing total pressure
Removing nitrogen gas continuously from the chamber
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