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Chapter 1 - Transition Elements and Iron Metallurgy

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Lesson 4 Quiz: Iron Chemical Properties, Reactions and Oxides

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1.
STEM Chemistry Problem 15: A 25.0 mL sample of 0.10 M H2SO4 is completely neutralized by 0.20 M NaOH. What volume of NaOH solution is required to reach the equivalence point?
10.0 mL of NaOH
25.0 mL of NaOH
50.0 mL of NaOH
12.5 mL of NaOH
2.
STEM Transition Elements Problem 22: Why are most compounds of transition metals in the first series colored and paramagnetic?
Due to nuclear fission within the metal atom
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
Because they possess completely filled 3d10 orbitals
Because of the total absence of electrons in the d-subshell
3.
STEM Faradaic Problem 24: What mass of copper (atomic mass = 63.5 g/mol) is deposited at the cathode when a constant current of 9.65 A passes through a CuSO4 solution for 1,000 seconds? (Faraday constant = 96,500 C/mol)
6.35 g of Cu
12.70 g of Cu
1.587 g of Cu
3.175 g of Cu
4.
STEM Chemistry Problem 38: A 25.0 mL sample of 0.10 M H2SO4 is completely neutralized by 0.20 M NaOH. What volume of NaOH solution is required to reach the equivalence point?
12.5 mL of NaOH
10.0 mL of NaOH
25.0 mL of NaOH
50.0 mL of NaOH
5.
STEM Transition Elements Problem 18: Why are most compounds of transition metals in the first series colored and paramagnetic?
Due to nuclear fission within the metal atom
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
Because they possess completely filled 3d10 orbitals
Because of the total absence of electrons in the d-subshell
6.
STEM Chemistry Problem 19: A 25.0 mL sample of 0.10 M H2SO4 is completely neutralized by 0.20 M NaOH. What volume of NaOH solution is required to reach the equivalence point?
50.0 mL of NaOH
12.5 mL of NaOH
10.0 mL of NaOH
25.0 mL of NaOH
7.
STEM Transition Elements Problem 44: Why are most compounds of transition metals in the first series colored and paramagnetic?
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
Because of the total absence of electrons in the d-subshell
Because they possess completely filled 3d10 orbitals
Due to nuclear fission within the metal atom
8.
STEM Transition Elements Problem 24: Why are most compounds of transition metals in the first series colored and paramagnetic?
Because of the total absence of electrons in the d-subshell
Due to nuclear fission within the metal atom
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
Because they possess completely filled 3d10 orbitals
9.
What is the exact chemical deduction according to Egyptian curriculum standards for: Electronic Configuration of the First Transition Series?
Chromium (Cr: 24) has an anomalous configuration [Ar] 4s1 3d5 to achieve half-filled d-subshell stability, and Copper (Cu: 29) is [Ar] 4s1 3d10 for completely filled d-subshell stability
Zinc (Zn: 30) is considered a typical transition element in all its compounds
Scandium (Sc: 21) exhibits stable oxidation states of +1, +2, and +3
Both Chromium and Copper have fully filled 4s2 orbitals
10.
STEM Faradaic Problem 11: What mass of copper (atomic mass = 63.5 g/mol) is deposited at the cathode when a constant current of 9.65 A passes through a CuSO4 solution for 1,000 seconds? (Faraday constant = 96,500 C/mol)
12.70 g of Cu
3.175 g of Cu
6.35 g of Cu
1.587 g of Cu
11.
STEM Transition Elements Problem 37: Why are most compounds of transition metals in the first series colored and paramagnetic?
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
Because they possess completely filled 3d10 orbitals
Because of the total absence of electrons in the d-subshell
Due to nuclear fission within the metal atom
12.
STEM Chemistry Problem 10: A 25.0 mL sample of 0.10 M H2SO4 is completely neutralized by 0.20 M NaOH. What volume of NaOH solution is required to reach the equivalence point?
25.0 mL of NaOH
12.5 mL of NaOH
50.0 mL of NaOH
10.0 mL of NaOH
13.
STEM Faradaic Problem 30: What mass of copper (atomic mass = 63.5 g/mol) is deposited at the cathode when a constant current of 9.65 A passes through a CuSO4 solution for 1,000 seconds? (Faraday constant = 96,500 C/mol)
6.35 g of Cu
12.70 g of Cu
1.587 g of Cu
3.175 g of Cu
14.
STEM Chemistry Problem 9: A 25.0 mL sample of 0.10 M H2SO4 is completely neutralized by 0.20 M NaOH. What volume of NaOH solution is required to reach the equivalence point?
25.0 mL of NaOH
12.5 mL of NaOH
10.0 mL of NaOH
50.0 mL of NaOH
15.
STEM Faradaic Problem 44: What mass of copper (atomic mass = 63.5 g/mol) is deposited at the cathode when a constant current of 9.65 A passes through a CuSO4 solution for 1,000 seconds? (Faraday constant = 96,500 C/mol)
6.35 g of Cu
12.70 g of Cu
3.175 g of Cu
1.587 g of Cu
16.
STEM Chemistry Problem 34: A 25.0 mL sample of 0.10 M H2SO4 is completely neutralized by 0.20 M NaOH. What volume of NaOH solution is required to reach the equivalence point?
25.0 mL of NaOH
10.0 mL of NaOH
12.5 mL of NaOH
50.0 mL of NaOH
17.
STEM Transition Elements Problem 6: Why are most compounds of transition metals in the first series colored and paramagnetic?
Because of the total absence of electrons in the d-subshell
Due to nuclear fission within the metal atom
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
Because they possess completely filled 3d10 orbitals
18.
STEM Chemistry Problem 23: A 25.0 mL sample of 0.10 M H2SO4 is completely neutralized by 0.20 M NaOH. What volume of NaOH solution is required to reach the equivalence point?
25.0 mL of NaOH
50.0 mL of NaOH
12.5 mL of NaOH
10.0 mL of NaOH
19.
STEM Transition Elements Problem 2: Why are most compounds of transition metals in the first series colored and paramagnetic?
Because of the total absence of electrons in the d-subshell
Because they possess completely filled 3d10 orbitals
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
Due to nuclear fission within the metal atom
20.
STEM Faradaic Problem 7: What mass of copper (atomic mass = 63.5 g/mol) is deposited at the cathode when a constant current of 9.65 A passes through a CuSO4 solution for 1,000 seconds? (Faraday constant = 96,500 C/mol)
6.35 g of Cu
1.587 g of Cu
12.70 g of Cu
3.175 g of Cu
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