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Integrated Science

Unit 2

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Lesson 1: Speed, Uniform Acceleration and Laws of Motion

Integrated Science

Lesson 1: Speed, Uniform Acceleration and Laws of Motion

Overview

Overview

  • The concept of force and how it is measured.
  • Newton’s first law and the phenomenon of inertia.
  • Momentum.
  • Newton’s second law (F = ma; force as the rate of change of momentum); the newton.
  • Explaining everyday phenomena (collisions, airbags, falling on different surfaces).
  • Newton’s third law (action and reaction) and its applications.
  • The meaning of motion, and its types (translational and periodic).
  • Speed and velocity; uniform and variable velocity; instantaneous and average velocity.
  • Drawing and reading the displacement–time graph.
  • Acceleration and its types (positive, zero, negative); drawing and reading the velocity–time graph.
  • Analysing motion diagrams and graphs of motion in a straight line.

🌳 Concept tree

  1. Speed, Uniform Acceleration and Laws of Motion
  2. ├── Why study motion?

├── Definition of motion

├── Types of motion

├── Why we need velocity

├── Speed and velocity

├── Converting units

├── Worked examples

├── Uniform and non-uniform (variable) velocity

├── Instantaneous and average velocity

├── Worked examples

├── How to draw it

├── Reading the displacement–time graph

├── Worked examples

├── Definition

├── A motion diagram→the car that gains 5 m/s every second

├── Types of acceleration

├── Worked examples

├── Reading the graph

├── Analysing a multi-stage graph

├── Extension — displacement from the v–t graph

├── Motion (dot) diagrams

├── More worked examples

  • ├── Short answers to typical discussion questions

├── Summary

├── Introduction

  • ├── What is force?

├── Resultant force

├── Observation and the old belief

├── Statement of the law

├── Consequences of the first law

├── Inertia

├── Momentum

├── Statement

├── Another statement of the law

├── Definition of the newton

├── Thinking exercise

├── Worked examples

  • ├── Life applications of the second law (force, time and change of momentum)
  • ├── The first law as a special case of the second

├── Observations

├── Statement

├── Properties of action and reaction

├── Applications

├── Worked examples

  • ├── Short answers to typical discussion questions

└── Summary

Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 1 / 49
Why study motion?

Why study motion?

  • Look around you some things are at rest and others are moving.
  • Ships, trains and aeroplanes can only run on a safe timetable if we can describe and analyse their motion.
  • Departure and arrival times follow from their speeds.
  • In this chapter we learn the concepts and quantities needed to describe motion; in the next chapter we study what causes motion (forces).
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 2 / 49
Definition of motion

Definition of motion

  • Motion is the change in the position of an object with time, relative to the position of another object (a reference).
  • Two points to notice:
  1. Motion is relative. A passenger sitting in a train is at rest relative to the train but moving relative to the platform. Whenever you say an object moves, you must say relative to what.
  2. If the position of an object does not change over a period of time, it is at rest.
  • When the object moves along a straight path, we call it motion in a straight line.
  • It is the simplest type of motion.
  • Example a train on a long straight stretch of railway track.
  • (Think if you look at a film strip showing the positions of a mouse at equal time intervals, the mouse is moving if its position relative to the background is different in the successive pictures.)
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 3 / 49
Types of motion

Types of motion

  • Motion can be classified into two main types:
Comparison aspectMain ideaExampleKeywords
Translational motion
  • motion that has a starting point and an end point. Examples: motion in a straight line
  • projectile motion (a thrown ball)
  • the motion of a car
  • train
  • ship or aeroplane
—startingpointExamplesstraight
Periodic motion
  • motion that repeats itself at equal intervals of time. Examples: circular motion (a point on a wheel)
  • vibrational (oscillating) motion
a swinging pendulum or a vibrating tuning-fork prongrepeatsitselfequalintervals
  • Practice classification
Motion Type
Pendulum of a clock periodic (vibrational)
A projectile translational
A train going from Cairo to Aswan translational
Prong of a sounding tuning fork periodic (vibrational)
The Earth’s revolution around the Sun periodic (circular)
  • Our study in this unit concentrates on force and motion and their life applications; it prepares the way for the mathematical proof of laws in mathematics and applied mathematics.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 4 / 49
Why we need velocity

Why we need velocity

  • We often say "fast" or "slow", but these words are not scientific.
  • To describe motion exactly we need a quantity — velocity (and speed).
  • Velocity
  • is the displacement covered by the object in one second, or the rate of change of displacement with time.
  • Its units m/s (SI) or km/h.

velocity v = displacement ÷ time = Δd / Δt

  • Here Δd (the change in position) is the displacement and Δt is the time taken.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 5 / 49
Speed and velocity

Speed and velocity

  • In a car, the speedometer in front of the driver shows, for example, "80 km/h".
  • It tells us how fast the car moves but nothing about its direction.
  • This quantity is called speed.
  • To describe the motion completely we need the direction too, for example "80 km/h toward the east" — this is velocity.
Point Speed Velocity
Definition distance covered per unit time displacement per unit time
Type of quantity scalar (magnitude only) vector (magnitude and direction)
Sign always positive
  • positive in one direction
  • negative in the opposite direction
  • So the speedometer measures speed, not velocity, because it does not give the direction of travel.
  • Note in the problems of this book, when we say "velocity" we use it as the quantity that gives the complete description of the motion; for straight-line motion the direction is just a plus or minus sign.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 6 / 49
Converting units

Converting units

  • 1 km/h = 1000 m / 3600 s = 5/18 m/s.
  • So multiply km/h by 5/18 to get m/s; multiply m/s by 18/5 (= 3.6) to get km/h.
  • Examples:
  • 36 km/h = 36 × 5/18 = 10 m/s.
  • 25 m/s = 25 × 3.6 = 90 km/h.
  • Convert a speed to m/s before you use it in a formula that uses seconds.
  • A common mistake is to put a value in km/h straight into the formula.
  • Multiply the km/h value by 5/18 to get m/s.
  • For example, 90 km/h becomes 90 x 5/18 = 25 m/s.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 7 / 49
Worked examples

Worked examples

Comparison aspectMain ideaKeywords
Example 1.A cyclist covers 450 m in 90 s along a straight road. Find the velocity in m/s and in km/hcyclistcoversalongstraight
v = Δd/Δt = 450/90 = 5 m/s; in km/h5 × 3.6 = 18 km/h
Example 2.A train moves at a velocity of 72 km/h. How far does it go in 25 min if the velocity is uniform?trainmovesvelocitydoes
•
  • 72 km/h = 20 m/s
  • t = 25 × 60 = 1500 s
  • Δd = vΔt = 20 × 1500 = 30 000 m = 30 km
1500
(Or in km/h72 × 25/60 = 30 km.)
Example 3.An athlete runs 6000 m in 40 min along a straight track. The average velocity is 6000/(40 × 60) = 2.5 m/s = 9 km/h. If he keeps this average velocity he covers 2.5 × 3600 = 9000 m in one hourathleteruns6000along
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 8 / 49
Uniform and non-uniform (variable) velocity

Uniform and non-uniform (variable) velocity

  • Imagine a runner photographed at equal time intervals (for example every second).
Comparison aspectMain ideaKeywords
Uniform velocity
  • the object covers equal displacements in equal intervals of time. Its velocity has a constant magnitude and a constant direction (a straight line). In the picture
  • the positions are equally spaced
objectcoversequaldisplacements
Non-uniform (variable) velocity
  • the object covers unequal displacements in equal intervals of time. The velocity changes in magnitude
  • or in direction
  • or both. The positions in the picture are unequally spaced
objectcoversunequaldisplacements
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 9 / 49
Instantaneous and average velocity

Instantaneous and average velocity

  • In real journeys a car does not keep a fixed velocity it speeds up, slows down, or stops at lights.
  • To describe such motion we use two quantities.
  • Instantaneous velocity (v)
  • — the velocity of the body at a certain moment.
  • It can be read from the speedometer at that moment (as a speed).
  • On a displacement–time graph it is the slope of the tangent to the curve at the point corresponding to that moment.
  • Average velocity (v̄) the total displacement from the starting point to the end point divided by the total time:
  • v̄ = (final position − initial position) / total time = Δd / Δt
  • On a displacement–time graph it is the slope of the straight line (chord) joining the starting point and the end point.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 10 / 49
Worked examples

Worked examples

  • Example 1 — average velocity of a two-part trip. A bus travels 120 km east in 1.5 h and then 60 km east in 0.5 h. Total displacement = 180 km; total time = 2.0 h.
  • v̄ = 180/2 = 90 km/h east. (This is neither 80 km/h nor 120 km/h: do not average the two part-velocities, 80 and 120, unless the times are equal.)

✍️ Worked examples

  • Example 2 — return trip. A student walks 600 m east in 5 min and then 600 m back west in 5 min.
  • Displacement = 0 → average velocity = 0.
  • Distance = 1200 m, so average speed = 1200/600 s = 2 m/s.
    This shows that speed and velocity are different quantities.
  • Example 3 — how long? A car moves with an average velocity of 15 m/s. How long does it take to cover 4.5 km? t = 4500/15 = 300 s = 5 min.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 11 / 49
How to draw it

How to draw it

  • Watch a moving object and record its displacement at different times. Then:
  1. Mark the time on the horizontal axis and the displacement on the vertical axis (with a suitable scale).
  2. For each time, draw a vertical line from the time axis and a horizontal line from the displacement axis; their crossing point is one data point.
  3. Repeat for all the readings.
  4. Draw the best straight line (or smooth curve) passing near the points.
  5. Find the velocity as the slope of the line.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 12 / 49
Reading the displacement–time graph

Reading the displacement–time graph

  • slope = Δ(displacement) / Δ(time) = velocity
Shape of the graph Meaning
Straight line sloping upward uniform velocity (positive)
Steeper straight line greater velocity
Horizontal line displacement does not change → the object is at rest (velocity = 0)
Straight line sloping downward uniform velocity in the negative direction (moving back)
Curve
  • variable velocity
  • the slope changes from point to point
Slope of a tangent at a point instantaneous velocity at that moment
Slope of the chord joining two points average velocity between those two moments
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 13 / 49
Worked examples

Worked examples

Comparison aspectMain ideaKeywords
Example 1.
  • A straight line on a displacement–time graph passes through (t = 2 s
  • d = 10 m) and (t = 8 s
  • d = 40 m). Velocity = slope = (40 − 10)/(8 − 2) = 30/6 = 5 m/s
straightlinedisplacementtime
Example 2.
  • A curved d–t graph: at t = 1 s the object is at 1 m and at t = 5 s it is at 25 m. The average velocity between these moments is (25 − 1)/(5 − 1) = 6 m/s. The instantaneous velocity at t = 3 s needs a tangent drawn at t = 3 s
  • if the tangent rises 12 m in 2 s
  • the instantaneous velocity is 6 m/s
curvedgraphobjectaverage
Example 3 (graph in words).
  • A walker moves from the origin for 10 s
  • rising to 20 m
  • then the graph is horizontal for 5 s
  • then it goes back down to 0 at t = 25 s. Velocities: first stage 20/10 = +2 m/s
  • second stage 0 (rest)
  • third stage (0 − 20)/10 = −2 m/s (returning). The total displacement at the end is zero
  • though the distance covered is 40 m
walkermovesoriginrising
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 14 / 49
Definition

Definition

  • We have seen that velocity can change in magnitude, direction or both.
  • Motion in which velocity changes with time is called accelerated motion.
  • The physical quantity that expresses the change of velocity with time is acceleration (a).
  • Examples of change of velocity:
  1. at the beginning of a journey the velocity increases;
  2. on a curve the direction of the velocity changes;
  3. at the end the velocity decreases until the vehicle stops.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 15 / 49
A motion diagram: the car that gains 5 m/s every second

A motion diagram: the car that gains 5 m/s every second

  • A car starting from rest has the following speedometer readings:
time (s) 0 1 2 3 4
velocity (m/s) 0 5 10 15 20
  • The velocity increases by 5 m/s every second — a constant rate. This rate is the acceleration:

a = Δv / Δt = (v₂ − v₁) / (t₂ − t₁)

Check with the table→between t = 1 s and t = 2 s, a = (10 − 5)/(2 − 1) = 5 m/s2.

Acceleration

  • is the change in the velocity of the body per unit time, i.e.
  • the time rate of change of velocity.
  • Unit m/s2 (SI) or km/h2.
  • It is a vector quantity.
  • Its dimensional formula is LT−2.
  • Meaning of "5 m/s2" every second the velocity changes by 5 m/s.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 16 / 49
Types of acceleration

Types of acceleration

  • Take the direction of the velocity as the positive direction.
  • A small ball rolling on a smooth surface with different slopes shows all three cases:
Positive acceleration(velocity increases): e.g. the ball rolling down an inclined plane.
Zero acceleration(velocity constant): e.g. the ball rolling on a smooth horizontal surface. The change in velocity is zero.
Negative acceleration(velocity decreases — often called deceleration or retardation): e.g. the ball rolling up an inclined plane.
General rule about signs→(very important):
  • If velocity and acceleration have the same direction (same sign), the object speeds up — even if both are negative.
  • If they have opposite directions (opposite signs), the object slows down.
  • If acceleration = 0, the velocity is constant. It is not necessarily zero (e.g. a car at a steady 20 m/s has zero acceleration).
  • Life application.
  • Inside every car there are three controls that change the velocity: the accelerator (gas) pedal increases the magnitude, the brake pedal decreases it, and the steering wheel changes its direction.
  • Each of them produces an acceleration.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 17 / 49
Worked examples

Worked examples

Example 1.A car increases its velocity uniformly from 10 m/s to 30 m/s in 8 s. a = (30 − 10)/8 = +2.5 m/s2.
Example 2 — braking.A car moving at 25 m/s brakes uniformly and its velocity falls to 5 m/s in 4 s. a = (5 − 25)/4 = −5 m/s2 (deceleration of 5 m/s2).
Example 3 — time to reach a velocity.A motorcycle starts from rest with a = 3 m/s2. Time to reach 90 km/h (= 25 m/s)? From a = Δv/Δt: t = 25/3 = 8.3 s.

✍️ Worked examples

Example 4 — a ball thrown up (sign meaning).→Take upward as positive: a ball leaves the hand at +20 m/s and, because it slows down, has a negative acceleration (−10 m/s2); after 1 s the velocity is +10 m/s, after 2 s it is 0, and after 3 s it is −10 m/s (moving down, now speeding up because velocity and acceleration are both negative).
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 18 / 49
Reading the graph

Reading the graph

  • Plot time on the horizontal axis and velocity on the vertical axis.
  • For the car in the table of Lesson 5 the graph is a straight line through the origin, which means that the velocity increases at a uniform rate, i.e.
  • uniform acceleration .
  • The slope of the velocity–time graph = acceleration.
Shape of the v–t graph Meaning
Horizontal line (above the axis) constant velocity → a = 0 (uniform velocity)
Horizontal line on the time axis (v = 0) at rest
Straight line sloping upward uniform positive acceleration
Straight line sloping downward uniform negative acceleration (deceleration)
Steeper line larger magnitude of acceleration
Curved line non-uniform acceleration
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 19 / 49
Analysing a multi-stage graph

Analysing a multi-stage graph

  • A car moves in a straight line, and its velocity is recorded for 30 s.
  • Suppose the graph is: A(0 s, 0) → B(10 s, 25 m/s) → C(20 s, 25 m/s) → D(30 s, 0).
  • Analyse each stage:
Stage AB BC CD
Initial velocity vᵢ 0 25 m/s 25 m/s
Final velocity vf 25 m/s 25 m/s 0
Change Δv +25 m/s 0 −25 m/s
Duration 10 s 10 s 10 s
Acceleration a = Δv/t +2.5 m/s2 0 −2.5 m/s2
Description speeding up uniformly constant velocity slowing down uniformly to rest (braking)
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 20 / 49
Extension — displacement from the v–t graph

Extension — displacement from the v–t graph

  • (Not stated in the book text, but needed for graph questions like "find the total distance covered".)
    The area between the v–t graph and the time axis equals the displacement (distance for motion in one direction).
  • For the graph above:
Comparison aspectMain ideaKeywords
AB½ × 10 × 25 = 125 m
BC10 × 25 = 250 m
CD½ × 10 × 25 = 125 m
•
  • Total distance = 500 m
  • average velocity = 500/30 = 16.7 m/s
Totaldistanceaveragevelocity
•
  • For constant acceleration
  • the following results (all follow from the straight-line graph) are useful
constantaccelerationfollowingresults
  1. v = u + at (this is just the definition of acceleration
  2. a = (v − u)/t),

s = ½(u + v)t (area of a trapezoid),

  • s = ut + ½at2, v2 = u2 + 2as.
  • Example. A car starts from rest and accelerates at 2 m/s2 for 10 s. Then v = 0 + 2 × 10 = 20 m/s and the distance s = ½ × 2 × 102 = 100 m (check: area of the triangle ½ × 10 × 20 = 100 m).
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 21 / 49
Motion (dot) diagrams

Motion (dot) diagrams

  • A motion diagram shows the positions of an object at equal time intervals as dots.
  • Equal spacing between dots → uniform velocity.
  • Spacing that increases → speeding up (positive acceleration).
  • Spacing that decreases → slowing down (negative acceleration).
    Each of these corresponds to a graph: equal spacing ↔ horizontal v–t line (straight d–t line); increasing spacing ↔ rising v–t line (upward-curving d–t line); decreasing spacing ↔ falling v–t line (flattening d–t curve).
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 22 / 49
More worked examples

More worked examples

Comparison aspectMain ideaKeywords
Example 1.
  • From a v–t graph
  • the line passes through (2 s
  • 6 m/s) and (6 s
  • 18 m/s). a = (18 − 6)/(6 − 2) = 3 m/s2
graphlinepassesthrough
Example 2.A train slows from 30 m/s to 10 m/s in 20 s. a = (10 − 30)/20 = −1 m/s2. Its v–t line slopes downward with slope −1trainslowslineslopes
Example 3 (both quantities negative).
  • A cart moves to the left (negative) with velocity −4 m/s and has acceleration −2 m/s2 (also to the left). After 3 s: v = −4 + (−2)(3) = −10 m/s. The speed has increased from 4 to 10 m/s
  • because velocity and acceleration have the same sign
cartmovesleftvelocity
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 23 / 49
Short answers to typical discussion questions

Short answers to typical discussion questions

Comparison aspectMain ideaKeywords
•
  • A ball rolls on the floor
  • slows down and stops — do the velocity and the acceleration have the same sign? No. The velocity is in the direction of motion (say +)
  • the acceleration is opposite (−) because the velocity decreases (friction slows the ball)
ballrollsfloorslows
If an object’s acceleration is zero, is its velocity zero?
  • No. Zero acceleration means constant velocity. Example: a car travelling steadily at 60 km/h on a straight
  • level road has a = 0 but v ≠ 0
meansconstantExampletravelling
Why does the average velocity differ from the instantaneous velocity?
  • The average is the overall displacement ÷ total time
  • the instantaneous is the value at one moment
overalldisplacementtotaltime
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 24 / 49
Summary

Summary

  • Motion = change of position with time relative to another object; types: translational and periodic.
  • Velocity v = Δd/Δt (vector, m/s); speed is the scalar magnitude. 1 km/h = 5/18 m/s.
  • Uniform velocity equal displacements in equal times; variable velocity: unequal.
  • Instantaneous velocity = slope of tangent on d–t; average velocity = total displacement/total time = slope of chord.
  • Acceleration a = Δv/Δt (m/s2, LT−2); positive, zero or negative; same signs → speeding up; opposite signs → slowing down.
  • d–t graph slope = velocity; v–t graph slope = acceleration (area = displacement).
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 25 / 49
Introduction

Introduction

  • In the previous chapter we described motion by speed, velocity and acceleration, without asking why things move.
  • In this chapter we ask what produces acceleration.
  • The answer is force.
  • Newton’s three laws of motion, which we study here, are among the most important laws in physics.
  • Before the seventeenth century no organised theory of motion existed, although many ancient philosophers had tried to explain it.
  • The greatest credit for founding it goes to two scientists Galileo and Newton.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 26 / 49
What is force?

What is force?

"Force" is a word we use every dayyour muscles pull a bag, a car engine starts the car moving, a brake stops it.
Forceis an external influence acting on an object that changes, or tries to change, its state of motion (its velocity in magnitude or direction).
  • Force is a vector quantity (it has magnitude and direction).
  • It is measured by a spring balance (spring scale).
  • Its SI unit is the newton (N).
  • "Tries to change" if you push a heavy wall and it does not move, your push is still a force, but another force (the reaction of the floor/friction) balances it.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 27 / 49
Resultant force

Resultant force

  • Often several forces act on one body.
  • Their vector sum is the resultant (net) force, written ΣF (read "sigma F").
  • Forces in the same line are added with signs (+ in one direction, − in the opposite one).
  • Example 1. A box on the floor is pulled to the right by 30 N and to the left by 10 N (friction). ΣF = 30 − 10 = 20 N to the right.
  • Example 2. The same box is pulled by 30 N to the right and 30 N to the left. ΣF = 0: the forces are balanced and the box keeps its state of motion.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 28 / 49
Observation and the old belief

Observation and the old belief

  • Imagine returning home after a long trip everything is as you left it.
  • This simple fact, "things stay as they are unless something changes them", is the basis of Newton’s first law.
  • Everyday experience seems to contradict it if you push a box on the floor, it slides some distance, slows down and stops.
  • Ancient thinkers concluded that rest is the natural state of matter and that every motion dies away.
  • Experiments showed that this is wrong the box stops because of friction, a force opposing its sliding.
  • If friction did not exist (as on very smooth ice, or in space) the box would go on moving for ever without stopping.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 29 / 49
Statement of the law

Statement of the law

  • Newton’s first law of motion An object remains at rest, or moves with constant velocity in a straight line, unless a resultant force acts on it and changes this state.
  • Mathematical form ΣF = 0 (the object keeps its state)
  • where ΣF is the resultant of all forces acting on it.
  • Several forces may act, but if they cancel each other the resultant is zero.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 30 / 49
Consequences of the first law

Consequences of the first law

Comparison aspectMain ideaKeywords
If ΣF = 0, then a = 0
  • the velocity does not change
  • whether the object is at rest or moving
velocitydoeschangewhether
•
  • A force is needed to start a stationary object moving or to stop a moving one (that is
  • to change its velocity)
forceneededstartstationary
No force is needed to keep an object moving at constant velocity(only to cancel friction/air resistance). A car moving steadily on a straight road has an engine force that exactly balances the resistances: ΣF = 0cancelfrictionresistancesteadily
Example 1.
  • A car moves at a steady 25 m/s along a straight road. The engine force is 900 N forward. What is the resistance to motion? Since the velocity is constant
  • ΣF = 0
  • so the resistance is 900 N backward
movessteadyalongstraight
Example 2.→A book rests on a table: its weight (downward) is balanced by the table’s upward force; ΣF = 0, so it remains at rest.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 31 / 49
Inertia

Inertia

  • Newton’s first law is also called the law of inertia.
  • Inertia is the tendency of a stationary object to remain at rest, and of a moving object to continue moving with the same velocity in a straight line; that is, objects resist any change in their state of rest or motion.
  • Everyday examples of inertia
  • A passenger standing in a bus is thrown forward when the bus brakes suddenly: his body tends to keep moving forward.
  • When a train suddenly moves forward, a small bag lying under a seat appears to slide backward relative to the train, because it tends to stay at rest while the train moves forward under it.
  • A card under a coin on a glass flick the card away quickly and the coin drops into the glass, since it tends to remain at rest.
  • Measure of inertia. Observation shows that the difficulty of stopping a moving body depends on its mass and its velocity:
  • A large truck is hard to stop, a small bicycle is easy, if they move at the same velocity.
  • A car moving fast is hard to stop; the same car moving slowly is easy to stop.
    The two factors together define a new quantity, the momentum.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 32 / 49
Momentum

Momentum

  • Momentum (p) is the product of the mass of a body and its velocity:
  • p = m v
Comparison aspectMain ideaKeywords
•It is a vector (same direction as the velocity)vectorsamedirectionvelocity
Unitkg·m/s
Dimensional formulaMLT−1
•A body with larger momentum needs a larger force or a longer time to be stoppedbodylargermomentumneeds
Example 1.A truck of mass 8000 kg moves at 15 m/s: p = 8000 × 15 = 1.2 × 105 kg·m/s. A cyclist and cycle of total mass 90 kg at 6 m/s: p = 540 kg·m/s. The truck’s momentum is more than 200 times largertruckmass8000moves
Example 2.
  • A 0.15 kg ball moves at 20 m/s to the right: p = +3 kg·m/s. After it rebounds at 20 m/s to the left
  • p = −3 kg·m/s
  • the change of momentum is −3 − (+3) = −6 kg·m/s
ballmovesrightAfter
Example 3.What speed gives a 1200 kg car the same momentum as the truck in Example 1? v = p/m = 1.2 × 105/1200 = 100 m/s (360 km/h)Whatspeedgives1200
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 33 / 49
Statement

Statement

  • By the first law, an object with no resultant force has no acceleration.
  • So if a resultant force acts (ΣF ≠ 0) the velocity changes and the object accelerates (a ≠ 0).
  • Newton’s second law gives the exact relation.
  • Newton’s second law The resultant force acting on an object is equal to the time rate of change of its momentum.

ΣF = Δp/Δt = (m vf − m vi)/Δt

  • If the mass is constant:

ΣF = m (vf − vi)/Δt = m Δv/Δt

and since Δv/Δt is the acceleration,

ΣF = m a→or a = ΣF / m
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 34 / 49
Another statement of the law

Another statement of the law

  • When a resultant force acts on an object it gives the object an acceleration that is directly proportional to the force and inversely proportional to its mass, and in the direction of the force.
  1. Same mass, greater force → greater acceleration.
  2. Same force, greater mass → smaller acceleration.
  3. Graph of acceleration against force.
  • For a given mass the graph a–F is a straight line through the origin whose slope is 1/m.
  • For a smaller mass the slope (and so the acceleration for the same force) is larger.
  • For example a 100 kg body has twice the acceleration of a 200 kg body under the same force.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 35 / 49
Definition of the newton

Definition of the newton

From F = ma→1 newton is the force that gives a mass of 1 kg an acceleration of 1 m/s2.

1 N = 1 kg·m/s2

  • The dimensional formula of force is MLT−2.
  • One newton is also equal to 105 dynes, so the dyne is a much smaller unit of force.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 36 / 49
Thinking exercise

Thinking exercise

  • A force F on a wooden cube gives it a certain acceleration.
  • The same force on another cube gives it three times the acceleration.
  • Since a = F/m with F constant, a ∝ 1/m, so the second cube has one-third of the mass of the first.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 37 / 49
Worked examples

Worked examples

Comparison aspectMain ideaKeywords
Example 1 — F = ma.A car of mass 1200 kg accelerates uniformly at 2.5 m/s2. The resultant force = 1200 × 2.5 = 3000 Nmass1200acceleratesuniformly
Example 2 — mass.A resultant force of 45 N gives a body an acceleration of 1.5 m/s2. m = F/a = 45/1.5 = 30 kgresultantforcegivesbody
Example 3 — net force with friction.
  • A 50 kg crate is pushed by a 200 N force while friction opposes the motion with 120 N. ΣF = 200 − 120 = 80 N
  • a = 80/50 = 1.6 m/s2
cratepushedwhileopposes
Example 4 — from the change of momentum.
  • A force acts on a 2 kg body
  • changing its velocity from 3 m/s to 15 m/s in 4 s. Δp = 2 × (15 − 3) = 24 kg·m/s
  • F = 24/4 = 6 N. (Check: a = 12/4 = 3 m/s2
  • F = 2 × 3 = 6 N.)
forceactsbodychanging
Example 5 — velocity after a time.
  • A 5 kg trolley at rest is pulled by a net force of 10 N for 6 s. a = 10/5 = 2 m/s2
  • v = at = 2 × 6 = 12 m/s
trolleyrestpulledforce
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 38 / 49
Life applications of the second law (force, time and change of momentum)

Life applications of the second law (force, time and change of momentum)

  • From F = Δ(mv)/Δt, i.e.
  • F·Δt = Δ(mv) (the product Ft is called the impulse), the force needed to bring a given moving body to rest depends on the time it takes:
  • If the change of momentum happens over a longer time, the force is smaller (the effect of the impact is less).
  • If it happens in a shorter time, the force is larger.
  • This explains:
  1. A car hitting a wall is more destructive than a car hitting a heap of straw: the wall stops it in a very short time (large force); straw takes longer (smaller force).
  2. A person falling from a height into water is not hurt but falling onto ground may hurt: water brings him to rest more slowly.
  3. The severity of the injury increases with the height of the fall, because the velocity (and so the momentum) at impact increases.
  4. An egg does not break when it falls on a cushion, but it breaks on the floor.
  5. A collision of a large truck with a wall is more destructive than that of a small truck: larger mass → larger momentum → larger force for the same stopping time.
  6. in cars increase the time over which the driver’s body comes to rest in a collision, reducing the force on him.
    Similarly, a cricket or football goalkeeper pulls the hands back while catching a fast ball to lengthen the stopping time.

✍️ Worked examples

  • Example 6 (numerical). A 0.15 kg ball moving at 20 m/s is caught and stopped.
  • Stopped in 0.01 s (hard hands): F = 0.15 × 20/0.01 = 300 N.
  • Stopped in 0.10 s (hands drawn back): F = 0.15 × 20/0.10 = 30 N, ten times smaller.
  • Example 7 (airbag). A driver of mass 70 kg moving at 14 m/s is stopped in 0.05 s by a rigid steering wheel: F = 70 × 14/0.05 = 19 600 N. With an airbag extending the time to 0.25 s: F = 70 × 14/0.25 = 3 920 N.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 39 / 49
The first law as a special case of the second

The first law as a special case of the second

  • If ΣF = 0 then, from ΣF = ma, a = 0 and the velocity is constant.
  • So the first law follows from the second law as a special case (zero resultant force).
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 40 / 49
Observations

Observations

  • A balloon blown up and released flies off as the air rushes out.
  • A person on a rolling chair who pushes a wall with his feet moves away from the wall.
  • A rifle "kicks back" when a bullet is fired.
    All these cases are explained by Newton’s third law.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 41 / 49
Statement

Statement

Comparison aspectMain ideaKeywords
Newton’s third law
  • When one object exerts a force on a second object
  • the second exerts a force on the first that is equal in magnitude and opposite in direction. In short: for every action there is an equal and opposite reaction
objectexertsforcesecond
Mathematical formF₁ = − F₂
  • Forces occur in pairs.
  • Example two spring balances hooked together and pulled give identical readings: the force of the first on the second equals that of the second on the first.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 42 / 49
Properties of action and reaction

Properties of action and reaction

Comparison aspectMain ideaKeywords
There is no single force
  • in the universe
  • action and reaction appear together and disappear together
universeactionreactionappear
•
  • They are equal in magnitude
  • opposite in direction
  • and have the same line of action
equalmagnitudeoppositedirection
They have the same nature
  • if the action is a gravitational force
  • so is the reaction
actiongravitationalforcereaction
They do not cancel each otherbecause they act on two different bodies. (Forces cancel only if they act on the same body.)becausedifferentbodiesForces
Thinking corner→when a large truck collides with a small car, which receives the larger force? Both receive forces of equal magnitude. The car is damaged more, and gains a larger acceleration (a = F/m), because its mass is smaller.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 43 / 49
Applications

Applications

Comparison aspectMain ideaKeywords
Rocket propulsion
  • burning gas of large mass is expelled backwards (downwards) at high speed
  • the reaction on the rocket is a thrust forward (upwards). A rocket needs no air to push against
  • so it works in space
burninglargemassexpelled
Recoil of a gun
  • the gun pushes the bullet forward
  • the bullet pushes the gun backward with an equal force
  • but the gun’s much larger mass gives it a very small acceleration
pushesbulletforwardbackward
Swimming/walking
  • a swimmer pushes the water back
  • the water pushes him forward
  • when walking your foot pushes the ground backward and the ground pushes you forward
swimmerpusheswaterback
Spacean astronaut who throws an object in one direction moves in the opposite direction. This suggests how a spacecraft can change its direction outside the atmosphere: by ejecting gas in the direction opposite to the desired changeastronautthrowsobjectdirection
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 44 / 49
Worked examples

Worked examples

✍️ Worked examples

  • Example 1.
  • Two skaters stand on smooth ice.
  • Skater A (60 kg) pushes skater B (40 kg) with a force of 120 N.
  • Then B pushes A with 120 N in the opposite direction (third law).
  • aB = 120/40 = 3 m/s2; aA = 120/60 = 2 m/s2, in opposite directions.
    The lighter skater accelerates more, although the forces are equal.
  • Example 2.
  • A hammer hits a nail with 400 N.
  • The nail pushes back on the hammer with 400 N in the opposite direction.
  • The nail moves in because it has little resistance; the hammer slows down because of the force of the nail.
  • Example 3. A 0.02 kg bullet leaves a 4 kg rifle with an acceleration of 5000 m/s2 during the shot. Force on the bullet = 0.02 × 5000 = 100 N. Force on the rifle = 100 N backward; its acceleration = 100/4 = 25 m/s2 backward (so a firm grip is needed).
  • Example 4.
  • Which statement is wrong?
  • "The weight of a book and the upward force of the table on it are an action-reaction pair." They act on the same object (the book) and are balanced, so they are not an action–reaction pair; the third-law pair of the table’s force on the book is the force of the book on the table.
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 45 / 49
Short answers to typical discussion questions

Short answers to typical discussion questions

Comparison aspectMain ideaKeywords
•
  • A train suddenly moves forward
  • where does a small bag under a seat go? Relative to the train it moves backward
  • because of its inertia (it tends to stay at rest)
trainsuddenlymovesforward
Why is the first law a special case of the second?
  • When ΣF = 0
  • ma = 0 so a = 0 — constant velocity
constantvelocity
What happens when an astronaut throws an object?
  • He moves in the opposite direction (third law)
  • a spacecraft can change direction by expelling gas
movesoppositedirectionthird
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 46 / 49
Summary

Summary

Comparison aspectMain ideaKeywords
Force
  • an external influence that changes or tries to change the state of motion
  • unit newton (N)
  • measured by a spring balance
externalinfluencechangestries
First law
  • ΣF = 0 → rest or constant velocity
  • inertia is the resistance to change of the state of motion
restconstantvelocityinertia
•Momentum p = mv (kg·m/s)Momentum
Second law
  • ΣF = Δp/Δt = ma
  • a ∝ F
  • a ∝ 1/m
  • 1 N = 1 kg·m/s2. A longer time of impact gives a smaller force
longertimeimpactgives
Third law
  • F₁ = −F₂
  • equal
  • opposite
  • same nature
  • on different bodies
  • appear and disappear together
equaloppositesamenature
•
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Key Scientific Tables & Anatomical Diagrams Extracted from Official Curricula

Key Scientific Tables & Anatomical Diagrams Extracted from Official Curricula

💡 Core Diagrams & Reference Data→All data, reference comparison tables, and anatomical figures have been accurately digitized from official curriculum textbooks.

🔬 figure_diagram_1

  • Scientific details and precise observational breakdown:
  • & From the opposite figure, answer the following :
  • 1. What is the name of the resulted gas from the reaction (1) ?
  • 3. Mention the type of the reaction happened in both tubes (1)

and (2), showing that by symbolic equations. (1)

Question 3] 5 marks |

  • ® Put () or (x):
  • 1. The reaction : Cl, + 2e° ——» 2CTI, represents oxidation process. ( )
  • 2. The reactions of the covalent compounds are slow. ( )
  • 3. Mercury causes the corrosion of the gold when they touch each other because

it is more active than gold. ( )

Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 48 / 49
Part 49

Part 49

  • 📖

🔍 In-Depth Explanations, Deductions & Multi-Book Insights:

General & Integrated Science (2026/2027)

  • Lesson 1 – Speed, Uniform Acceleration and Laws of Motion
  • Kinematics describes the motion of physical bodies without regarding the forces causing it.
  • We derive the concepts of regular and irregular velocity, acceleration (a = Δv / Δt), graphical representations of motion, and Newton's laws governing mechanical motion in science.

🌳 Conceptual Hierarchy Tree

Kinematics and Dynamics Foundations

├── 1. Speed and Velocity (v = d / t)
│ ├── Uniform SpeedCovers equal distances in equal time intervals
│ └── Average SpeedTotal distance covered divided by total time taken (vavg = dtotal / ttotal)
├── 2. Acceleration (a = [v2 – v1] / Δt)
│ ├── Positive (Accelerating)Final speed exceeds initial speed (v2 > v1)
│ ├── Negative (Decelerating)Final speed is less than initial speed (v2 < v1)
│ └── Zero AccelerationMoving with constant uniform speed
└── 3. Graphical Motion Analysis
├── Distance-Time (d – t) graphSlope equals Velocity
└── Speed-Time (v – t) graphSlope equals Acceleration; Area under curve equals Distance
📋 Master Teacher's Blackboard Secrets
RULE 1When a moving car applies brakes until it comes to a complete stop: Final velocity v2 = 0, and acceleration 'a' is negative.
RULE 2In a Distance-Time graph: A horizontal line parallel to the time axis indicates the body is AT REST (v = 0).
RULE 3In a Speed-Time graph: A horizontal line parallel to the time axis indicates UNIFORM CONSTANT SPEED (a = 0).
📊 MatrixGraphical Curves and Physical Interpretations in Kinematics
Graph Type Curve Shape Physical Meaning Physical Slope Value
Distance – Time (d – t) Straight line passing through origin Uniform Constant Speed Slope = Velocity (v)
Distance – Time (d – t) Horizontal line parallel to time axis Body at complete rest Slope = 0 (v = 0)
Speed – Time (v – t) Straight line passing through origin Uniform Positive Acceleration Slope = Acceleration (+a)
Speed – Time (v – t) Horizontal line parallel to time axis Uniform Constant Speed Slope = 0 (Zero acceleration)
Lesson 1: Speed, Uniform Acceleration and Laws of Motion · 49 / 49