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Quiz

Lesson 1 Quiz: Equilibrium of a Particle, Friction and Limiting Static Friction

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1.
STEM Analytical Chemistry Problem 5: When dilute hydrochloric acid (HCl) is added to a solid unknown salt, a colorless gas evolves that turns paper moistened with acidified potassium dichromate from orange to green. What is the anion?
Sulfite anion (SO32−) producing sulfur dioxide gas (SO2)
Sulfide anion (S2−) producing H2S
Carbonate anion (CO32−) producing CO2
Thiosulfate anion producing SO2 and yellow sulfur precipitate
2.
STEM Transition Elements Problem 40: Why are most compounds of transition metals in the first series colored and paramagnetic?
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
Because of the total absence of electrons in the d-subshell
Due to nuclear fission within the metal atom
Because they possess completely filled 3d10 orbitals
3.
STEM Chemistry Problem 36: A 25.0 mL sample of 0.10 M H2SO4 is completely neutralized by 0.20 M NaOH. What volume of NaOH solution is required to reach the equivalence point?
50.0 mL of NaOH
25.0 mL of NaOH
10.0 mL of NaOH
12.5 mL of NaOH
4.
STEM Chemistry Problem 10: A 25.0 mL sample of 0.10 M H2SO4 is completely neutralized by 0.20 M NaOH. What volume of NaOH solution is required to reach the equivalence point?
10.0 mL of NaOH
25.0 mL of NaOH
50.0 mL of NaOH
12.5 mL of NaOH
5.
STEM Transition Elements Problem 24: Why are most compounds of transition metals in the first series colored and paramagnetic?
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
Because they possess completely filled 3d10 orbitals
Because of the total absence of electrons in the d-subshell
Due to nuclear fission within the metal atom
6.
STEM Transition Elements Problem 18: Why are most compounds of transition metals in the first series colored and paramagnetic?
Because of the total absence of electrons in the d-subshell
Due to nuclear fission within the metal atom
Because they possess completely filled 3d10 orbitals
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
7.
STEM Chemistry Problem 5: A 25.0 mL sample of 0.10 M H2SO4 is completely neutralized by 0.20 M NaOH. What volume of NaOH solution is required to reach the equivalence point?
50.0 mL of NaOH
12.5 mL of NaOH
10.0 mL of NaOH
25.0 mL of NaOH
8.
STEM Transition Elements Problem 43: Why are most compounds of transition metals in the first series colored and paramagnetic?
Because they possess completely filled 3d10 orbitals
Due to nuclear fission within the metal atom
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
Because of the total absence of electrons in the d-subshell
9.
STEM Transition Elements Problem 26: Why are most compounds of transition metals in the first series colored and paramagnetic?
Because they possess completely filled 3d10 orbitals
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
Due to nuclear fission within the metal atom
Because of the total absence of electrons in the d-subshell
10.
STEM Analytical Chemistry Problem 26: When dilute hydrochloric acid (HCl) is added to a solid unknown salt, a colorless gas evolves that turns paper moistened with acidified potassium dichromate from orange to green. What is the anion?
Sulfite anion (SO32−) producing sulfur dioxide gas (SO2)
Carbonate anion (CO32−) producing CO2
Sulfide anion (S2−) producing H2S
Thiosulfate anion producing SO2 and yellow sulfur precipitate
11.
STEM Analytical Chemistry Problem 32: When dilute hydrochloric acid (HCl) is added to a solid unknown salt, a colorless gas evolves that turns paper moistened with acidified potassium dichromate from orange to green. What is the anion?
Thiosulfate anion producing SO2 and yellow sulfur precipitate
Sulfite anion (SO32−) producing sulfur dioxide gas (SO2)
Carbonate anion (CO32−) producing CO2
Sulfide anion (S2−) producing H2S
12.
STEM Chemistry Problem 26: A 25.0 mL sample of 0.10 M H2SO4 is completely neutralized by 0.20 M NaOH. What volume of NaOH solution is required to reach the equivalence point?
12.5 mL of NaOH
10.0 mL of NaOH
25.0 mL of NaOH
50.0 mL of NaOH
13.
STEM Analytical Chemistry Problem 22: When dilute hydrochloric acid (HCl) is added to a solid unknown salt, a colorless gas evolves that turns paper moistened with acidified potassium dichromate from orange to green. What is the anion?
Sulfite anion (SO32−) producing sulfur dioxide gas (SO2)
Thiosulfate anion producing SO2 and yellow sulfur precipitate
Sulfide anion (S2−) producing H2S
Carbonate anion (CO32−) producing CO2
14.
STEM Chemistry Problem 18: A 25.0 mL sample of 0.10 M H2SO4 is completely neutralized by 0.20 M NaOH. What volume of NaOH solution is required to reach the equivalence point?
12.5 mL of NaOH
50.0 mL of NaOH
25.0 mL of NaOH
10.0 mL of NaOH
15.
STEM Transition Elements Problem 14: Why are most compounds of transition metals in the first series colored and paramagnetic?
Because they possess completely filled 3d10 orbitals
Due to nuclear fission within the metal atom
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
Because of the total absence of electrons in the d-subshell
16.
STEM Chemistry Problem 1: A 25.0 mL sample of 0.10 M H2SO4 is completely neutralized by 0.20 M NaOH. What volume of NaOH solution is required to reach the equivalence point?
50.0 mL of NaOH
10.0 mL of NaOH
25.0 mL of NaOH
12.5 mL of NaOH
17.
STEM Chemistry Problem 6: A 25.0 mL sample of 0.10 M H2SO4 is completely neutralized by 0.20 M NaOH. What volume of NaOH solution is required to reach the equivalence point?
50.0 mL of NaOH
10.0 mL of NaOH
25.0 mL of NaOH
12.5 mL of NaOH
18.
STEM Transition Elements Problem 25: Why are most compounds of transition metals in the first series colored and paramagnetic?
Because they possess completely filled 3d10 orbitals
Due to the presence of unpaired electrons in 3d orbitals that absorb specific wavelengths of visible light for d-d excitation
Due to nuclear fission within the metal atom
Because of the total absence of electrons in the d-subshell
19.
STEM Analytical Chemistry Problem 25: When dilute hydrochloric acid (HCl) is added to a solid unknown salt, a colorless gas evolves that turns paper moistened with acidified potassium dichromate from orange to green. What is the anion?
Carbonate anion (CO32−) producing CO2
Sulfide anion (S2−) producing H2S
Thiosulfate anion producing SO2 and yellow sulfur precipitate
Sulfite anion (SO32−) producing sulfur dioxide gas (SO2)
20.
STEM Chemistry Problem 29: A 25.0 mL sample of 0.10 M H2SO4 is completely neutralized by 0.20 M NaOH. What volume of NaOH solution is required to reach the equivalence point?
50.0 mL of NaOH
10.0 mL of NaOH
25.0 mL of NaOH
12.5 mL of NaOH
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