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Physics — Second Secondary

Physics — Second Secondary

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Physics — Second Secondary 2026/2027

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Question bank: Chapter 5: Properties of Hydrostatics

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  • Questions count: 6
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1.
The pressure due to the liquid alone at a depth h is:
ρgh
Pa + ρgh
ρh/g
ρg/h
2.
The total pressure at a point at depth h in a liquid open to the atmosphere is:
ρgh
Pa − ρgh
Pa + ρgh
Pa/ρgh
3.
If a liquid is replaced by one of twice the density, the pressure ρgh at the same depth becomes:
half
the same
double
four times
4.
One atmosphere equals:
76 mm Hg
760 mm Hg
7600 mm Hg
0.76 mm Hg
5.
One bar equals:
103 Pa
104 Pa
105 Pa
106 Pa
6.
One torr equals:
1 mm Hg
1 cm Hg
1 Pa
1 bar
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