
Practice with full answer key
Point 5 of 5 — Definite Integration, Areas and Volumes of RevolutionQuestion bank: 0 questions (0 with pictures)
05 Practice with full answer key
- ∫01 (6x² − 4x + 1) dx → 2 − 2 + 1 = 1
- ∫1e (1/x) dx → [ln x]1e = 1
- ∫01 x ex² dx → u = x², du = 2x dx → ½(e − 1)
- ∫−21 |x| dx → 2 + ½ = 5/2
- Area between y = x² and y = 2x → intersections 0 and 2, A = ∫(2x − x²) = 4/3
- Area bounded by y = √x, y = 0, x = 4 → ∫04 √x dx = 16/3
- Volume of y = x³ about the x-axis, 0 ≤ x ≤ 2 → π∫x⁶ dx = 128π/7
- Volume of y = 1/x about the x-axis, 1 ≤ x ≤ 3 → π(1 − ⅓) = 2π/3
- ∫0π sin x dx → [−cos x]0π = 2
- If ∫03 f(x) dx = 7 and ∫35 f(x) dx = 2, find ∫05 f = 9 and ∫50 f = −9
📝 Question bank for this point
0 questions linked to this point only, 0 of them with pictures.