Dabour Hub EGEgyptian Curriculum 2026/2027
Solving systems of linear equations

Solving systems of linear equations

Point 4 of 5 — Determinants, Matrices and Solving Linear EquationsQuestion bank: 0 questions (0 with pictures)

04 Solving systems of linear equations

The inverse-matrix method

  • Write the system as AX = B, then X = A⁻¹B, provided det A ≠ 0.
  • Example: 2x + 3y = 7 and x − 2y = −7.
    A = [[2, 3], [1, −2]], det A = −4 − 3 = −7, A⁻¹ = (−1/7)[[−2, −3], [−1, 2]].
  • X = A⁻¹B = (−1/7)[[−2·7 + (−3)(−7)], [−1·7 + 2(−7)]] = (−1/7)[[7], [−21]] = [[−1], [3]], so x = −1 and y = 3.

Cramer's rule

  • For AX = B with det A ≠ 0: x = Dx/D, y = Dy/D, z = Dz/D, where D = det A and Dx is D with the x-column replaced by B.
  • Same system: D = −7, Dx = |[[7, 3], [−7, −2]]| = −14 + 21 = 7 → x = 7/(−7) = −1.
  • Dy = |[[2, 7], [1, −7]]| = −14 − 7 = −21 → y = (−21)/(−7) = 3.
  • Both methods give the same answer; Cramer's rule is faster for a single unknown, the inverse method is better when several right-hand sides share the same A.

Interpreting the determinant

1≠ 0
System AX = B
  • Unique solution
2= 0 and consistent
System AX = B
  • Infinitely many solutions
3= 0 and inconsistent
System AX = B
  • No solution

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