Dabour Hub EGEgyptian Curriculum 2026/2027
1-3 (a) The ratio between two consecutive terms

1-3 (a) The ratio between two consecutive terms

Point 6 of 8 — Lesson 1: Counting Principle, Permutations (nPr) and Combinations (nCr)Question bank: 5 questions (5 with pictures)

06 1-3 (a) The ratio between two consecutive terms

Ratio of terms

  • For consecutive terms Tr and Tr+1 of (x+a)n: Tr+1Tr=n−r+1r×ax
  • For the coefficients (when the terms are written with a common variable), the factor ax is replaced by the ratio of the coefficients of the second and first terms of the binomial.
  • For (1+x)n:  coefficient of Tr+1coefficient of Tr=n−r+1r.
  • Proof of the ratio: nCrnCr−1=n!r!(n−r)!×(r−1)!(n−r+1)!n!=n−r+1r.
✍️ Worked examples

Example 14: In the expansion of (x+y)12 find T4T3 and the ratio T9T7.

Solution:

  • For T4T3 take r=3: 12−3+13⋅yx=103⋅yx.
  • T9T7=T9T8×T8T7.
  • T9T8 has r=8: 12−8+18⋅yx=58⋅yx.
  • T8T7 has r=7: 12−7+17⋅yx=67⋅yx.
  • T9T7=58×67⋅y2x2=1528⋅y2x2.

📝 Question bank for this point

5 questions linked to this point only, 5 of them with pictures.