🎯 Learning outcomes
- Define variation function V(h), average rate of change function A(h), and the instantaneous rate of change (derivative).
- Interpret the first derivative geometrically as the trigonometric tangent slope m = tan θ to the curve.
- Formulate and master standard differentiation rules: Constant, Power, Sum/Difference, Product, and Quotient rules.
- Apply the Chain Rule for composite functions and generalized power differentiation.
- Determine the analytical equations of tangent and normal lines to plane curves at specified points.
- Apply differential calculus to kinematic physical quantities (displacement, instantaneous velocity, acceleration).
🌳 Concept tree
01 Key terms
- Variation Function V(h): The absolute change in the dependent variable y = f(x) corresponding to an increment h in the independent variable x: V(h) = f(x1 + h) - f(x1).
- Average Rate of Change A(h): The ratio of variation in function value to the increment h: A(h) = V(h) / h = [f(x1 + h) - f(x1)] / h. Geometrically represents the slope of the secant line passing through points (x1, f(x1)) and (x1+h, f(x1+h)).
- Instantaneous Rate of Change (First Derivative f'(x)): The limiting value of the average rate of change as h approaches zero: f'(x) = limh -> 0 [f(x + h) - f(x)] / h. Represents the slope of the tangent line to the curve at x.
- Differentiability: A function f is differentiable at x = a if the limit definition of the derivative exists and is finite. Differentiability strictly implies continuity at that point.
- Normal Line: The straight line perpendicular to the tangent line at the exact point of tangency. Its slope satisfies: mnormal = -1 / mtangent (provided mtangent ≠ 0).
02 Laws and key relationships
- Limit Definition of the First Derivative (First Principles): [ Formula: f'(x) = dy/dx = limh -> 0 [f(x + h) - f(x)] / h ] Calculates the instantaneous rate of change of f(x) by taking the limit of secant slopes as the distance between points collapses to zero.
- Quotient Rule of Differentiation: [ Formula: d/dx [u / v] = [v · u' - u · v'] / v² ] The derivative of a quotient equals denominator times derivative of numerator minus numerator times derivative of denominator, divided by denominator squared.
- The Chain Rule for Composite Functions: [ Formula: dy/dx = (dy/du) · (du/dx) ; d/dx [u(x)]n = n [u(x)]n - 1 · u'(x) ] Enables differentiation of nested functions by multiplying the derivative of the outer function by the derivative of the inner function.
03 Foundational Limits: Variation, Average Rate, and the Derivative
Differential calculus originated from two classical geometric and physical problems: determining the slope of a tangent line to an arbitrary plane curve (Fermat and Leibniz) and calculating the instantaneous velocity of a moving body (Newton).
Consider a function y = f(x). When x changes from an initial value x1 to x1 + h (where h = Δx is a non-zero increment):
(1) The Variation Function V(h) measures the vertical displacement: V(h) = f(x1 + h) - f(x1).
(2) The Average Rate of Change Function A(h) normalizes this variation per unit increment: A(h) = V(h) / h = [f(x1 + h) - f(x1)] / h. Geometrically, A(h) represents the slope msecant of the secant line cutting the curve through points P(x1, f(x1)) and Q(x1 + h, f(x1 + h)).
(3) The Instantaneous Rate of Change (The First Derivative dy/dx or f'(x1)) is the limiting behavior as the increment h shrinks towards zero: dy/dx = limh -> 0 A(h) = limh -> 0 [f(x1 + h) - f(x1)] / h. As h -> 0, point Q travels along the curve towards P, and the secant line PQ transitions smoothly into the unique Tangent Line at point P. The derivative equals the tangent slope: f'(x1) = tan θ, where θ is the positive angle made with the positive x-axis.
04 Fundamental Algebraic Rules and Theorems of Differentiation
Evaluating the limit definition for every function is computationally tedious; standard operational differentiation rules are derived directly from first principles:
(1) Constant Rule: The derivative of any constant real number c is zero: d/dx [c] = 0 (since a horizontal line y = c has zero slope).
(2) Power Rule: For any real exponent n: d/dx [xn] = n xn - 1. Examples: d/dx [x] = 1; d/dx [x⁵] = 5x⁴; d/dx [1/x] = d/dx [x⁻¹] = -1 x⁻² = -1/x²; d/dx [√x] = d/dx [x1/2] = (1/2) x-1/2 = 1 / (2√x).
(3) Constant Multiple Rule: d/dx [c · f(x)] = c · f'(x).
(4) Sum and Difference Rule: d/dx [f(x) ± g(x)] = f'(x) ± g'(x).
(5) Product Rule: The derivative of a product of two differentiable functions: d/dx [u(x) · v(x)] = u(x) · v'(x) + v(x) · u'(x) (First × derivative of second + Second × derivative of first).
(6) Quotient Rule: For rational functions where denominator v(x) ≠ 0: d/dx [u(x) / v(x)] = [v(x) · u'(x) - u(x) · v'(x)] / [v(x)]² (Denominator × derivative of numerator - Numerator × derivative of denominator, divided by denominator squared).
05 The Chain Rule, Tangent Lines, and Kinematic Motion
The Chain Rule: If y is a differentiable function of u, and u is a differentiable function of x, then: dy/dx = (dy/du) · (du/dx). In particular, for a function raised to a power: d/dx [f(x)]n = n [f(x)]n - 1 · f'(x).
Tangent and Normal Lines: At any regular point P(x1, y1) lying on the curve y = f(x):
A. Tangent Line Equation: Calculate slope m = f'(x1). The tangent line equation is: y - y1 = m(x - x1). If m = 0, the tangent is horizontal (y = y1). If the denominator of f'(x1) is zero, the tangent is vertical (x = x1).
B. Normal Line Equation: Because the normal line is perpendicular to the tangent, its slope is mnormal = -1 / m. The normal line equation is: y - y1 = (-1 / m)(x - x1).
Kinematic Physical Applications: If s(t) represents the position vector of a particle at time t: (1) Instantaneous Velocity v(t) = ds/dt = s'(t). (2) Instantaneous Acceleration a(t) = dv/dt = d²s/dt² = s''(t). When a particle changes its direction of motion, it comes to instantaneous rest: v(t) = 0.
06 Worked examples
Worked Example 1: Tangent and Normal Equations to a Rational Function
Problem Statement: Find the equations of both the tangent line and the normal line to the curve y = (3x - 1) / (x + 1) at the point where x = 1.
Detailed Solution & Derivation: Step 1: Find the y-coordinate at x = 1: y1 = (3(1) - 1) / (1 + 1) = 2 / 2 = 1. Tangency point is P(1, 1). Step 2: Differentiate y using the Quotient Rule: dy/dx = [(x + 1)·d/dx(3x - 1) - (3x - 1)·d/dx(x + 1)] / (x + 1)² = [(x + 1)(3) - (3x - 1)(1)] / (x + 1)² = [3x + 3 - 3x + 1] / (x + 1)² = 4 / (x + 1)². Step 3: Calculate tangent slope m at x = 1: m = 4 / (1 + 1)² = 4 / 4 = 1. Step 4: Equation of Tangent Line: y - y1 = m(x - x1) -> y - 1 = 1(x - 1) -> y = x (or x - y = 0). Step 5: Normal slope mnormal = -1 / m = -1 / 1 = -1. Step 6: Equation of Normal Line: y - 1 = -1(x - 1) -> y - 1 = -x + 1 -> x + y - 2 = 0.
Worked Example 2: Kinematic Motion Analysis via Derivatives
Problem Statement: A projectile moves along a straight line such that its distance s (in meters) from a fixed point after t seconds is given by: s(t) = t³ - 6t² + 9t + 4. Determine: (1) The velocity at any time t; (2) The time instances when the particle is at rest; (3) The total distance covered during the first 4 seconds.
Detailed Solution & Derivation: Step 1: Velocity v(t) = s'(t) = 3t² - 12t + 9. Step 2: Particle is at rest when v(t) = 0: 3(t² - 4t + 3) = 0 -> 3(t - 1)(t - 3) = 0 -> t = 1 second and t = 3 seconds. Step 3: Because the particle reverses direction at t = 1 and t = 3, total distance must be computed in three sub-intervals: [0, 1], [1, 3], and [3, 4]. s(0) = 4 m; s(1) = 1 - 6 + 9 + 4 = 8 m; s(3) = 27 - 54 + 27 + 4 = 4 m; s(4) = 64 - 96 + 36 + 4 = 8 m. Distance d1 = |s(1) - s(0)| = |8 - 4| = 4 m. Distance d2 = |s(3) - s(1)| = |4 - 8| = 4 m. Distance d3 = |s(4) - s(3)| = |8 - 4| = 4 m. Total distance covered = 4 + 4 + 4 = 12 meters.
07 Exam tips
- Exam Secret: 'Continuity does NOT imply differentiability'. A classic example is f(x) = |x| at x = 0: it is continuous, but the left derivative is -1 while the right derivative is +1. Because left and right limits do not match, f'(0) does not exist (sharp corner).
- Exam Trap: If the tangent line makes an obtuse angle with the positive x-axis, its slope m is negative (m = tan θ < 0). If θ = 90°, m is undefined (vertical tangent).
- When finding the rate of change of area or volume with respect to time, always apply the Chain Rule: dA/dt = (dA/dr) · (dr/dt).
08 Real-world applications
- Economic Marginal Analysis: In macroeconomics, marginal cost MC(x) = C'(x) is the derivative of the total cost function, indicating the cost of manufacturing one additional unit.
- Aerospace Trajectory Optimization: Rocket guidance computers calculate instantaneous rates of velocity change to adjust propellant throttle and maintain stable orbital insertion.
- Civil Engineering Stress Analysis: Structural deflection of suspension bridges under vehicle loads is modeled using fourth-order differential equations derived from curvature slopes.
Challenge questions
Interactive ministerial-pattern questions based exclusively on this chapter with step-by-step reasoning.
The derivative of f(x) = 4 x3 - 5 x2 + 7 x - 9 with respect to x is:
The slope of the tangent line to the curve y = x2 - 6 x + 5 at the point (4, -3) equals:
If y = (2x + 1) * (3x - 4), then dy/dx evaluated at x = 1 equals:
Using the Quotient Rule, the derivative of y = (x + 3) / (x - 2) for x != 2 is:
According to the Chain Rule, if y = (3 x2 - 5)4, then dy/dx is:
