Dabour Hub EGEgyptian Curriculum 2026/2027
3-9 Mixed applications with areas

3-9 Mixed applications with areas

Point 9 of 9 — Unit 3: Parallel Lines, Proportional Segments and Angle BisectorsQuestion bank: 0 questions (0 with pictures)

09 3-9 Mixed applications with areas

  • Triangles ABD and ACD share the same altitude from A, so area(△ABD)/area(△ACD) = BD/DC; using the bisector theorem this ratio is also AB/AC.
  • Combining with similarity: a ratio of lengths gives a ratio of areas only when the triangles are similar or share an altitude — state which one you are using.
  • Perimeter problems: if a bisector or a parallel divides a side, first find the two parts with the ratio, then substitute into the length formulas.
  • Coordinate setups: assign the base on the x-axis and use the section formula with the ratio from the bisector theorem to locate D.

📝 Question bank for this point

0 questions linked to this point only, 0 of them with pictures.