7.1Gravitation
Planetary Motion and Gravitation — American System Physics Revision Notes & Topical Questions
10 min read 7 parts Lesson 3 of 5 1 quiz
State and apply Newton's law of universal gravitation, including the inverse-square dependence.Gravitational force = G × mass 1 × mass 2 ÷ (distance between centres)2: F = Gm1m2/r2 (F in N, m in kg, r in m).What the symbols mean: F = gravitational force (N) · G = 6.67 × 10−11 N m…
- Newton's third law
- Kepler's third law
- From Newton's law for a circular orbit
- Second law
- Cavendish used a torsion balance
- Universal gravitational constant (G)
Section 1 of 7Planetary Motion and Gravitation
Section 2 of 7Process & sequence
Using Kepler's third lawwrite these steps in this order; each step is a marking point.
Section 3 of 7Compare
| Law | Statement (short) | What it tells you |
|---|---|---|
| First | Orbits are ellipses, Sun at one focus | Shape of an orbit |
| Second | Equal areas in equal times | Planet speeds up near the Sun, slows far away |
| Third | T2 ∝ r3 for the same central body | Farther planets have much longer years |
Kepler found the laws from Tycho Brahe's observations; Newton later explained them with gravitation.
| Change | New force |
|---|---|
| Double one mass | 2F |
| Double both masses | 4F |
| Double the distance | F/4 |
| Triple the distance | F/9 |
| Halve the distance | 4F |
Section 4 of 7Worked examples
- F = Gm1m2/r2 = (6.67 × 10-11)(5.97 × 1024)(7.35 × 1022) / (3.84 × 108)2
Numerator = 2.927 × 1037;- denominator = 1.475 × 1017
F = 1.98 × 1020 N (attractive, along the Earth–Moon line).
- denominator = 1.475 × 1017
- F ∝ m1m2/r2. New F = 36 × 2 / 32 = 36 × 2/9 = 8.0 N.
- Kepler's third law(TM/TE)2 = (rM/rE)3 = 1.523 = 3.512
TM/TE = √3.512 = 1.87
TM = 1.87 × 1 year = 1.87 Earth years.
Section 5 of 7Key terms
Section 6 of 7Command terms
Section 7 of 7Exam technique
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Q1. If the distance between two masses is halved, the gravitational force becomes:
Show answer
C. F ∝ 1/r2; (1/2)2 in the denominator gives 4F.
Q2. The SI unit of G is:
- A. N·m2/kg2
- B. N/kg
- C. m/s2
- D. N·kg2/m2
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A. Rearranging G = Fr2/(m1m2) gives N·m2/kg2.
Q3. According to Kepler's second law, a planet moves fastest when it is:
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B. Equal areas in equal times means a shorter Sun–planet line must sweep faster.
Q4. Kepler's third law states that:
- A. T ∝ r
- B. T3 ∝ r2
- C. T ∝ r2
- D. T2 ∝ r3
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D. Period squared is proportional to mean radius cubed.
Q5. What did the Cavendish experiment first measure?
- A. g
- B. the Sun's mass
- C. G
- D. the speed of the Moon
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C. The torsion balance measured the tiny force between lead spheres, giving G.
Q6. A satellite of mass 500 kg and one of mass 1000 kg orbit Earth at the same radius. Their periods are:
- A. the same
- B. the heavier one's is double
- C. the heavier one's is half
- D. impossible to compare
Show answer
A. The orbiting mass cancels: T = 2π√(r3/GM) depends only on r and the central mass.
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