Reflection and Refraction
Reflection and Refraction — American System Physics Revision Notes & Topical Questions
5 min read 6 parts Lesson 1 of 5 1 quiz
Reflection and Refraction: Mirrors, Refraction and Lenses — AMERICAN SYSTEM PHYSICS notes: Apply the law of reflection, Snell's law and the mirror and lens equation to locate and describe images and explain total internal reflection.The law of reflection has two parts: angle of i…
- lateral inversion
- critical angle
- Magnification
- short sight (myopia)
- Worked example 1
- Worked example 2
Section 1 of 6Reflection and plane mirrors
The law of reflection has two parts: angle of incidence i equals angle of reflection r (both measured from the normal), and the incident ray, reflected ray and normal lie in one plane.
- which is why we can see non-luminous objects from any direction.
- (a sheet of paper in a lit room)
To find the image in a plane mirror, draw two rays from a point on the object, reflect each with i = r, then extend the reflected rays backward as dashed lines; the image is where they cross.
- which is why AMBULANCE is printed reversed).
Section 2 of 6Refraction and total internal reflection
Refraction is the change in direction of a wave as it enters another medium, caused by a change in speed; frequency stays constant while speed and wavelength change.
| Medium | n |
|---|---|
| Vacuum/air | 1.00 |
| Water | 1.33 |
| Glass | 1.52 |
| Diamond | 2.42 |
The critical angle c is the angle of incidence in the denser medium for which the angle of refraction is exactly 90°; sin c = 1/n for a boundary with air.
Section 3 of 6Mirrors, lenses and image formation
The mirror/lens equation is 1/f = 1/do + 1/di.
| Device | Type | Images |
|---|---|---|
| Plane mirror | - | virtual, upright, same size |
| Concave mirror | converging | real inverted (object beyond f) or virtual upright (inside f) |
| Convex mirror | diverging | virtual, upright, smaller (wide field, used as car wing mirror) |
| Convex lens | converging | real inverted or virtual magnified |
| Concave (diverging) lens | diverging | virtual, upright, smaller |
A diverging lens is thinner in the middle and spreads parallel rays as if from the principal focus.
Section 4 of 6Worked examples
A ray hits a plane mirror with angle of incidence 40°. What is the angle between the reflected ray and the mirror surface? [2]2 marks
r = 40° from the normal, so the angle to the surface is 90° − 40° = 50°.
An object is 30 cm in front of a plane mirror. How far is the image from the object? [1]1 mark
The image is 30 cm behind the mirror: 30 + 30 = 60 cm.
A convex lens has f = 10 cm and the object is 30 cm away. Find the image and describe it. [3]3 marks
1/di = 1/10 − 1/30, so di = 15 cm; the image is real, inverted and smaller.
f = 20 cm and do = 60 cm. Find di. [2]2 marks
1/di = 1/20 − 1/60 = 2/60, so di = 30 cm.
An object 4.0 cm tall gives an image 1.0 cm tall. Find the magnification. [1]1 mark
m = 1.0/4.0 = 0.25.
Explain why a mirror rotated by 15° turns the reflected ray (fixed incident ray) through 30°. [2]2 marks
The normal rotates by 15°, changing both i and r by 15°, so the reflected ray turns through twice the mirror angle.
Section 5 of 6Key terms
| Term | Meaning |
|---|---|
| Reflected ray | The ray leaving a surface after reflection. |
| Lateral inversion | The left-right reversal of an image in a plane mirror. |
| Refraction | Change in direction of a wave on entering another medium, caused by a change in speed. |
| Critical angle | Angle of incidence in the denser medium giving 90° refraction; sin c = 1/n. |
| Diverging (concave) lens | A lens thinner in the middle that spreads parallel rays. |
| Magnification | Image height divided by object height, m = hi/ho. |
| Short sight (myopia) | Defect where light is focused in front of the retina; corrected by a diverging lens. |
Section 6 of 6Exam technique
Marked practiceQuizzes for this lesson
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