18.3Electrostatics
Electric Fields and Potential — American System Physics Revision Notes & Topical Questions
10 min read 7 parts Lesson 5 of 5 1 quiz
Define electric field and field strength and state the direction of a field.Field strength = force ÷ charge, E = F/q (N/C); so F = qE (N).What the symbols mean: E = electric field strength (N C−1) · F = force on the charge (N) · Q or q = charge (C)Field of a point chargeE = kq/r2…
- Uniform field between plates
- Millikan's oil drop
- Field lines are a model
- How much work is done moving a 3.0 μC charge through a potential difference of 12 V?
- Electric field strength (E)
- Direction of an electric field
Section 1 of 7Electric Fields and Potential
Section 2 of 7Process & sequence
- or parallel metal strips) and connect them to a high-voltage supply.
- (with safety precautions and teacher supervision)
Drawing an electric field patternwrite these steps in this order; each step is a marking point.
Section 3 of 7Compare
| Arrangement | Pattern of lines | Notes |
|---|---|---|
| Isolated positive point charge | Straight lines radiating outward | Field strength falls as 1/r2 |
| Isolated negative point charge | Straight lines pointing inward | Same shape, opposite direction |
| + and − charges near each other | Curved lines from + to − | Dense between charges |
| Two like charges | Lines curve apart; neutral point midway | Zero field at neutral point (equal charges) |
| Parallel plates | Parallel, equally spaced from + to − plate | Uniform field; E = ΔV/d; edges curve |
Section 4 of 7Worked examples
- E = F/q = 0.024/4.0 × 10−6 = 6.0 × 103 N/C in the direction of the force.
- (a) E = ΔV/d = 500/0.025 = 2.0 × 104 V/m (N/C).
- (b) F = qE = 1.60 × 10−19 × 2.0 × 104 = 3.2 × 10−15 N, directed towards the positive plate.
How much work is done moving a 3.0 μC charge through a potential difference of 12 V?
- W = qΔV = 3.0 × 10−6 × 12 = 3.6 × 10−5 J.
Section 5 of 7Key terms
Section 6 of 7Command terms
Section 7 of 7Exam technique
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Q1. Electric field strength is defined as
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B. E = F/q, in N/C.
Q2. A 2.0 μC charge in a field of 3.0 × 10⁴ N/C feels a force of
- A. 0.060 N
- B. 6.0 N
- C. 1.5 × 10⁴ N
- D. 0.015 N
Show answer
A. F = qE = 2.0×10⁻⁶ × 3.0×10⁴ = 0.060 N.
Q3. Plates 0.010 m apart at 200 V give a field of
- A. 2.0 V/m
- B. 200 V/m
- C. 2.0 × 10⁴ V/m
- D. 2.0 × 10³ V/m
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C. E = ΔV/d = 200/0.010 = 2.0×10⁴ V/m.
Q4. Field lines around an isolated positive charge point
- A. inward
- B. outward
- C. in circles
- D. nowhere
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B. Lines point away from positive charges.
Q5. One volt is equal to
- A. 1 N/C
- B. 1 J/C
- C. 1 C/J
- D. 1 J s
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B. Potential difference = work per unit charge.
Q6. An electron is placed in a field pointing east. The force on it is
- A. east
- B. west
- C. north
- D. zero
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B. Negative charges feel a force opposite to the field.
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