1.3.2Kinematics
Motion Graphs — AP PHYSICS 1 Revision Notes & Topical Questions
5 min read 10 parts Lesson 11 of 14 1 quiz
Lesson summary
1.3.2 Motion Graphs — AP PHYSICS 1 notes: Interpret position-time, velocity-time and acceleration-time graphs, including slope and area.GraphSlopey-interceptArea under curvePosition-timeInstantaneous velocityInitial positionNo meaningVelocity-timeAccelerationInitial velocityDispl…
- Constant gradient
- Curved line
- Positive slope
- Horizontal line
- Straight sloping line
- Displacement
Section 1 of 10Interpreting motion graphs
| Graph | Slope | y-intercept | Area under curve |
|---|---|---|---|
| Position-time | Instantaneous velocity | Initial position | No meaning |
| Velocity-time | Acceleration | Initial velocity | Displacement |
| Acceleration-time | No meaning | Initial acceleration | Change in velocity |
Section 2 of 10Position-time graphs
Constant gradient
- Constant gradient constant velocity
Curved line
- Curved line acceleration
Positive slope
- Positive slope motion in the positive direction; negative slope — motion in the negative direction
Horizontal line
- Horizontal line at rest
Section 3 of 10Velocity-time graphs
Straight sloping line
- Straight sloping line uniform acceleration
Curve
- Curve non-uniform acceleration
Horizontal line
- Horizontal line constant velocity
Area
- Area displacement, with areas below the axis counted as negative
Section 4 of 10Acceleration-time graphs
Horizontal line
- Horizontal line constant acceleration
Area
- Area change in velocity
Section 5 of 10Finding slope
1
For a straight line, calculate Δy/Δx.
2
For a curve, draw a tangent at the chosen point.
3
Calculate the gradient of the tangent.
4
Use a ruler and make the triangle large.
Section 6 of 10Pattern: taxicab on a v-t graph
Shape
- Shape acceleration, constant velocity, deceleration, rest, then motion in the negative direction
Displacement
- Displacement the positive area (+9 m) and negative area (−10 m) give a net displacement of −1 m
Return to start
- Return to start when the negative area equals the positive area (9 m)
Section 7 of 10Sketching graphs
Required
- Required correct shape and labelled axes
Not required
- Not required annotation with specific values
Section 8 of 10More from the specification
More from the specification
Motion graph invariance across reference frames
- Motion graph invariance across reference frames velocity-time slope calculations yield identical acceleration regardless of origin shifts between inertial reference frames.
Stationary
- Not moving.
Reference frame
- Coordinate system used by an observer.
Final velocity
- Velocity at the end, v.
Kinematic equation
- Equation for constant-acceleration motion.
Kinematic equations
- Equations relating displacement, velocity, acceleration and time for constant acceleration.
Relative motion
- Motion of one object measured from another.
Section 9 of 10Key terms
| Term | Meaning |
|---|---|
| Slope | Gradient of a graph, Δy/Δx. |
| Tangent | Line touching a curve at a point. |
| Area under a graph | Product of the axes quantities, e.g. displacement for v-t. |
| Uniform acceleration | Straight line on a v-t graph. |
Section 10 of 10Exam technique
1
Reading the area under a position-time graph as a quantity.
2
Reading the slope of an acceleration-time graph as a quantity.
3
Using a chord instead of a tangent for instantaneous values.
4
Counting areas below the axis as positive.
Marked practiceQuizzes for this lesson
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