7.10Advanced Organic Chemistry
Nuclear Magnetic Resonance Spectroscopy — AQA A Level Chemistry Revision Notes & Topical Questions
5 min read 7 parts Lesson 10 of 12
Nuclear Magnetic Resonance Spectroscopy: 1H and 13C NMR — AQA A LEVEL CHEMISTRY — COMPLETE NOTES notes: Explain the principles of NMR and use chemical shift, integration and splitting patterns to deduce structures.Nuclei with an odd number of nucleons, such as 1H and 13C, behave like tiny magnets.
- Worked example 1
- Worked example 2
- Worked example 3
- Worked example 4
- Deuterated solvent
- Number of peaks: the number of different proton environments
Part 1 of 5Principles of NMR
Nuclei with an odd number of nucleons, such as 1H and 13C, behave like tiny magnets.
- so nuclei in different environments absorb at different positions.
- TMS is used because it is inert, volatile, gives one sharp signal from 12 equivalent hydrogens and is at the end of the scale.
Part 2 of 5Carbon-13 NMR
The number of peaks equals the number of different carbon environments.
- Symmetry reduces the number of signalsfor example, propanone has two (CH3 and C=O), and benzene has one.
Part 3 of 5Proton (1H) NMR
Four pieces of information are used:
- Hydrogens on O (OH) and N usually appear as singlets because of rapid exchange.
Adding D2O removes OH and NH signals, since the H is replaced by D, helping to identify those groups.
Part 4 of 5Putting it together
Start with the molecular formula (from mass spectrometry) and the number of peaks; use integration to assign numbers of hydrogens; use shifts to identify groups; use splitting to see which groups are neighbours. Example: ethyl ethanoate shows three 1H peaks: a triplet (CH3CH2, 3H), a singlet (CH3CO, 3H) and a quartet (OCH2, 2H).
Part 5 of 5Worked examples
How many peaks are in the 13C NMR of propan-2-ol? [2]2 marks
Two: two equivalent CH3 carbons and the CH(OH) carbon.
A compound C4H8O2 has a 1H spectrum: singlet 3H at δ 2.0, quartet 2H at δ 4.1, triplet 3H at δ 1.2. Give its structure. [3]3 marks
The quartet and triplet show an ethyl group (CH3CH2); the δ 4.1 shift means the CH2 is next to oxygen of an ester; the singlet at δ 2.0 is CH3 next to C=O with no neighbours. Structure: CH3COOCH2CH3 (ethyl ethanoate); hydrogens 3+2+3 = 8 matches the formula.
Give the splitting of the CH2 peak in CH3CH2Br. [1]1 mark
A quartet (three neighbouring H on CH3).
Why is TMS used as the reference compound? [2]2 marks
It is inert and non-toxic, gives a single sharp peak from 12 identical H, and its signal is at a lower δ than most others.
Key terms
| Term | Meaning |
|---|---|
| Chemical shift | Position of a peak relative to TMS in ppm. |
| TMS | Tetramethylsilane, the NMR reference compound. |
| Integration | Peak area, proportional to number of H. |
| Splitting | Peak splitting by neighbouring H following the n+1 rule. |
| Deuterated solvent | Solvent in which H is replaced by D so it gives no 1H signal. |
Avoid these mistakes
Last updated: