5.4.8Forces
Distance-Time Graphs — AQA GCSE Combined Science Trilogy 8464 - Physics Revision Notes & Topical Questions
5 min read 8 parts Lesson 25 of 44
Section 1 of 8What a distance-time graph shows
A distance-time graph shows how far an object is from a starting point at each moment. Time is plotted along the horizontal axis (x-axis) and distance along the vertical axis (y-axis). Because the graph tells us the position at every moment, we can read off where the object is, when it moves, when it stops and how fast it goes.
Distance in these graphs is measured in metres (m) or kilometres (km) and time in seconds (s) or hours (h). Always check the axis labels and units before reading values, and note where each axis begins, since the graph might not start at zero.
Section 2 of 8The meaning of the shape
The shape of the line tells the story of the journey:
Note that a downward-sloping line does not mean a negative speed. Speed is the size of the rate of change, so the speed is still the numerical value of the gradient, without the minus sign. It is the direction that changed.
Section 3 of 8Finding speed from the gradient
The gradient (slope) of a distance-time graph is equal to the speed:
gradient = change in distance ÷ change in time = speed
To find the gradient of a straight line, draw a right-angled triangle against the line, as large as is practical.
For a curved graph, the speed at a particular moment is the gradient of the tangent, a straight line drawn to just touch the curve at that point. This is called the instantaneous speed.
Section 4 of 8Average speed from the graph
The average speed over the whole journey is the total distance travelled divided by the total time, not the average of the speeds.
This topic leads directly to the definition of speed in 1.1.2, and the corresponding graph of velocity against time in 1.1.5.
Section 5 of 8Worked reading of a graph
Suppose a graph for a bus shows these stages: 0 to 40 s, a line rising from 0 m to 200 m; 40 to 70 s, a horizontal line at 200 m; 70 to 100 s, a line rising to 500 m.
- as in 'the bus is stationary between 40 s and 70 s because the distance stays at 200 m'.
Also check carefully whether a graph shows distance from the start or total distance travelled: a returning journey only appears as a falling line on the first.
Section 6 of 8Worked examples
A cyclist's graph is a straight line from (0 s, 0 m) to (20 s, 100 m). Find her speed.
Gradient = change in distance ÷ change in time = 100 m ÷ 20 s = 5.0 m/s.
A graph shows a car moving 60 m in the first 10 s, staying at rest from 10 s to 25 s and then travelling a further 90 m between 25 s and 40 s. Find its speed in each part and the average speed for the whole journey.
First part: 60 ÷ 10 = 6.0 m/s.
Rest: gradient zero, so 0 m/s.
Last part: 90 ÷ (40 − 25) = 90 ÷ 15 = 6.0 m/s.
Whole journey: total distance = 150 m, total time = 40 s, so average speed = 150 ÷ 40 = 3.75 m/s.
A distance-time graph for a walker is a line from (0 s, 0 m) to (50 s, 60 m), and then a line from (50 s, 60 m) to (110 s, 0 m). Describe the motion and find the speeds.
The walker moves away from the start for 50 s at 60 ÷ 50 = 1.2 m/s, then returns to the start in 60 s at 60 ÷ 60 = 1.0 m/s.
The total distance walked is 120 m, but the final displacement is zero, because the walker has returned.
Section 7 of 8Key terms
| Term | Meaning |
|---|---|
| Gradient | Change in vertical value divided by change in horizontal value. |
| Stationary | Not moving; shown by a horizontal line on a distance-time graph. |
| Constant speed | Equal distances in equal times; shown by a straight sloping line. |
| Average speed | Total distance divided by total time. |
| Tangent | A straight line touching a curve at one point; its gradient is the speed at that instant. |
Section 8 of 8Exam technique
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