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Medical physics and astronomy (A Level)

24. Medical Physics

5 min read 10 parts Lesson 21 of 22 Unit quiz

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24. Medical Physics — Cambridge AS & A Level Physics 9702 — CAMBRIDGE AS & A LEVEL PHYSICS 9702 — COMPLETE NOTES notes: Explain how ultrasound, X-rays, CT scans and PET scans are produced, used and compared, and use acoustic impedance, attenuation and annihilation.Transducer = an…

  • Piezoelectric effect
  • Applications
  • Transducer structure
  • Transmit and receive
  • Imaging process
  • Acoustic impedance Z

Section 1 of 10The piezoelectric effect and transducers

  • Transducer = any device that converts energy from one form to another.
  • Piezoelectric effect = certain crystals (such as quartz, a lattice of silicon dioxide) produce a p.d. when deformed,
    • and deform when a p.d. is applied.
    • Compressing or stretching the crystal induces an e.m.f., and alternating compression gives an alternating e.m.f.
    • An alternating p.d. makes the crystal vibrate at the same frequency, producing sound.
    • The crystal is cut to a size that resonates at the required frequency.
  • Applications
    • microphones and ultrasound transmitters and receivers.
      • (pressure variations to electrical signals)

Section 2 of 10Generating and using ultrasound

  • Ultrasound = sound with a frequency above the range of human hearing (above 20 kHz), typically in the MHz range for medical use.
  • Transducer structure
    • a piezoelectric crystal with electrodes supplying an alternating p.d.
  • Damping
    • the crystal is backed with epoxy resin so it gives short pulses, which improves resolution.
  • Transmit and receive
    • the same crystal acts as transmitter (p.d. to sound) and receiver.
      • (sound to alternating p.d.)
  • Imaging process
    • the transducer sends a pulse into the body, which is partly reflected at boundaries between tissues.
    • The echo returns and generates an electrical signal for the scanner.
    • The scanner uses the speed of sound and the time delay to calculate depth, and the echo intensity to show the nature of the boundary.
    • Many pulses are combined into a two-dimensional image, as for an unborn child.
  • Frequency
    • a higher frequency gives a shorter wavelength and better resolution, so smaller details are seen.

Section 3 of 10Acoustic impedance and coupling gel

  • Acoustic impedance Z = the product of the density of a medium and the speed of ultrasound in it, Z = ρc, in kg m−2 s−1.
    • Sound is fastest in solids and slowest in gases, because closer particles pass vibrations faster.
    • The c is the speed of sound, not light.
  • Boundary behaviour
    • part of the wave is reflected and part transmitted, and a larger difference in impedance gives greater reflection.
  • Intensity reflection coefficient
    • α = IR/I0 = (Z2 − Z1)2/(Z2 + Z1)2, given in the data booklet.
    • If Z1 = Z2 there is no reflection.
    • Energy is conserved, I0 = IT + IR.
  • Problem
    • air has Z about 400 kg m−2 s−1 and skin about 1.7 × 106, so almost all ultrasound reflects at an air gap (α ≈ 1).
  • Coupling gel
    • a gel with impedance similar to skin fills the gap, so very little is reflected (α ≈ 0.001) and most of the beam enters the body.
    • It matches impedances and does not make the ultrasound travel faster.

Section 4 of 10Attenuation of ultrasound

  • Attenuation = the loss of intensity as a wave is absorbed while travelling through a material.
  • Equation
    • I = I0e−μx, where μ is the absorption coefficient (m−1) and x the distance; this equation is not given.
  • Frequency dependence
    • about 0.5 dB cm−1 is lost for every 1 MHz of frequency.
  • Image formation
    • attenuation is not a major problem, because the image is made from reflections at boundaries.
  • Echoes from depth
    • the beam is attenuated going in, partly reflected and attenuated coming back, so the path is 2x.

Section 5 of 10Producing X-rays

  • X-rays = short-wavelength electromagnetic radiation, about 10−8 to 10−13 m.
  • Production
    • electrons from a heated cathode are accelerated to a metal anode target.
      • (thermionic emission)
    • The fast electrons decelerate in the target, transferring kinetic energy to X-ray photons.
    • Electrons in the target atoms dropping to lower energy levels release characteristic X-ray photons.
  • Maximum photon energy
    • Emax = eV = hfmax = hc/λmin.
  • Spectrum
    • continuous,
    • because electrons decelerate by different amounts, with a sharp cut-off at short wavelength because each electron gives its energy to at most one photon.

Section 6 of 10Quality of X-ray images and attenuation

  • Aim
    • minimise the patient's exposure and maximise the contrast and sharpness of the image.
  • Exposure
    • X-rays are ionising and can damage tissue or cause cancer.
    • An aluminium filter absorbs long-wavelength (soft) X-rays, which are absorbed by the body and do not form the image.
  • Contrast = the difference in blackening between structures.
    • It improves with hard X-rays for bone, softer X-rays for tissue and a contrast medium.
    • Good contrast needs a large difference between the transmitted intensities through different structures.
  • Sharpness = how well-defined edges are, improved by a narrower beam, a collimator or lead grid to cut scattering, and smaller pixels.
  • Attenuation
    • bone absorbs X-rays strongly, so it appears white.
    • I = I0e−μx, where μ is the linear absorption coefficient and depends on photon energy and material.
    • Half-value thickness is the thickness of material that halves the beam intensity.
    • For several materials multiply the factors, I/I0 = e−μ1x1 × e−μ2x2.

Section 7 of 10CT scanning

  • CT (CAT) scan = an X-ray tube rotates around a stationary patient, taking images of one slice from many angles,
    • and a computer combines successive slices into a 3D image that can be viewed from any angle.
AdvantagesDisadvantages
Higher resolution than a single X-rayMuch higher radiation dose
Distinguishes tissues with similar attenuation coefficientsPossible side effects from contrast media
Produces a 3D image
  • Dose
    • a CT scan needs many exposures from many angles, whereas a plain X-ray needs one.

Section 8 of 10Radioactive tracers

  • Tracer = a substance containing radioactive nuclei, introduced to the body and absorbed by tissue to study the structure and function of organs.
  • Suitable isotopes
    • technetium-99m and fluorine-18 bind to organic molecules, emit gamma or positron radiation and decay to stable isotopes.
      • (such as glucose)
    • Technetium-99m has a half-life of 6 hours.
    • Fluorine-18 has a half-life of 110 minutes, so exposure is short.
  • Uses
    • diagnosing cancer, finding areas of reduced blood flow in the heart, and detecting brain injury, Alzheimer's disease and dementia.
  • Monitoring
    • the tracer appears on the screen once tissues absorb it, showing the progress of a disease and the effect of treatment.

Section 9 of 10PET scanning and annihilation

  • PET (positron emission tomography) = imaging of tissue by measuring the metabolic activity of cells, commonly using fluorodeoxyglucose (glucose containing fluorine-18).
  • Decay
    • fluorine-18 undergoes β+ decay: 189F → 188O + 0+1e + νe.
  • Annihilation
    • a positron travels less than a millimetre, meets an electron and both are destroyed, converting their mass to energy as two gamma photons in opposite directions.
    • Mass, energy and momentum are conserved, and any particle and its antiparticle can annihilate.
    • Each photon has E = hf = mec2 and momentum p = E/c.

Section 10 of 10Detecting gamma rays in PET

  • Scanner
    • the patient lies in a ring of detectors, each with a scintillator crystal and a photomultiplier.
    • A gamma photon excites electrons in the crystal, which excite others, and as they return to lower states they emit faint visible light.
    • The photomultiplier amplifies the light and converts it to an electrical signal.
  • Line of response
    • the two photons travel in opposite directions, so a pair of simultaneous hits defines a line through the annihilation point.
  • Image
    • a computer processes many lines and arrival times, and more photons from a point mean more tracer there, which appears as a bright area.
  • Practical points
    • the short half-life gives low exposure but the patient must be scanned quickly, and PET scanners are expensive and not in every hospital.

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