12.2.2Particle Model
Absolute Zero — Edexcel GCSE Combined Science 1SC0 - Physics Revision Notes & Topical Questions
5 min read 9 parts Lesson 13 of 13
Part 1 of 7Cooling a gas
As a gas is cooled, its molecules slow down.
Part 2 of 7Extrapolating to zero pressure
Experiments with different gases and different starting amounts all give straight lines. When the lines are extended (extrapolated) backwards, they all reach zero pressure at the same temperature, about −273 °C. Real gases liquefy before they get there, so the line is extended by calculation, not measurement.
Zero pressure would mean the molecules were no longer hitting the walls, that is, they would have almost no kinetic energy. So −273 °C is the lowest temperature possible. We call it absolute zero.
Part 3 of 7What absolute zero means
- They do not stop completely, but at IGCSE we treat them as having essentially none.
- (quantum effects)
Notice that absolute zero was found using the behaviour of gases, but it applies to every substance: it is the lower limit for temperature itself.
Part 4 of 7The Kelvin scale
The kelvin (K) is the SI unit of temperature. The Kelvin scale starts at absolute zero, so it has no negative values. A temperature step of 1 K is exactly the same size as a step of 1 °C. To convert:
T (K) = θ (°C) + 273
θ (°C) = T (K) − 273
Note that the kelvin is written K with no degree sign.
Part 5 of 7Why use the Kelvin scale?
The Celsius scale is based on the properties of water, so its zero is arbitrary.
Part 6 of 7Evidence from experiments
A simple way to find absolute zero is to use a flask of air at constant volume connected to a pressure gauge.
- but it is convincing evidence that there is a minimum possible temperature.
Low temperature in practice
Scientists can cool materials to within a tiny fraction of a kelvin above absolute zero using liquid helium (boiling at about 4 K) and further techniques.
- which is a statement of the third law of thermodynamics encountered in later physics courses.
Part 7 of 7Worked examples
Convert (a) 25 °C to kelvin and (b) 150 K to °C.
(a) T = 25 + 273 = 298 K.
(b) θ = 150 − 273 = −123 °C.
A student says 'the temperature rose from 10 °C to 20 °C, so the particles have twice the energy'. Is this correct? Use the Kelvin scale to decide.
10 °C = 283 K and 20 °C = 293 K. The ratio is 293 / 283 ≈ 1.04, so the average kinetic energy has risen by only about 4%, not doubled. The student wrongly used the Celsius scale, which has no true zero.
Key terms
| Term | Meaning |
|---|---|
| Absolute zero | Lowest possible temperature: 0 K or about −273 °C. |
| Kelvin (K) | SI unit of temperature, starting from absolute zero. |
| Extrapolate | Extend a graph line beyond the measured data. |
| Kinetic energy | Energy an object has because of its motion. |
Avoid these mistakes
Last updated: