2.2.2Electricity
Voltage in Series and Parallel — Edexcel International GCSE Science Double Award 4SD0 - Physics Revision Notes & Topical Questions
5 min read 8 parts Lesson 6 of 14
Part 1 of 7Series circuits
In a series circuit the e.m.f. of the supply is shared among the components. The sum of the p.d. across all the components equals the p.d. of the supply:
Vsupply = V1 + V2 + V3
This follows from conservation of energy
- each coulomb leaving the cell carries a certain amount of energy, and this is transferred in the components it passes through.
- If the components are identical, they share the voltage equally;
- if not, the component with the larger resistance has the larger p.d. across it, because V = IR with the same current in each.
Notice how the series rules connect to the equation V = IR.
Part 2 of 7Parallel circuits
In a parallel circuit, each branch is connected directly across the same two points, so each branch has the same p.d. as the supply:
V1 = V2 = Vsupply
For this reason, two lamps in parallel across a 6.0 V cell each have 6.0 V across them, however different they are. The lamps in a house are all in parallel so each receives the full 230 V of the mains supply.
Because every branch in parallel sees the full supply voltage, the same lamp shines with the same brightness in a parallel circuit no matter how many other lamps are added, as long as the supply can provide enough current.
Part 3 of 7Cells and batteries
When cells are connected in series, positive end to negative end, their e.m.f. values add: two 1.5 V cells in series give 3.0 V.
Part 4 of 7Measuring voltage
Voltmeters are connected in parallel across the component.
When you draw circuits for these questions, label the p.d. across each component with an arrow or a V label. Then check that around any closed loop, the voltage gains from cells equal the voltage drops across components. This rule is the energy conservation law for circuits, and a quick check on your answers.
Part 5 of 7Potential divider idea
Two resistors in series across a supply divide the supply voltage in proportion to their resistances.
Remember that a switch that is open has the full supply p.d. across it, because no current flows and so there is no p.d. across the other components, whereas a closed switch has zero p.d. across it as its resistance is negligible. This is a useful fault-finding clue: a voltmeter across a broken wire reads the full supply voltage.
Part 6 of 7Summary table
| Series | Parallel | |
|---|---|---|
| Voltage | Shared; adds to supply voltage | Same across every branch |
| Current | Same | Splits |
Combine this with V = IR to solve circuits with several components.
Part 7 of 7Worked examples
Two lamps are in series with a 9.0 V battery. The first has 3.5 V across it. Find the p.d. across the second lamp.
V2 = 9.0 − 3.5 = 5.5 V.
Three resistors in parallel are connected to a 12 V supply. What is the p.d. across each?
The same as the supply: 12 V across each.
A 4.0 Ω and a 8.0 Ω resistor are in series with a 6.0 V cell. Find the p.d. across the 8.0 Ω resistor.
I = V/R = 6.0 / 12 = 0.50 A.
V = IR = 0.50 × 8.0 = 4.0 V.
What the symbols mean: V = potential difference (V) · I = current (A) · R = resistance (Ω)
Key terms
| Term | Meaning |
|---|---|
| Potential divider | Series resistors that split a supply voltage. |
| E.m.f. | Energy per coulomb given by a source. |
| Series cells | Cells in a chain whose e.m.f. add. |
| Branch p.d. | Voltage across one branch of a parallel circuit. |
Avoid these mistakes
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