3.2.4Waves
Snell’s Law — Edexcel International GCSE Science Double Award 4SD0 - Physics Revision Notes & Topical Questions
5 min read 9 parts Lesson 12 of 14
Section 1 of 9Refractive index
The refractive index n of a material is a measure of how much it slows and bends light. It is defined as the ratio of the speed of light in a vacuum (or air) to the speed in the material:
n = c / v
Since light is always slower in a material than in a vacuum, n is always greater than 1 and has no unit. Typical values: air about 1.00, water 1.33, glass about 1.5, diamond 2.4. A higher refractive index means a slower speed and more bending.
Section 2 of 9Snell's law
For light entering a material from air, the sine of the angle of incidence divided by the sine of the angle of refraction is constant for any angle:
n = sin i / sin r
This is known as Snell's law. It means that if n is known, r can be calculated for any i using r = sin−1(sin i / n). Remember to use a calculator in degree mode.
Section 3 of 9Using the equation
You can rearrange the formula as needed: sin i = n sin r and sin r = sin i / n.
- as light paths are reversible.
The speed of light in the material can be found from v = c / n.
Section 4 of 9Graphs and measurement
If you measure i and r for several rays, plotting sin i on the vertical axis against sin r on the horizontal axis gives a straight line through the origin whose gradient is the refractive index.
Section 5 of 9Why it matters
Refractive index decides how lenses focus light and how prisms spread colours, and explains why diamonds sparkle: the high index of 2.4 gives a small critical angle (see Total Internal Reflection), so light is trapped and reflected many times inside the stone. It also explains apparent depth: a swimming pool appears shallower than its true depth by a factor of roughly n.
Section 6 of 9Worked strategy for refraction questions
A reliable method is to follow the same steps each time.
The combination of Snell's law with the idea of speed lets you answer more complex questions.
- but at IGCSE most questions involve air,
- which is why the simple formula is enough.
Section 7 of 9Worked examples
Light passes from air into glass of refractive index 1.50. The angle of incidence is 45°. Find the angle of refraction.
sin r = sin i / n = sin 45° / 1.50 = 0.7071 / 1.50 = 0.4714.
r = sin−1(0.4714) = 28.1°.
Light passes from air into water at i = 60° and the angle of refraction is 40.5°. Calculate the refractive index.
n = sin 60° / sin 40.5° = 0.866 / 0.649 = 1.33.
Find the speed of light in diamond (n = 2.4).
v = c / n = 3.0 × 108 / 2.4 = 1.25 × 108 m s−1.
Section 8 of 9Key terms
| Term | Meaning |
|---|---|
| Refractive index | Ratio of the speed of light in a vacuum to its speed in the material |
| Snell’s law | n = sin i / sin r |
| Optically dense | Having a high refractive index |
| Sine | Trigonometric ratio used in the law |
| Gradient | Slope of the sin i against sin r graph, equal to n |
Section 9 of 9Exam technique
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