4.2.1Energy Resources and Energy Transfers
Work Done — Edexcel International GCSE Science Double Award 4SD0 - Physics Revision Notes & Topical Questions
5 min read 9 parts Lesson 8 of 12
Part 1 of 7Work as energy transfer
In physics, work done is the energy transferred when a force moves an object.
Work is a scalar. It has size but no direction, though it can be positive (the force speeds the object up) or negative in advanced work (the force slows it down).
Part 2 of 7The equation
work done = force × distance moved in the direction of the force
W = F d
where W is work done in joules (J), F is the force in newtons (N) and d is the distance in metres (m) moved along the line of the force.
- because the force you exert is upwards while the movement is horizontal and perpendicular to it.
Part 3 of 7Where the energy goes
The work done on an object equals the energy transferred to it. Different situations show different destinations:
- There is no gain in kinetic energy because the speed is constant.
Because work is a way of describing a transfer, we can also say the energy transferred equals the work done by the force when the force does the transferring.
Part 4 of 7Working with forces and distances
Often you are not given F directly.
On a force-distance graph, the area under the line is the work done. A constant force gives a rectangle; a force that grows steadily, like stretching a spring, gives a triangle whose area is ½Fd.
Part 5 of 7Typical sizes and pitfalls
A person climbing a flight of stairs of height 3 m with mass 60 kg does about 60 × 9.8 × 3 ≈ 1800 J of work against gravity.
Part 6 of 7Work, direction and the idea of a
The phrase "in the direction of the force" is easy to overlook.
A planet orbiting in a circle, or a satellite at constant height, is a similar case: the gravitational force acts at right angles to the motion, so it does no work and the speed stays constant.
Part 7 of 7Worked examples
A student pushes a box with a constant force of 40 N across a floor for 6.0 m. Calculate the work done.
W = Fd = 40 × 6.0 = 240 J. This energy is transferred from the student's chemical store, mostly to the thermal store of the box and floor if the box moves at steady speed.
A crane lifts a 250 kg container through 12 m at constant speed. Find the work done by the crane. (g = 9.8 N kg−1)
Worked examplesForce needed = weight = mg = 250 × 9.8 = 2450 N.W = Fd = 2450 × 12 = 29 400 J ≈ 29 kJ.This is also the gain in gravitational potential energy of the container.A 15 N force moves a trolley 80 cm along a bench. How much energy is transferred to the trolley?
Convert distance: 80 cm = 0.80 m.
W = Fd = 15 × 0.80 = 12 J.
Key terms
| Term | Meaning |
|---|---|
| Work done | Energy transferred when a force moves an object through a distance. |
| Joule | Unit of work and energy: 1 N × 1 m. |
| Force | A push or pull measured in newtons. |
| Weight | Force of gravity on a mass, W = mg. |
| Friction | Force opposing relative motion between surfaces. |
| Force-distance graph | Graph whose area under the line equals work done. |
Avoid these mistakes
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