3.3Genetics and Heredity
Chromosomes and inheritance — EST 2 Biology Revision Notes & Topical Questions
35 min read 55 parts Lesson 3 of 6 2 quizzes
SAT Biology chromosomes and inheritance: connect meiosis, linkage, sex chromosomes, pedigrees and karyotypes to inheritance patterns. Genes lie at specific loci on chromosomes.
- crossing-over
- Nondisjunction
Section 1 of 55Chromosome theory
Section 2 of 55Crossing-over and linkage
Section 3 of 55Sex chromosomes
Section 4 of 55Pedigrees
Section 5 of 55Karyotypes and nondisjunction
Section 6 of 55Why cells divide by mitosis
All the cells in the body, except the gametes, are produced by mitosis of the zygote. Mitosis makes new cells that are genetically identical to the parent cell.
Section 7 of 55Meiosis and the halving of chromosome number
Meiosis is a type of nuclear division that gives rise to cells that are genetically different. It is involved in the production of gametes (sex cells), such as sperm and egg cells or pollen grains and ova.
The number of chromosomes must be halved when gametes are formed. Otherwise the zygote, formed when two gametes join at fertilisation, would have double the number of chromosomes.
Section 8 of 55Genes, alleles and genotype
Inheritance is the transmission of genetic information from one generation to the next. A gene is a short length of DNA on a chromosome that codes for a particular characteristic.
Alleles are versions, or forms, of a gene. Because chromosomes exist in matching pairs, an individual has two copies of each gene and so two alleles. The two can carry the same instructions or different instructions.
It is not always possible to find the genotype just by looking at the phenotype. A phenotype linked to a dominant allele appears in both the dominant homozygous and the heterozygous genotype. Two individuals who are both homozygous for the same characteristic produce offspring with exactly the same genotype and phenotype as themselves.
Section 9 of 55First monohybrid crosses with pea height
The height of pea plants is controlled by one gene with two alleles. The tall allele is dominant and written T; the short allele is recessive and written t. Tall plants are TT or Tt, and short plants are tt.
| Cross | Offspring genotypes | Result |
|---|---|---|
| TT (tall) x tt (short) | All Tt | All tall; probability of tall 100% |
| Tt x Tt (offspring of the first cross) | TT, Tt, Tt, tt | 3 tall : 1 short; probability of short 25% |
Step 1 is to write the gametes of each parent, and step 2 is to determine the probability from the Punnett square.
Section 10 of 55Comparing mitosis and meiosis
Mitosis and meiosis both begin with chromosome copying, but their outcomes are very different. A comparison table is the clearest way to remember the contrasts that exam questions are built on.
| Feature | Mitosis | Meiosis |
|---|---|---|
| Number of divisions | One | Two |
| Daughter cells | Two | Four |
| Chromosome number | Stays diploid | Halved to haploid |
| Genetic make-up | Identical to parent | Genetically different |
| Where it happens | Body cells, zygote and embryo | Reproductive organs |
| Purpose | Growth, repair, replacement, asexual reproduction | Production of gametes |
Notice that meiosis, unlike mitosis, includes recombination, in which paired chromosomes exchange segments before being pulled apart. This is why gametes from the same parent are not all identical, and why brothers and sisters can look different even though they share the same parents.
Section 11 of 55Worked examples
The height of pea plants is controlled by one gene. T is tall and dominant, t is short. A homozygous short plant is crossed with a homozygous tall plant. Show the offspring and the probability that any offspring is tall. [4]4 marks
Parents: tt and TT. Gametes: t and T. Every box of the Punnett square is Tt, so all offspring are heterozygous and tall. Probability of tall = 100%.
Two of the Tt offspring are crossed. Determine the probability that an offspring is short. [3]3 marks
Gametes: T or t from each parent. Offspring genotypes TT, Tt, Tt, tt. Phenotypes 3 tall : 1 short. Probability short = 1/4 = 25%.
Explain why meiosis must halve the chromosome number. [2]2 marks
Gametes fuse at fertilisation to form a zygote. If gametes were diploid, the chromosome number would double in every generation, so they must be haploid.
Section 12 of 55The Tt x tt cross
Show the results of crossing a heterozygous tall plant with a short plant. The heterozygous parent is Tt and the short parent is tt. Gametes: T or t from the first parent, and only t from the second.
| T | t | |
|---|---|---|
| t | Tt | tt |
| t | Tt | tt |
Offspring genotypes are Tt, Tt, tt, tt. Phenotypes are 2 tall : 2 short, so the probability of a short offspring is 50% and the probability of a tall offspring is 50%.
Section 13 of 55A step-by-step Punnett square method
A Punnett square answers all three.
A good answer shows the parent gametes, the offspring genotypes, and an indication of which offspring have the characteristic asked for, and then states the probability.
Section 14 of 55Choosing letters for alleles
If you are asked to use your own letters, pick a letter whose capital and lower-case forms look clearly different, so the examiner is not left in doubt about which allele is dominant. For example, C and c are not very different when written by hand, whereas A and a are very different.
Always use the capital letter for the dominant allele and the lower-case for the recessive allele, and state a key such as A = tall, a = short.
Section 15 of 55Family pedigree diagrams
Family pedigree diagrams trace the pattern of inheritance of a characteristic, usually a disease, through the generations of a family. Squares usually represent males and circles females; shaded symbols show affected individuals.
A pedigree can show, for example, that:
To find genotypes, work from individuals you can be sure about. If two unaffected parents have an affected child, the allele is recessive and both parents are carriers. An affected child must therefore have received one recessive allele from each parent.
Section 16 of 55Codominance and X-linked inheritance in outline
Codominance occurs when both alleles in a heterozygous organism contribute to the phenotype.
Section 17 of 55Worked approach to a full exam question
Consider a question that gives a family pedigree and asks for the probability that a new child will be affected. A reliable approach is to work in a fixed order so no step is missed.
Remember that each pregnancy is a separate event. If two carrier parents have already had an affected child, the chance of the next child being affected is still 1 in 4, or 25%. Marks are lost when students claim that the next child is safe because one has already been affected.
Section 18 of 55Worked examples
A heterozygous tall pea plant is crossed with a short plant. Determine the probability that the offspring are short. [4]4 marks
Parents Tt and tt. Gametes T, t and t, t. Offspring Tt, Tt, tt, tt: 2 tall and 2 short. Probability of short = 2/4 = 50%.
Why should a student choose A and a rather than C and c as letters for alleles? [1]1 mark
The capital and lower-case forms of A and a look clearly different when handwritten, so the dominant and recessive alleles cannot be confused.
A pedigree shows two unaffected parents with an affected daughter. What does this tell you about the allele? [3]3 marks
The allele is recessive, because it was hidden in both parents. Both parents must be carriers, and the daughter has two copies of the recessive allele.
Section 19 of 55The zoom model: from organism to DNA base
The zoom model helps you picture where you are in a cell.
Chromosomes are located in the nucleus of cells. Inheritance is the transmission of genetic information from generation to generation, and it is carried in the DNA of the chromosomes.
Section 20 of 55Haploid and diploid numbers
All humans have 23 different chromosomes in each cell, and most body cells hold two copies of each, making 46. This is the diploid number. Haploid means half the normal number of chromosomes, so human gametes have 23.
In an exam you may be given information about a different species with a different chromosome number. Read the question carefully: use the number given, not 46.
Before a cell divides by mitosis, the chromosomes double (each copies itself), so that when the cell splits in two, each new cell still has two copies of each chromosome and is still diploid. Mitosis is described in steps:
Section 21 of 55How sex is determined
Sex is determined by an entire chromosome pair, unlike most other characteristics, which are determined by just one gene or a number of genes. Females are XX and males are XY.
Because only a father can pass on a Y chromosome, he is responsible for determining the sex of the child.
- and of those about half carry an X chromosome and about half carry a Y chromosome.
| X (egg) | X (egg) | |
|---|---|---|
| X (sperm) | XX female | XX female |
| Y (sperm) | XY male | XY male |
The inheritance of sex is shown with a Punnett square in which the X and Y chromosomes replace the alleles. The probability of a boy or a girl is 50% for each pregnancy.
Section 22 of 55Control of gene expression
The DNA base sequence determines the amino acid sequence in a protein. Expression of a gene means whether that gene is transcribed and translated in a particular cell or not.
- Cell specialisation all body cells contain the same genes, but each makes only the specific proteins it needs.
- Protein types these may be enzymes, antibodies or receptors for neurotransmitters.
In this way DNA controls cell function by controlling the production of proteins.
Section 23 of 55Putting the topics together
- A zygote receives 23 chromosomes from each parent, one of which is the sex chromosome.
- Mitosis of the zygote then builds the whole body, so every body cell has the same 46 chromosomes and the same genes.
- Which genes are expressed decides what each cell becomes.
- and cells produced by mitosis contain the same number as the parent.
- For a species with a diploid number of 14, a gamete has 7 chromosomes and a zygote 14.
- so the chance of either sex is 50%.
- A common four-mark answer lists the sex chromosomes of the parents, the gametes, the offspring genotypes and the probability.
Section 24 of 55Worked examples
Explain why the father determines the sex of a child. [3]3 marks
Eggs always carry an X chromosome. Sperm carry either X or Y, about half of each. A sperm with X gives XX (girl); a sperm with Y gives XY (boy). Only the father can pass on Y.
A species has a diploid number of 8. State the number of chromosomes in a gamete and in a cell after mitosis. [2]2 marks
Gamete: 4 (haploid). Cell after mitosis: 8, because mitosis keeps the diploid number.
All the cells in a person contain the same genes, but a muscle cell differs from a nerve cell. Explain. [2]2 marks
Different genes are expressed in each cell. Each makes only the proteins it needs, because most genes are switched off in any one cell.
Section 25 of 55Meiosis step by step
Meiosis is the cell division that produces haploid gametes such as sperm cells, egg cells, pollen grains and ova.
Recombination means the daughter cells differ from each other and from the parent cell.
Section 26 of 55Genes, alleles and what they mean
Inheritance is the transmission of genetic information from one generation to the next. A gene is a short length of DNA on a chromosome that codes for a particular characteristic. Alleles are versions of a gene.
Chromosomes exist in matching pairs, so an individual has two copies of each gene and therefore two alleles of each gene. An individual can only inherit two alleles for each gene; they can be the same or different, carrying the same instructions or different instructions.
Section 27 of 55Worked monohybrid crosses for pea height
Pea height is controlled by one gene with a dominant tall allele (T) and a recessive short allele (t). Tall = TT and short = tt in the homozygous plants.
| Cross | Offspring genotypes | Phenotypes | Probability |
|---|---|---|---|
| tt x TT | Tt x4 | All tall | Tall 100% |
| Tt x Tt | TT, Tt, Tt, tt | 3 tall : 1 short | Short 25% |
| Tt x tt | Tt, Tt, tt, tt | 2 tall : 2 short | Tall 50% |
The Punnett square should show the parent gametes, the offspring genotypes, and an indication of which offspring show each phenotype.
Section 28 of 55Presenting answers and pedigrees
If you choose your own letters, avoid pairs such as C and c that look alike when handwritten; A and a are very different.
Pedigree diagrams trace a characteristic, usually a disease, through generations. A pedigree may show that both males and females are affected, that every generation has affected individuals, and that one family group has no affected parents or children.
Section 29 of 55Linking meiosis to the variety in offspring
Meiosis explains why the Punnett square works.
Recombination adds further variation. Because paired chromosomes exchange DNA, the alleles in a gamete may be a new mixture compared with either of the parent's own chromosomes. Fertilisation then adds more variation, because any gamete from one parent can fuse with any gamete from the other.
These three sources explain why offspring of the same parents differ from each other and why the observed numbers in a real cross are close to, but rarely exactly, the predicted ratio.
Section 30 of 55Worked examples
Describe what happens in the second division of meiosis. [2]2 marks
Chromosomes line up along the centre of the cell and fibres pull them apart, as in mitosis. This results in four haploid cells in total.
Two homozygous recessive short plants (tt) are crossed. State the genotype and phenotype of the offspring. [2]2 marks
All offspring are tt and short, exactly the same as the parents.
A tall plant is crossed with a short plant and 50% of the offspring are short. What is the genotype of the tall parent? [2]2 marks
Tt. A homozygous TT parent would give no short offspring; Tt x tt gives 50% tt.
Section 31 of 55Reading a family pedigree
A family pedigree diagram traces the pattern of inheritance of a specific characteristic, usually a disease, through generations of a family. The pedigree in this topic shows three features:
Look first for unaffected parents with an affected child, which proves a recessive allele, then trace the carriers back through the generations.
Section 32 of 55Codominance and blood groups
Codominance occurs when both alleles in a heterozygous organism contribute to the phenotype. Inheritance of blood group is an example. There are three alleles of the gene: IA, IB and IO.
In a worked Punnett square, a parent with blood group A and a parent with group B have a child with group O.
- because they are able to produce a child with group O: the child must have inherited an IO allele from each parent.
Section 33 of 55Sex-linked inheritance: colour blindness
Colour blindness is an X-linked condition. The allele is carried on the X chromosome and is recessive. A normal male is XNY; a carrier female is XNXn.
| XN | Xn | |
|---|---|---|
| XN | XNXN normal female | XNXn carrier female |
| Y | XNY normal male | XnY colour-blind male |
In this cross there is a 25% chance of producing a colour-blind male, 25% chance of a carrier female, 25% chance of a normal female and 25% chance of a normal male. Males are affected more often because they have only one X.
Section 34 of 55Chromosomes, genes and DNA
Chromosomes are located in the nucleus of cells.
Section 35 of 55Exam technique for pedigree and sex-linkage questions
Pedigree questions reward systematic thinking. Annotate the diagram by writing a genotype beside each individual wherever you are certain. Affected people in a recessive pedigree are always homozygous recessive. Unaffected parents of an affected child are always carriers.
For sex-linked cases, check the following before answering:
When a question says a trait appears more often in males, give the reason: males have only one X chromosome, so one recessive allele is enough to be expressed, whereas a female needs two. Marks are also given for stating that a carrier female shows the normal phenotype but can pass the allele to half of her children.
Section 36 of 55Worked examples
Parents with blood groups A and B have a child with group O. State the parents' genotypes and explain. [3]3 marks
IAIO and IBIO. The child needs an IO allele from each parent, so neither parent can be homozygous.
A normal male and a carrier female have a child. Give the probability that the child is a colour-blind male. [3]3 marks
Gametes XN, Y and XN, Xn. The four children are XNXN, XNXn, XNY and XnY. One in four, so 25%.
State two features of a pedigree for a disease. [2]2 marks
Both males and females are affected, and every generation has affected individuals.
Section 37 of 55DNA code determines the amino acid sequence
The DNA base sequence determines the amino acid sequence in a protein. The DNA code, a series of bases, is converted into protein, a series of amino acids. Proteins are made by ribosomes, with the order of amino acids controlled by the order of bases in DNA. The process of protein synthesis has two stages: transcription and translation.
Section 38 of 55Transcription and translation
DNA cannot travel out of the nucleus to the ribosomes, because it is far too big to pass through a nuclear pore. Instead:
| Stage | Where | What happens |
|---|---|---|
| Transcription | Nucleus | Gene copied to mRNA |
| Translation | Ribosome in cytoplasm | mRNA triplets read; tRNA brings amino acids |
Section 39 of 55Which proteins are made
Expression of a gene means whether it is transcribed and translated in a particular cell.
Section 40 of 55Chromosome numbers, mitosis and meiosis
All humans have 23 different chromosomes, in pairs, giving 46 in each body cell. Haploid means half the normal number. In exams, check the number given for other species.
New cells made by mitosis start by copying every chromosome, so each new cell still has two copies of each chromosome and is diploid.
Meiosis gives genetically different cells and makes gametes. The number must be halved, otherwise the zygote would have double. The first division separates pairs after recombination, the second division separates the copies, and four haploid cells are formed.
Section 41 of 55Worked examples
Explain why mRNA is needed in protein synthesis. [2]2 marks
DNA is too big to leave the nucleus through a pore. mRNA carries a copy of the gene to the ribosome in the cytoplasm.
Describe the role of tRNA. [2]2 marks
Each tRNA binds to one specific amino acid and carries it from the cytoplasm to the ribosome so the amino acids are added in the correct order.
A muscle cell and a skin cell have the same DNA. Explain why they make different proteins. [2]2 marks
Different genes are expressed. Most genes are switched off, and each cell makes only the proteins it needs.
Section 42 of 55Key vocabulary of inheritance
Inheritance is the transmission of genetic information from one generation to the next. A gene is a short length of DNA found on a chromosome that codes for a particular characteristic. Alleles are versions of a gene. Since chromosomes exist in matching pairs, an individual has two copies of each gene and therefore two alleles.
It is not always possible to deduce genotype from phenotype. If two individuals homozygous for the same characteristic are bred, offspring have exactly the same genotype and phenotype as the parents.
Section 43 of 55Three worked crosses
Pea height is controlled by one gene: T (tall, dominant) and t (short, recessive). Tall = TT, short = tt.
Each Punnett square should indicate the parent gametes, the offspring genotypes and which offspring show the trait. Step 2 is always to determine the probability from the square.
Section 44 of 55Method and presentation
To work out ratios, percentage chances or phenotypes, follow these steps:
If you choose your own letters, pick a pair with an obvious difference between capital and lower case: C and c are not very different when handwritten, whereas A and a are.
Section 45 of 55Pedigree diagrams for family traits
Pedigrees trace a characteristic, usually a disease, through generations. In the example, both males and females are affected, every generation has affected individuals, and one family group has no affected parents or children. Use them with the Punnett method to decide whether the allele is dominant or recessive and which individuals must be heterozygous.
Section 46 of 55Checking answers and common examiner points
After finishing a cross, check it with three quick tests. First, the number of boxes must be four for a monohybrid cross. Second, the probabilities must add up to 100%. Third, every offspring must have one allele from each parent, so a tt parent can never produce a TT child.
Examiners often ask you to explain a result in words.
Finally, remember that the predicted ratio applies to large numbers. A family of four offspring from Tt x Tt may well show no short plants, because each fertilisation is a chance event.
Use the same checking habit with pedigrees: any genotype you write for a person must be consistent with both their parents and their children.
Section 47 of 55Worked examples
Pea plants: T (tall) is dominant. Cross homozygous short with homozygous tall. What is the probability that offspring are tall? [3]3 marks
tt x TT gives only Tt. Every offspring is tall, so the probability is 100%.
Two Tt offspring are crossed. What is the probability that an offspring is short? [3]3 marks
TT, Tt, Tt, tt gives 3 tall : 1 short. Probability of short = 25%.
State why a tall pea plant cannot be assumed to be TT. [1]1 mark
Tt is also tall because the dominant phenotype shows in heterozygotes.
Section 48 of 55Codominance
Codominance occurs when both alleles in a heterozygous organism contribute to the phenotype. Inheritance of blood group is an example of codominance. There are three alleles of the gene that governs the inheritance of blood group: IA, IB and IO.
| Phenotype | Possible genotypes |
|---|---|
| A | IAIA, IAIO |
| B | IBIB, IBIO |
| AB | IAIB |
| O | IOIO |
Section 49 of 55Deducing parental genotypes
In the blood-group Punnett square, the parent with group A must have the genotype IAIO and the parent with group B must have the genotype IBIO.
Section 50 of 55Sex-linked characteristics: colour blindness
Colour blindness is an X-linked recessive condition. The results of a cross between a normal male (XNY) and a female carrier (XNXn) are as follows.
| Child | Genotype | Chance |
|---|---|---|
| Normal female | XNXN | 25% |
| Carrier female | XNXn | 25% |
| Normal male | XNY | 25% |
| Colour-blind male | XnY | 25% |
A son always gets his Y from the father and his X from the mother, which is why a son of a carrier mother has a 50% chance of being colour-blind, while no daughter of a normal father can be colour-blind.
Section 51 of 55Answering sex-linked questions
Write the sex chromosomes in the Punnett square instead of single letters, put the allele as a superscript on the X, and remember that Y carries no allele for the gene. A female needs two recessive alleles to be affected, but a male needs only one.
Section 52 of 55Comparing the two patterns of inheritance
Codominance and sex-linkage are different ideas that are easily confused, so compare them directly.
| Feature | Codominant blood group | X-linked colour blindness |
|---|---|---|
| Gene location | Autosome | X chromosome |
| Number of alleles | Three (IA, IB, IO) | Two (XN, Xn) |
| Heterozygote | Shows both alleles (AB) | Carrier female, usually unaffected |
| Males and females | Equally affected | Males more often affected |
In an autosomal codominant cross, the sex of the child does not matter. In an X-linked cross, the sex of the child is part of the answer, so the table must show both sexes and the question may ask for the chance of a particular sex with a particular phenotype.
As a final check, use these rules.
- which allows paternity or maternity claims to be tested: for example a group AB child cannot have a group O parent,
- because the child needs both an IA and an IB allele and a group O parent has only IO to give.
Section 53 of 55Worked examples
Explain why neither parent in a cross can be homozygous if a group A and group B couple have a group O child. [2]2 marks
The group O child is IOIO, so each parent passed on an IO. The parents are therefore IAIO and IBIO.
A colour-blind man marries a normal homozygous woman. What are the chances of colour-blind children? [3]3 marks
XnY x XNXN: sons XNY (normal), daughters XNXn (carriers). No child is colour-blind: 0%.
A carrier woman and normal man have a son. What is the chance he is colour-blind? [2]2 marks
The son's X comes from the mother: XN or Xn equally, so 50%.
Section 54 of 55Key terms
| Term | Meaning |
|---|---|
| Gene | A short length of DNA on a chromosome that codes for a characteristic. |
| Allele | A version of a gene. |
| Haploid | Having half the normal number of chromosomes. |
| Zygote | The fertilised egg formed when two gametes fuse. |
| Homozygous | Having two identical alleles of a gene. |
| Heterozygous | Having two different alleles of a gene. |
| Term | Meaning |
|---|---|
| Punnett square | A grid showing the possible gametes of two parents and the resulting offspring genotypes. |
| Pedigree | A family tree tracing a characteristic through generations. |
| Carrier | An unaffected individual who has one copy of a recessive allele. |
| Probability | The chance of an outcome, expressed as a fraction or percentage. |
| Codominance | Both alleles are expressed in the heterozygote. |
| Term | Meaning |
|---|---|
| Diploid | Having two copies of each chromosome (46 in humans). |
| Haploid | Having half the normal number of chromosomes (23 in humans). |
| Sex chromosomes | The X and Y chromosomes; XX is female and XY is male. |
| Gene expression | Whether a gene is transcribed and translated in a particular cell. |
| Gamete | A sex cell such as a sperm or egg. |
| Term | Meaning |
|---|---|
| Meiosis | Nuclear division producing four genetically different haploid cells. |
| Recombination | Exchange of DNA between paired chromosomes during the first division of meiosis. |
| Genotype | The alleles an individual has for a gene. |
| Phenotype | The observable characteristic. |
| Dominant allele | An allele whose phenotype appears even when only one copy is present. |
| Term | Meaning |
|---|---|
| Codominance | Both alleles are expressed in the heterozygote. |
| X-linked | A gene carried on the X chromosome. |
| Carrier | A heterozygote who has a recessive allele without showing the trait. |
| Pedigree | A family tree showing inheritance of a trait. |
| Colour blindness | An X-linked recessive condition affecting colour vision. |
| Term | Meaning |
|---|---|
| Transcription | Copying the base code of a gene onto mRNA. |
| Translation | Reading the mRNA code at a ribosome to assemble amino acids. |
| mRNA | Messenger RNA, which carries the gene's code to a ribosome. |
| tRNA | Transfer RNA, which carries one specific amino acid to the ribosome. |
| Ribosome | The site where proteins are made. |
| Term | Meaning |
|---|---|
| Homozygous | Having two identical alleles. |
| Heterozygous | Having two different alleles. |
| Dominant | An allele whose effect shows when one copy is present. |
| Recessive | An allele that shows only when two copies are present. |
| Inheritance | Transmission of genetic information from one generation to the next. |
| Term | Meaning |
|---|---|
| Codominance | Both alleles are expressed in a heterozygote. |
| X-linked | Located on the X chromosome. |
| Carrier | Heterozygous female for an X-linked recessive allele. |
| Blood group | A phenotype set by alleles I-A, I-B and I-O. |
Section 55 of 55Exam technique
Marked practiceQuizzes for this lesson
Last updated:
\n