6.2Thermochemistry
Energy cycles and spontaneity — EST 2 Chemistry Revision Notes & Topical Questions
5 min read 8 parts Lesson 2 of 2 1 quiz
Energy cycles and spontaneity EST Chemistry notes: Apply Hess's law.ΔH°f of an element in its standard state is zero.From bondsΔH = Σ(bonds broken) − Σ(bonds formed).Use kelvin in ΔG = ΔH − TΔS and match kJ with J.Spontaneous does not mean fast.The crossover temperature is T = ΔH…
- Standard conditions
- ΔH = +50 kJ, ΔS = +0.20 kJ/K. Above what T is it spontaneous?
- Energy cycles and spontaneity EST Chemistry: what to do next
- Standard enthalpy of formation (ΔH°f)
- Bond enthalpy
- Entropy (S)
Part 1 of 8Key ideas
Part 2 of 8Learning objectives
Part 3 of 8Essential knowledge
Part 4 of 8Process & sequence
Hess's law routewrite these steps in this order; each step is a marking point.
- Target equation
- Rearrange steps
- Adjust ΔH
- Add and cancel
- Total ΔH
Part 5 of 8Worked examples
- (−394 + 2(−286)) − (−75) = −891 kJ.
- T = 50 ÷ 0.20 = 250 K.
Part 6 of 8Summary
Part 7 of 8Keep going
Energy cycles and spontaneity EST Chemistry: what to do next
These Energy cycles and spontaneity EST Chemistry notes covered the key ideas, worked examples and exam technique for this topic. Check your Energy cycles and spontaneity EST Chemistry understanding with the practice questions below, then reread any Energy cycles and spontaneity EST Chemistry point you were unsure about before moving on.

Part 8 of 8Compare: Compare
| ΔH | ΔS | ΔG | Spontaneous? |
|---|---|---|---|
| − | + | Always − | At all T |
| + | − | Always + | Never |
| − | − | − at low T | Low temperatures |
| + | + | − at high T | High temperatures |
| Change | Example |
|---|---|
| Solid → liquid → gas | Ice melting |
| More gas moles formed | 2H2O2 → 2H2O + O2 |
| Solid dissolves | NaCl in water |
| Temperature rises | Faster particle motion |
Key terms
Command terms
Exam technique
Keywords the mark scheme looks for in this lesson
How to get full marks (examiner guidance)
Marked practiceQuizzes for this lesson
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